ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÊýÊ®ÄêÀ´£¬»¯Ñ§¹¤×÷Õ߶Ô̼µÄÑõ»¯ÎïºÍÇ⻯Îï×öÁ˹㷺ÉîÈëµÄÑо¿²¢È¡µÃÁËһЩÖØÒª³É¹û¡£ÒÑÖª£ºC(s)£«O2(g)£½CO2(g)£»¦¤H£½£393 kJ¡¤mol£1
2CO (g)£«O2(g)£½2CO2(g)£»¦¤H£½£566 kJ¡¤mol£1
2H2(g)£«O2(g)£½2H2O(g)£»¦¤H£½£484 kJ¡¤mol£1
£¨1£©¹¤ÒµÉϳ£²ÉÓý«Ë®ÕôÆøÅçµ½×ÆÈȵÄÌ¿²ãÉÏʵÏÖúµÄÆø»¯£¨ÖƵÃCO¡¢H2£©£¬¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇ_______________¡£
£¨2£©ÉÏÊöúÆø»¯¹ý³ÌÖÐÐèÏòÌ¿²ã½»ÌæÅçÈë¿ÕÆøºÍË®ÕôÆø£¬ÅçÈë¿ÕÆøµÄÄ¿µÄÊÇ__________£»¸ÃÆø»¯Æø¿ÉÔÚ¼ÓÈȺʹ߻¯¼ÁϺϳÉÒºÌåȼÁϼ״¼£¬¸Ã·´Ó¦·½³ÌʽΪ_______________¡£
£¨3£©µç×Ó¹¤ÒµÖÐʹÓõÄÒ»Ñõ»¯Ì¼³£ÒÔ¼×´¼ÎªÔÁÏͨ¹ýÍÑÇâ¡¢·Ö½âÁ½²½·´Ó¦µÃµ½¡£
µÚÒ»²½£º2CH3OH(g) === HCOOCH3(g)+2H2(g) ¡÷H>0
µÚ¶þ²½£ºHCOOCH3(g) === CH3OH(g) +CO(g) ¡÷H>0
ÔòÒÔ¼×´¼ÖÆÒ»Ñõ»¯Ì¼µÄ·´Ó¦Îª___________·´Ó¦£¨Ìî¡°ÎüÈÈ¡±¡¢¡°·ÅÈÈ¡±£©¡£
£¨4£©¿Æѧ¼ÒÓõª»¯ïزÄÁÏÓëÍ×é×°ÈçͼµÄÈ˹¤¹âºÏϵͳ£¬ÀûÓøÃ×°Öóɹ¦µØʵÏÖÁËÒÔ
CO2ºÍH2OºÏ³ÉCH4¡£
¢Ùд³ö͵缫±íÃæµÄµç¼«·´Ó¦Ê½____________¡£
¢ÚΪÌá¸ß¸ÃÈ˹¤¹âºÏϵͳµÄ¹¤×÷ЧÂÊ£¬¿ÉÏò×°ÖÃÖмÓÈëÉÙÁ¿___________£¨Ñ¡Ìî¡°ÇâÑõ»¯ÄÆ¡±»ò¡°ÁòËᡱ£©¡£
£¨5£©ÌìÈ»ÆøÒ²¿ÉÖØÕûÉú²ú»¯¹¤ÔÁÏ£¬×î½ü¿Æѧ¼ÒÃÇÀûÓÃÌìÈ»ÆøÎÞÑõ´ß»¯ÖØÕû»ñµÃ·¼ÏãÌþX¡£ÓÉÖÊÆ×·ÖÎöµÃXµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª106£¬ÆäºË´Å¹²ÕñÇâÆ×Èçͼ£¬ÔòXµÄ½á¹¹¼òʽΪ_____________¡£
¡¾´ð°¸¡¿C(s)£«H2O(g)= CO (g)£«H2(g)£»¦¤H£½+132 kJ¡¤mol£1 Èò¿·Ö̿ȼÉÕ£¬Ìṩ̿ÓëË®ÕôÆø·´Ó¦ËùÐèÒªµÄÈÈÁ¿ CO + 2H2CH3OH ÎüÈÈ CO2£«8e££«8H£«£½CH4£«2H2O ÁòËá
¡¾½âÎö¡¿
£¨1£©ÒÑÖª£º¢ÙC(s)£«O2(g)£½CO2(g)£»¦¤H£½£393 kJ¡¤mol£1£»¢Ú2CO (g)£«O2(g)£½2CO2(g)£»¦¤H£½£566 kJ¡¤mol£1£»¢Û2H2(g)£«O2(g)£½2H2O(g)£»¦¤H£½£484 kJ¡¤mol£1¡£¸ù¾Ý¸Ç˹¶¨ÂÉ£º¢Ù-1/2¡Á¢Ú-1/2¡Á¢ÛµÃË®ÕôÆøÓëÌ¿·´Ó¦Éú³ÉCO¡¢H2µÄÈÈ»¯Ñ§·½³ÌʽÊÇC(s)£«H2O(g)="=CO" (g)£«H2(g)£»¦¤H£½+132 kJ¡¤mol£1¡£
£¨2£©ÃºÆø»¯ÎªÎüÈÈ·´Ó¦£¬¹Ê·´Ó¦¹ý³ÌÖÐÐèÏòÌ¿²ã½»ÌæÅçÈë¿ÕÆøºÍË®ÕôÆø£¬ÅçÈë¿ÕÆøµÄÄ¿µÄÊÇÈò¿·Ö̿ȼÉÕ£¬Ìṩ̿ÓëË®ÕôÆø·´Ó¦ËùÐèÒªµÄÈÈÁ¿£»COºÍH2ÔÚ¼ÓÈȺʹ߻¯¼ÁÏÂÉú³ÉÒºÌåȼÁϼ״¼£¬¸Ã·´Ó¦·½³ÌʽΪCO + 2H2CH3OH¡£
£¨3£©ÒÑÖª£º¢Ù2CH3OH(g) ==HCOOCH3(g)+2H2(g) ¡÷H>0£¬¢ÚHCOOCH3(g) ==CH3OH(g) +CO(g) ¡÷H>0£¬¸ù¾Ý¸Ç˹¶¨ÂÉ£º¢Ù+¢ÚµÃCH3OH(g) ="=" CO(g)+2H2(g)µÄ¡÷H>0£¬ÔòÒÔ¼×´¼ÖÆÒ»Ñõ»¯Ì¼µÄ·´Ó¦ÎªÎüÈÈ·´Ó¦¡£
£¨4£©·ÖÎöÌâ¸ø×°ÖÃÖª¸Ã×°ÖÃΪԵç³Ø£¬µç³Ø·´Ó¦ÎªCO2+2H2O==CH4+2O2£¬µç×ÓÓÉGaNµç¼«ÑØÍâµç·Á÷Ïò͵缫£¬ÔòGaNΪԵç³ØµÄ¸º¼«£¬Íµç¼«ÎªÔµç³ØµÄÕý¼«£¬Àë×Ó½»»»Ä¤ÎªÖÊ×Ó½»»»Ä¤£¬Ôòµç½âÖÊÈÜҺΪËáÐÔÈÜÒº¡£¢Ù͵缫ΪԵç³ØµÄÕý¼«£¬·¢Éú»¹Ô·´Ó¦£¬CO2µÃµç×ÓÉú³É¼×Í飬µç½âÖÊΪËáÐÔÈÜÒº£¬Í¨¹ýÇâÀë×ÓºÍˮƽºâµçºÉºÍÔ×Ó£¬µç¼«·´Ó¦Ê½ÎªCO2£«8e££«8H£«£½CH4£«2H2O¡£¢Úµç½âÖÊΪËáÐÔÈÜÒº£¬ÎªÌá¸ß¸ÃÈ˹¤¹âºÏϵͳµÄ¹¤×÷ЧÂÊ£¬¿ÉÏò×°ÖÃÖмÓÈëÉÙÁ¿ÁòËá¡£
£¨5£©·¼ÏãÌþXµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª106£¬ÀûÓÃÉÌÓà·¨ÍƶÏXµÄ·Ö×ÓʽΪC8H10£¬ÆäºË´Å¹²ÕñÇâÆ×ÓÐ2¸ö·å£¬X·Ö×ÓÖк¬ÓÐ2ÖÖÇâÔ×Ó£¬ÔòXµÄ½á¹¹¼òʽΪ