ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿½«Ê¢ÓеªÆøºÍ¶þÑõ»¯µª»ìºÏÆøÌåµÄÊÔ¹Ü(ÊÔ¹ÜÈÝ»ýΪVL)µ¹Á¢ÓÚË®ÖУ¬¾­¹ý×ã¹»³¤µÄʱ¼äºó£¬ÊÔ¹ÜÄÚÆøÌåµÄÌå»ý±äΪaL¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)¸Ã»ìºÏÆøÌåµ¹Á¢ÓÚË®Öз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ______________________¡£

(2)Èôa£½V£¬ÔòÔ­»ìºÏÆøÌåÖеªÆøÓë¶þÑõ»¯µªµÄÌå»ýÖ®±ÈÊÇ__________¡£

(3)½áºÏµÚ(2)СÌ⣬ÏòaLÆøÌåÖÐͨÈëÑõÆøÖÁÊÔ¹ÜÖиպÃÖ»ÓÐÒ»ÖÖÆøÌåʱ£¬Í£Ö¹Í¨ÈëÑõÆø¡£

¢ÙÊÔ¹ÜÖÐ×îÖÕÊ£ÓàµÄÆøÌåÊÇ____________£¬ÆäÌå»ýÊÇ____________¡£

¢Ú¸Ã¹ý³ÌÖÐ×Ü·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ__________________¡£

¡¾´ð°¸¡¿3NO2£«H2O=2HNO3£«NO1¡Ã3N NO£«3O2£«2H2O=4HNO3

¡¾½âÎö¡¿

(1)»ìºÏÆøÌåÖжþÑõ»¯µªºÍË®·´Ó¦Éú³ÉÏõËáºÍÒ»Ñõ»¯µª£¬·½³ÌʽΪ£º3NO2£«H2O=2HNO3£«NO£»£¨2£©¸ù¾Ý·´Ó¦Ç°ºóÆøÌåÌå»ý²îÁ¿¼ÆËã¡£»ìºÏÆøÌåµ¹Á¢ÓÚË®ÖкóÌå»ý¼õÉÙVL£¬ÓÉ¿ÉÖª¶þÑõ»¯µªµÄÌå»ýΪ¡ÁVL£½VL£¬µªÆøµÄÌå»ýΪVL£­VL£½VL£¬Ô­»ìºÏÆøÌ嵪ÆøÓë¶þÑõ»¯µªÌå»ý±ÈΪ1¡Ã3¡££¨3£©aLÔ­»ìºÏÆøÌåÈÜÓÚˮʱͨÈëÑõÆøʱ£¬4NO£«3O2£«2H2O===4HNO3£¬×îºóÊ£ÓàÒ»ÖÖÆøÌåΪµªÆø£¬ÆäÌå»ýΪV¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿SO2µÄ·ÀÖÎÓëÀûÓöÔÓÚ»·¾³±£»¤ÒâÒåÖØ´ó¡£Ä³Ð¡×éÔÚʵÑéÊÒÖжÔSO2µÄÐÔÖʼ°»ØÊÕÀûÓõÈÏà¹ØÎÊÌâ½øÐÐ̽¾¿¡£

£¨1£©ÓÃÏÂͼװÖÃÖƱ¸´¿¾»µÄSO2£¬·¢Éú×°ÖÃÖз´Ó¦µÄ»¯Ñ§·½³ÌʽΪ________£¬×°ÖõÄÁ¬½Ó˳ÐòΪ£ºa¡ú________£¨°´ÆøÁ÷·½Ïò£¬ÓÃСд×Öĸ±íʾ£©

£¨2£©ÓÃÈçͼװÖÃ̽¾¿SO2µÄÐÔÖÊ¡£ÏÞÑ¡ÊÔ¼Á£ºNaOHÈÜÒº¡¢Ï¡H2SO4¡¢H2O2ÈÜÒº¡¢FeCl3ÈÜÒº¡¢ µí·Û-KIÈÜÒº¡¢ÐÂÖÆH2SÈÜÒº¡£

