ÌâÄ¿ÄÚÈÝ

5£®ÐÂÐ͸ßЧµÄ¼×´¼È¼Áϵç³Ø²ÉÓò¬Îªµç¼«²ÄÁÏ£¬Á½µç¼«ÉÏ·Ö±ðͨÈëCH3OHºÍO2£®Ä³Ñо¿Ð¡×齫Á½¸ö¼×´¼È¼Áϵç³Ø´®Áªºó×÷ΪµçÔ´£¬½øÐб¥ºÍÂÈ»¯ÄÆÈÜÒºµç½âʵÑ飬ÈçͼËùʾ£®»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÒÒȼÁϵç³ØµÄ¸º¼«·´Ó¦Ê½Îª2CH3OH-12e-+16OH-=2CO32-+12H2O£®
£¨2£©ÈôÔ­NaClÈÜҺΪ300ml£¬¼ÙÉèµç½â¹ý³ÌÖÐÌå»ý²»±ä£¬µ±Ã¿¸öȼÁϵç³ØÖÐͨÈë0.16g¼×´¼ÍêÈ«·´Ó¦Ê±£¬¸ÃÈÜÒºµÄPHΪ13£®

·ÖÎö £¨1£©CH3OH¼îÐÔȼÁϵç³ØÖУ¬¸º¼«CH3OHʧµç×Ó±»Ñõ»¯£»
£¨2£©¸ù¾Ý¹Øϵʽ1molCH3OH¡«6mol e-¡«3mol Cl2¡«6molOH-¼ÆË㣮

½â´ð ½â£º£¨1£©ÔÚ¼îÐÔÈÜÒºÖУ¬CH3OH¼îÐÔȼÁϵç³ØÖУ¬¸º¼«CH3OHʧµç×Ó±»Ñõ»¯£¬·´Ó¦Ê½Îª£º2CH3OH-12e-+16OH-=2CO32-+12H2O£¬
¹Ê´ð°¸Îª£º2CH3OH-12e-+16OH-=2CO32-+12H2O£»
£¨2£©¸ù¾Ý2CH3OH-12e-+16OH-=2CO32-+12H2OµÃ£¬¹Øϵʽ1molCH3OH¡«6mol e-¡«3mol Cl2¡«6molOH-
                                                1 mol                        6mol
                                               $\frac{0.16}{32}$=0.005mol            n£¨OH-£©
ËùÒÔn£¨OH-£©=0.03mol
ËùÒÔc£¨OH-£©=$\frac{0.03}{0.3}$=0.1mol/L£¬ËùÒÔc£¨H+£©=$\frac{1¡Á10{\;}^{-14}}{0.1}$=10-13£¬
ËùÒÔ£¬pH=13£¬¹Ê´ð°¸Îª£º13£®

µãÆÀ ±¾Ì⺭¸Çµç½â³ØºÍÔ­µç³ØµÄÖ÷ÌåÄÚÈÝ£¬Éæ¼°µç¼«ÅжÏÓëµç¼«·´Ó¦Ê½ÊéдµÈÎÊÌ⣬×öÌâʱעÒâ´ÓÑõ»¯»¹Ô­µÄ½Ç¶ÈÅжÏÔ­µç³ØµÄÕý¸º¼«ÒÔ¼°µç¼«·½³ÌʽµÄÊéд£¬±¾ÌâÖÐÄѵãºÍÒ×´íµãΪµç¼«·½³ÌʽµÄÊéд£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
4£®ÒÑÖª£º
Ò©Æ·Ãû³ÆÈÛµã/¡æ·Ðµã£¨¡æ£©ÃܶÈg/cm3ÈܽâÐÔ
¶¡´¼-89.5117.70.8098΢ÈÜÓÚË®¡¢ÈÜÓÚŨÁòËá
1-ä嶡Íé-112.4101.61.2760²»ÈÜÓÚË®ºÍŨÁòËá
¸ù¾ÝÌâÒâÍê³ÉÌî¿Õ£º
£¨Ò»£©ÖƱ¸1-ä嶡Íé´Ö²úÆ·£ºÔÚͼ1×°ÖõÄÔ²µ×ÉÕÆ¿ÖÐÒÀ´Î¼ÓÈëNaBr£¬10mLÕý¶¡´¼£¬2Á£·Ðʯ£¬·ÖÅú¼ÓÈë1£º1µÄÁòËáÈÜÒº£¬Ò¡ÔÈ£¬¼ÓÈÈ30min£®»¯Ñ§·½³Ìʽ£ºNaBr+H2SO4+CH3CH2CH2CH2OH¡úCH3CH2CH2CH2Br+NaHSO4+H2O
£¨1£©·´Ó¦×°ÖÃÖмÓÈë·ÐʯµÄÄ¿µÄÊÇ·ÀÖ¹ÒºÌ屩·Ð£®ÅäÖÆÌå»ý±ÈΪ1£º1µÄÁòËáËùÓõĶ¨Á¿ÒÇÆ÷Ϊb£¨Ñ¡Ìî±àºÅ£©
a£®Ììƽ   b£®Á¿Í²   c£®ÈÝÁ¿Æ¿   d£®µÎ¶¨¹Ü
£¨2£©ÀäÄý¹ÜµÄ½øË®·½ÏòΪϽøÉϳö£¬ÕâÑùÑ¡ÔñµÄÔ­ÒòÊÇÄܸü³ä·ÖÀäÄý£®
£¨3£©Í¼2×°ÖÃÖУ¬ÄÜ´úÌæÉÏͼÖÐ×îºóÊÕ¼¯×°ÖõÄÊÇABD£¨ÌîÐòºÅ£©£®

£¨4£©ÈôÓÃŨÁòËá½øÐÐʵÑ飬Óлú²ãÖлá³ÊÏÖ×Ø»ÆÉ«£¬³ýÈ¥ÆäÖÐÔÓÖʵÄÕýÈ··½·¨ÊÇd£¨Ñ¡Ìî±àºÅ£©£®
a£®ÕôÁó  b£®ÇâÑõ»¯ÄÆÈÜҺϴµÓ  c£®ÓÃËÄÂÈ»¯Ì¼ÝÍÈ¡  d£®ÓÃÑÇÁòËáÄÆÈÜҺϴµÓ
£¨¶þ£©ÖƱ¸¾«Æ·£º½«µÃµ½µÄ´Ö1-ä嶡ÍéÒÀ´ÎÓÃŨÁòËᡢˮ¡¢10% Ì¼ËáÄÆ¡¢Ë®Ï´µÓºó¼ÓÈëÎÞË®ÂÈ»¯¸Æ½øÐиÉÔȻºóÔÙ½«1-ä嶡Í鰴ͼ3×°ÖÃÕôÁ󣮣¨5£©ÊÕ¼¯²úƷʱ£¬¿ØÖƵÄζÈÓ¦ÔÚ101.6¡æ×óÓÒ£»
£¨6£©ÊµÑéÖƵõÄ1-ä嶡ÍéµÄÖÊÁ¿Îª10.895g£¬ÔòÕý¶¡´¼µÄ²úÂÊΪ72.7%£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø