ÌâÄ¿ÄÚÈÝ
¹ýÁòËá¼Ø£¨£©¾ßÓÐÇ¿Ñõ»¯ÐÔ£¨³£±»»¹ÔΪÁòËá¼Ø£©£¬80 ¡æÒÔÉÏÒ×·¢Éú·Ö½â¡£ÊµÑéÊÒÄ£Ä⹤ҵºÏ³É¹ýÁòËá¼ØµÄÁ÷³ÌÈçÏ£º
£¨1£©ÁòËá狀ÍÁòËáÅäÖƳɵç½âÒº£¬ÒÔ²¬×÷µç¼«½øÐеç½â£¬Éú³É¹ýÁòËáï§ÈÜÒº¡£Ð´³öµç½âʱ·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ_____________________________________
___________________________________¡£
£¨2£©ÒÑÖªÏà¹ØÎïÖʵÄÈܽâ¶ÈÇúÏßÈçÓÒͼËùʾ¡£ÔÚʵÑéÊÒÖÐÌá´¿¹ýÁòËá¼Ø´Ö²úÆ·µÄʵÑé¾ßÌå²Ù×÷ÒÀ´ÎΪ£º½«¹ýÁòËá¼Ø´Ö²úÆ·ÈÜÓÚÊÊÁ¿Ë®ÖУ¬________________£¬¸ÉÔï¡£
£¨3£©ÑùÆ·ÖйýÁòËá¼ØµÄº¬Á¿¿ÉÓõâÁ¿·¨½øÐвⶨ¡£ÊµÑé²½ÖèÈçÏ£º
²½Öè1£º³ÆÈ¡¹ýÁòËá¼ØÑùÆ·0.300 0 gÓÚµâÁ¿Æ¿ÖУ¬¼ÓÈë30 mLË®Èܽ⡣
²½Öè2£ºÏòÈÜÒºÖмÓÈë4.00 0 g KI¹ÌÌ壨ÂÔ¹ýÁ¿£©£¬Ò¡ÔÈ£¬ÔÚ°µ´¦·ÅÖÃ30 min¡£
²½Öè3£ºÔÚµâÁ¿Æ¿ÖмÓÈëÊÊÁ¿´×ËáÈÜÒºËữ£¬ÒÔµí·ÛÈÜÒº×÷ָʾ¼Á£¬ÓÃ0.100 0 mol¡¤L£1Na2S2O3±ê×¼ÈÜÒºµÎ¶¨ÖÁÖյ㣬¹²ÏûºÄNa2S2O3±ê×¼ÈÜÒº21.00 mL¡£
£¨ÒÑÖª·´Ó¦£ºI2£«2S2O32-=2I££«S4O62-£©
¢ÙÈô²½Öè2ÖÐ佫µâÁ¿Æ¿¡°ÔÚ°µ´¦·ÅÖÃ30 min¡±£¬Á¢¼´½øÐв½Öè3£¬Ôò²â¶¨µÄ½á¹û¿ÉÄÜ________£¨Ñ¡Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±¡¢¡°ÎÞÓ°Ï족£©£»ÉÏÊö²½Öè3Öеζ¨ÖÕµãµÄÏÖÏóÊÇ____________________________________________¡£
¢Ú¸ù¾ÝÉÏÊö²½Öè¿É¼ÆËã³ö¸ÃÑùÆ·ÖйýÁòËá¼ØµÄÖÊÁ¿·ÖÊýΪ_______________¡£
¢ÛΪȷ±£ÊµÑé½á¹ûµÄ׼ȷÐÔ£¬ÄãÈÏΪ»¹ÐèÒª____________________________¡£
£¨4£©½«0.40 mol¹ýÁòËá¼ØÓë0.20 molÁòËáÅäÖƳÉ1 LÈÜÒº£¬ÔÚ80 ¡æÌõ¼þϼÓÈȲ¢ÔÚtʱ¿ÌÏòÈÜÒºÖеμÓÈëÉÙÁ¿FeCl3ÈÜÒº£¬²â¶¨ÈÜÒºÖи÷³É·ÖµÄŨ¶ÈÈçͼËùʾ£¨H£«Å¨¶Èδ»³ö£©¡£Í¼ÖÐÎïÖÊXµÄ»¯Ñ§Ê½Îª________________________¡£
£¨1£©ÁòËá狀ÍÁòËáÅäÖƳɵç½âÒº£¬ÒÔ²¬×÷µç¼«½øÐеç½â£¬Éú³É¹ýÁòËáï§ÈÜÒº¡£Ð´³öµç½âʱ·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ_____________________________________
___________________________________¡£
£¨2£©ÒÑÖªÏà¹ØÎïÖʵÄÈܽâ¶ÈÇúÏßÈçÓÒͼËùʾ¡£ÔÚʵÑéÊÒÖÐÌá´¿¹ýÁòËá¼Ø´Ö²úÆ·µÄʵÑé¾ßÌå²Ù×÷ÒÀ´ÎΪ£º½«¹ýÁòËá¼Ø´Ö²úÆ·ÈÜÓÚÊÊÁ¿Ë®ÖУ¬________________£¬¸ÉÔï¡£
£¨3£©ÑùÆ·ÖйýÁòËá¼ØµÄº¬Á¿¿ÉÓõâÁ¿·¨½øÐвⶨ¡£ÊµÑé²½ÖèÈçÏ£º
²½Öè1£º³ÆÈ¡¹ýÁòËá¼ØÑùÆ·0.300 0 gÓÚµâÁ¿Æ¿ÖУ¬¼ÓÈë30 mLË®Èܽ⡣
²½Öè2£ºÏòÈÜÒºÖмÓÈë4.00 0 g KI¹ÌÌ壨ÂÔ¹ýÁ¿£©£¬Ò¡ÔÈ£¬ÔÚ°µ´¦·ÅÖÃ30 min¡£
²½Öè3£ºÔÚµâÁ¿Æ¿ÖмÓÈëÊÊÁ¿´×ËáÈÜÒºËữ£¬ÒÔµí·ÛÈÜÒº×÷ָʾ¼Á£¬ÓÃ0.100 0 mol¡¤L£1Na2S2O3±ê×¼ÈÜÒºµÎ¶¨ÖÁÖյ㣬¹²ÏûºÄNa2S2O3±ê×¼ÈÜÒº21.00 mL¡£
£¨ÒÑÖª·´Ó¦£ºI2£«2S2O32-=2I££«S4O62-£©
¢ÙÈô²½Öè2ÖÐ佫µâÁ¿Æ¿¡°ÔÚ°µ´¦·ÅÖÃ30 min¡±£¬Á¢¼´½øÐв½Öè3£¬Ôò²â¶¨µÄ½á¹û¿ÉÄÜ________£¨Ñ¡Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±¡¢¡°ÎÞÓ°Ï족£©£»ÉÏÊö²½Öè3Öеζ¨ÖÕµãµÄÏÖÏóÊÇ____________________________________________¡£
¢Ú¸ù¾ÝÉÏÊö²½Öè¿É¼ÆËã³ö¸ÃÑùÆ·ÖйýÁòËá¼ØµÄÖÊÁ¿·ÖÊýΪ_______________¡£
¢ÛΪȷ±£ÊµÑé½á¹ûµÄ׼ȷÐÔ£¬ÄãÈÏΪ»¹ÐèÒª____________________________¡£
£¨4£©½«0.40 mol¹ýÁòËá¼ØÓë0.20 molÁòËáÅäÖƳÉ1 LÈÜÒº£¬ÔÚ80 ¡æÌõ¼þϼÓÈȲ¢ÔÚtʱ¿ÌÏòÈÜÒºÖеμÓÈëÉÙÁ¿FeCl3ÈÜÒº£¬²â¶¨ÈÜÒºÖи÷³É·ÖµÄŨ¶ÈÈçͼËùʾ£¨H£«Å¨¶Èδ»³ö£©¡£Í¼ÖÐÎïÖÊXµÄ»¯Ñ§Ê½Îª________________________¡£
£¨1£©2SO42-£«2H£«S2O82-£«H2¡ü
£¨2£©ÔÚ²»³¬¹ý80 ¡æµÄÌõ¼þϼÓÈÈŨËõ£¬ÀäÈ´½á¾§£¬¹ýÂË£¬ÓÃÀäˮϴµÓ¡¡£¨3£©¢ÙƫС¡¡×îºóÒ»µÎµÎÈëºóÈÜÒºÓÉÀ¶É«±äΪÎÞÉ«£¬ÇÒ30 s²»±äÉ«¡¡¢Ú94.50%£¨»ò0.945 0£©
¢ÛÖظ´ÉÏÊöʵÑé²½Öè1¡«2´Î¡¡£¨4£©H2O2
£¨2£©ÔÚ²»³¬¹ý80 ¡æµÄÌõ¼þϼÓÈÈŨËõ£¬ÀäÈ´½á¾§£¬¹ýÂË£¬ÓÃÀäˮϴµÓ¡¡£¨3£©¢ÙƫС¡¡×îºóÒ»µÎµÎÈëºóÈÜÒºÓÉÀ¶É«±äΪÎÞÉ«£¬ÇÒ30 s²»±äÉ«¡¡¢Ú94.50%£¨»ò0.945 0£©
¢ÛÖظ´ÉÏÊöʵÑé²½Öè1¡«2´Î¡¡£¨4£©H2O2
£¨1£©ÓÉÌâÒâÖª£¬ÁòËáï§×ª»¯Îª¹ýÁòËáï§ÎªÑõ»¯·´Ó¦£¬ÔòÓ¦·¢ÉúH£«µÄ»¹Ô·´Ó¦£»£¨2£©¸ù¾Ý¸÷ÎïÖʵÄÈܽâ¶È±ä»¯ºÍ¹ýÁòËá¼ØµÄÐÔÖÊ£¬Ó¦ÔËÓÃÖؽᾧ·¨½øÐÐÌá´¿·ÖÀë¡££¨3£©¢ÙÈôÔÚ²½Öè2ÖÐ佫µâÁ¿Æ¿·ÅÖÃ30 minÁ¢¼´½øÐв½Öè3£¬Ôò¿ÉÄÜÔì³É¹ýÁòËá¼ØδÄÜÍêȫת»¯£¬×îÖÕµ¼Ö²ⶨ½á¹ûƫС£»µÎ¶¨Öյ㼴ÊǵⵥÖʸպÃÏûºÄÍê±Ï£¬×îºóÒ»µÎµÎÈëºóÈÜÒºÓÉÀ¶É«±äΪÎÞÉ«£¬ÇÒ30 s²»±äÉ«¡£¢Ú¸ù¾Ýµç×ÓתÒƹØϵÓÐS2O82-¡«I2¡«2S2O32-£¬¹Ên£¨K2S2O8£©£½0.1000 mol¡¤L£1¡Á0.021 L¡Á£½0.001 05 mol£¬m£¨K2S2O8£©£½0.001 05 mol¡Á270 g¡¤mol£1£½0.283 5 g£¬w£¨K2S2O8£©£½¡Á100%£½94.50%¡£¢Û¶¨Á¿ÊµÑé¾ùÓ¦Öظ´½øÐÐ2¡«3´Î£¬¹ÊÓ¦¸Ã¡°Öظ´ÉÏÊöʵÑé²½Öè1¡«2´Î¡±¡££¨4£©ÓɹýÁòËá¼ØµÄ½á¹¹¼°Í¼ÖÐÁ£×ÓµÄÁ¿±ä»¯Öª£¬0.4 mol¹ýÁòËá¼Ø¿ÉÉú³É0.4 mol H2O2£¬È»ºóÔÙ·Ö½â¿ÉµÃ0.2 mol O2£¬ÓëͼÎǺϡ£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