²Ù×÷²½Öè

ʵÑéÏÖÏó

½âÊÍÔ­Òò

ÓÃ×¢ÉäÆ÷½«ÐÂÖÆH2SÈÜҺעÈë³äÂúSO2µÄÉÕÆ¿

²úÉúÈé°×É«»ë×Ç

+4¼ÛSÓÐ_______ÐÔ

ÓÃ×¢ÉäÆ÷½«_______ÈÜҺעÈë³äÂúSO2µÄÉÕÆ¿

_______

+4¼ÛSÓл¹Ô­ÐÔ£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ_______

£¨3£©¹¤ÒµÉÏ»ØÊÕÀûÓÃSO2µÄÒ»ÖÖ;¾¶ÊÇ£º

¸ÃС×éÔÚʵÑéÊÒ̽¾¿²½Öè¢òʱ£¬Ò»¶¨Ìõ¼þÏÂÏò100mL c0mol¡¤L£­1µÄ(NH4)2SO3ÈÜҺͨÈë¿ÕÆøºó£¬Óû²â¶¨ÈÜÒºÖÐ(NH4)2SO3µÄÑõ»¯ÂÊ(¦Á)¡£

¢ÙΪ¸ÃС×éÉè¼ÆʵÑé·½°¸£¨²»±ØÃèÊö²Ù×÷¹ý³ÌµÄϸ½Ú£¬ÎïÀíÁ¿µÄÊýÖµÓÃ×Öĸ±íʾ£©£º______________________________________________________________________________

¢Ú¦Á =________¡Á100%£¨ÓÃʵÑé·½°¸ÖеÄÎïÀíÁ¿±íʾ£©¡£

¡¾ÌâÄ¿¡¿Ìú¼°Æ仯ºÏÎïÔÚÉú²úºÍÉú»îÖÐÓÐ׏㷺µÄÓ¦Óá£

I.Ñõ»¯ÌúÊÇÖØÒª¹¤ÒµÑÕÁÏ£¬Ó÷ÏÌúмÖƱ¸ËüµÄÁ÷³ÌÈçÏ£º

»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©²Ù×÷A¡¢BµÄÃû³Æ·Ö±ðÊÇ______¡¢_____£»¼ÓÈëÉÔ¹ýÁ¿µÄNH4HCO3ÈÜÒºµÄ×÷ÓÃÊÇ_______¡£

£¨2£©Ð´³öÔÚ¿ÕÆøÖгä·Ö¼ÓÈÈìÑÉÕFeCO3µÄ»¯Ñ§·½³Ìʽ£º__________¡£

II.ÉÏÊöÁ÷³ÌÖУ¬ÈôìÑÉÕ²»³ä·Ö£¬×îÖÕ²úÆ·ÖлẬÓÐÉÙÁ¿µÄFeOÔÓÖÊ¡£Ä³Í¬Ñ§Îª²â¶¨²úÆ·ÖÐFe2O3µÄº¬Á¿£¬½øÐÐÈçÏÂʵÑ飺

a.³ÆÈ¡ÑùÆ·8.00g£¬¼ÓÈë×ãÁ¿Ï¡H2SO4Èܽ⣬²¢¼Óˮϡ±­ÖÁ100mL£»

b.Á¿È¡25.00mL´ý²âÈÜÒºÓÚ׶ÐÎÆ¿ÖУ»

c.ÓÃËữµÄ0.01000mol¡¤L-1KMnO4±ê×¼ÒºµÎ¶¨ÖÁÖյ㣻

d.Öظ´²Ù×÷b¡¢c2¡«3´Î£¬µÃ³öÏûºÄKMnO4ÈÜÒºÌå»ýµÄƽ¾ùֵΪ20.00mL.

