ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÒÑÖª»¯Ñ§·´Ó¦ÖеÄÄÜÁ¿±ä»¯,ÊÇÓÉ»¯Ñ§·´Ó¦Öоɻ¯Ñ§¼ü¶ÏÁÑʱÎüÊÕµÄÄÜÁ¿Óëл¯Ñ§¼üÐγÉʱ·Å³öµÄÄÜÁ¿²»Í¬ËùÖ¡£ÏÂͼΪN2(g)ºÍO2(g)Éú³ÉNO(g)¹ý³ÌÖеÄÄÜÁ¿±ä»¯£º
£¨1£©ÈËÃÇͨ³£°Ñ²ð¿ª1 molij»¯Ñ§¼üËùÎüÊÕµÄÄÜÁ¿¿´³É¸Ã»¯Ñ§¼üµÄ¼üÄÜ¡£¼üÄܵĴóС¿ÉÒÔºâÁ¿»¯Ñ§¼üµÄÇ¿Èõ£¬ÔòN¡ÔN¼üµÄ¼üÄÜΪ_________________kJ¡¤mol-1¡£¸ù¾ÝÉÏͼд³öN2(g)ºÍO2(g)Éú³ÉNO(g)µÄÈÈ»¯Ñ§·½³Ìʽ£º________________________________¡£
£¨2£©NO(g)·Ö½âÉú³ÉN2(g)ºÍO2(g)µÄÈÈ»¯Ñ§·½³ÌʽΪ£º_____________________¡£µ±ÓÐ16 g O2(g)Éú³Éʱ,¸Ã·´Ó¦ÖзųöµÄÈÈÁ¿Îª£º_________________kJ¡£
¡¾´ð°¸¡¿946N2(g)+O2(g)2NO(g)¡¡¦¤H=180 kJ¡¤mol-12NO(g)N2(g)+O2(g)¡¡¦¤H=¡ª180 kJ¡¤mol-190
¡¾½âÎö¡¿
£¨1£©¸ù¾ÝʾÒâͼ¿ÉÖª£¬N¡ÔN¼üµÄ¼üÄÜΪ946kJ/mol¡£·´Ó¦ÈȾÍÊǶϼüÎüÊÕµÄÄÜÁ¿ºÍÐγɻ¯Ñ§¼üËù·Å³öµÄÄÜÁ¿µÄ²îÖµ£¬Òò´Ë¸ù¾Ý¼üÄÜ¿ÉÖª£¬¸Ã·´Ó¦µÄ·´Ó¦ÈÈ¡÷H£½946kJ/mol£«498kJ/mol£2¡Á632kJ/mol£½£«180kJ/mol£¬ËùÒԸ÷´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÊÇN2(g)+O2(g)£½2NO(g)¡¡¦¤H=£«180 kJ¡¤mol-1¡£¹Ê´ð°¸Îª£º946£»N2(g)+O2(g)2NO(g)¡¡¦¤H=+180 kJ¡¤mol-1£»
£¨2£©Õý·´Ó¦ÊÇÎüÈÈ·´Ó¦£¬ÔòÄæ·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬ËùÒÔNO(g)·Ö½âÉú³ÉN2(g)ºÍO2(g)µÄÈÈ»¯Ñ§·½³ÌʽΪ2NO(g)£½N2(g)+O2(g)¡¡¦¤H=£180 kJ¡¤mol-1¡£16gÑõÆøÊÇ0.5mol£¬ËùÒԷųöµÄÈÈÁ¿ÊÇ180 kJ¡¤mol-1¡Á0.5mol£½90kJ¡£¹Ê´ð°¸Îª£º2NO(g)N2(g)+O2(g)¡¡¦¤H=¡ª180 kJ¡¤mol-1£» 90¡£