£¨3£©Ð´³öµÎ¶¨¹ý³ÌÖз¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º_________¡£

£¨4£©È·¶¨µÎ¶¨´ïµ½ÖÕµãµÄ²Ù×÷¼°ÏÖÏóΪ_________¡£

£¨5£©ÉÏÊöÑùÆ·µÄÖÊÁ¿·ÖÊýΪ_________¡£

£¨6£©ÏÂÁвÙ×÷»áµ¼ÖÂÑùÆ·ÖÐFe2O3µÄÖÊÁ¿·ÖÊýµÄ²â¶¨½á¹ûÆ«µÍµÄÓÐ______¡£

a.δ¸ÉÔè׶ÐÎÆ¿ b.Ê¢×°±ê×¼ÒºµÄµÎ¶¨¹ÜûÓÐÓñê×¼ÒºÈóÏ´

c.µÎ¶¨½áÊøʱÑöÊӿ̶ÈÏ߶ÁÊý d.Á¿È¡´ý²âÒºµÄµÎ¶¨¹ÜûÓÐÈóÏ´

¡¾ÌâÄ¿¡¿¢ñ.ÏÂÁÐÊÇijÑо¿ÐÔѧϰС×é¶ÔijÎÞÉ«Ë®Ñù³É·ÖµÄ¼ì²â¹ý³Ì£¬ÒÑÖª¸ÃË®ÑùÖÐÖ»¿ÉÄܺ¬ÓÐK+ ¡¢Mg2+¡¢Fe3+¡¢Cu2+¡¢Al3+¡¢Ag+¡¢Ca2+¡¢CO32-¡¢SO42-¡¢Cl-ÖеÄÈô¸ÉÖÖÀë×Ó£¬¸ÃС×éͬѧȡÁË100mlË®Ñù½øÐÐʵÑ飺ÏòË®ÑùÖÐÏȵμÓÏõËá±µÈÜÒº£¬ÔٵμÓ1mol¡¤L-1ÏõËᣬʵÑé¹ý³ÌÖгÁµíÖÊÁ¿ÓëËù¼ÓÊÔ¼ÁÁ¿µÄ¹Øϵ±ä»¯ÈçÏÂͼËùʾ£º

(1)½öƾ¹Û²ì¿ÉÖª¸ÃË®ÑùÖÐÒ»¶¨²»º¬ÓеÄÑôÀë×ÓÊÇ________¡£

(2)ÓÉBµãµ½Cµã±ä»¯¹ý³ÌÖÐÏûºÄÏõËáµÄÌå»ýΪ__________ml¡£

(3)ÊÔ¸ù¾ÝʵÑé½á¹ûÍƲâK+ÊÇ·ñ´æÔÚ_______(Ìî¡°ÊÇ¡±»ò¡°·ñ¡±)Èô´æÔÚ£¬ÆäÎïÖʵÄÁ¿Å¨¶ÈµÄ·¶Î§ÊÇ______mol¡¤L-1(Èô²»´æÔÚ£¬Ôò²»±Ø»Ø´ð)¡£

(4)Éè¼Æ¼òµ¥ÊµÑéÑéÖ¤Ô­Ë®ÑùÖпÉÄÜ´æÔÚµÄÀë×Ó__________________________________(д³öʵÑé²½Öè¡¢ÏÖÏóºÍ½áÂÛ)¡£

II.ʪ·¨ÖƱ¸¸ßÌúËá¼Ø(K2FeO4)µÄ·´Ó¦ÌåϵÖÐÓÐÁùÖÖÁ£×Ó£ºFe(OH)3¡¢ClO£­¡¢OH£­¡¢FeO42-¡¢Cl£­¡¢H2O¡£

(1)д³ö²¢Åäƽʪ·¨ÖƸßÌúËá¼Ø·´Ó¦µÄÀë×Ó·½³Ìʽ£º_________________________¡£

(2)Èô·´Ó¦¹ý³ÌÖÐתÒÆÁË0.3 molµç×Ó£¬Ôò»¹Ô­²úÎïµÄÎïÖʵÄÁ¿Îª________ mol¡£

(3)µÍÎÂÏ£¬ÔÚ¸ßÌúËáÄÆÈÜÒºÖмÓÈëKOHÖÁ±¥ºÍ¿ÉÎö³ö¸ßÌúËá¼Ø(K2FeO4)£¬Ô­Òò_______________________________________________________________________¡£

(4)ÒÑÖªK2FeO4ÄÜË®½â²úÉúFe(OH)3ÓÃ×÷¾»Ë®¼Á£¬Çëд³öË®½âµÄÀë×Ó·½³Ìʽ___________

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø