ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÒÑÖªXÊÇÒ»ÖÖ¾ßÓйûÏãζµÄºÏ³ÉÏãÁÏ£¬ÏÂͼΪºÏ³ÉXµÄijÖÖÁ÷³Ì£º
Ìáʾ£º¢Ù²»ÄÜ×îÖÕ±»Ñõ»¯Îª¡ªCOOH£»
¢ÚDµÄ²úÁ¿¿ÉÒÔÓÃÀ´ºâÁ¿Ò»¸ö¹ú¼ÒµÄʯÓÍ»¯¹¤Ë®Æ½¡£
Çë¸ù¾ÝÒÔÉÏÐÅÏ¢£¬»Ø´ðÏÂÁÐÎÊÌ⣺
(1)C·Ö×ÓÖйÙÄÜÍŵÄÃû³ÆÊÇ__________£¬EµÄ½á¹¹¼òʽÊÇ________¡£
(2)D+E¡úXµÄ»¯Ñ§·´Ó¦ÀàÐÍΪ________·´Ó¦¡£
(3)ÉÏÊöA¡¢B¡¢C¡¢D¡¢E¡¢XÁùÖÖÎïÖÊÖУ¬»¥ÎªÍ¬ÏµÎïµÄÊÇ____________________¡£
(4)CµÄÒ»ÖÖͬ·ÖÒì¹¹ÌåF¿ÉÒÔ·¢ÉúË®½â·´Ó¦£¬ÔòFµÄ½á¹¹¼òʽΪ________¡¢ ________¡£
(5)·´Ó¦C£«E¡úXµÄ»¯Ñ§·½³ÌʽΪ______________¡£
¡¾´ð°¸¡¿ ôÈ»ù CH3CH2OH õ¥»¯·´Ó¦/È¡´ú·´Ó¦ A¡¢E HCOOCH2CH3 CH3COOCH3 CH3CH2COOH + CH3CH2OH CH3CH2COOCH2CH3 + H2O
¡¾½âÎö¡¿DµÄ²úÁ¿¿ÉÒÔÓÃÀ´ºâÁ¿Ò»¸ö¹ú¼ÒµÄʯÓÍ»¯¹¤Ë®Æ½£¬DΪÒÒÏ©£¬ÒÒÏ©ÓëË®·¢Éú¼Ó³É±äΪÒÒ´¼£¨E£©£¬ÓÉÓÚXÊǺ¬ÓÐ5¸ö̼µÄ±¥ºÍÒ»Ôªõ¥£¬ËùÒÔÓлúÎïCΪº¬ÓÐ3¸öCµÄ±¥ºÍÒ»ÔªôÈËᣬ¼´±ûË᣻ËùÒÔ£¬ÓлúÎïAΪ1-±û´¼£»ÓлúÎïBΪ±ûÈ©¡£
(1)×ÛÉÏËùÊö£¬CΪ±ûËᣬ¹ÙÄÜÍŵÄÃû³ÆôÈ»ù£»EΪÒÒ´¼£¬½á¹¹¼òʽCH3CH2OH£»ÕýÈ·´ð°¸£ºôÈ»ù£»CH3CH2OH¡£
(2)ÒÒ´¼ºÍ±ûËá·¢Éúõ¥»¯·´Ó¦Éú³Éõ¥ºÍË®£¬ÕýÈ·´ð°¸£ºõ¥»¯·´Ó¦/È¡´ú·´Ó¦¡£
(3)1-±û´¼¡¢±ûÈ©¡¢±ûËá¡¢ÒÒÏ©¡¢±ûËáÒÒõ¥¡¢ÒÒ´¼ÁùÖÖÎïÖÊÖУ¬»¥ÎªÍ¬ÏµÎïµÄÊÇ1-±û´¼ºÍÒÒ´¼£»ÕýÈ·´ð°¸£ºA¡¢E¡£
(4) FΪ±ûËáµÄͬ·ÖÒì¹¹Ì壬Äܹ»·¢ÉúË®½â·´Ó¦£¬½á¹¹Öк¬ÓÐõ¥»ù£¬FµÄ½á¹¹¼òʽΪ·Ö±ðΪ£ºHCOOCH2CH3 ¡¢CH3COOCH3£»ÕýÈ·´ð°¸£ºHCOOCH2CH3 ¡¢CH3COOCH3¡£
(5) ±ûËáºÍÒÒ´¼ÔÚŨÁòËá¼ÓÈÈÌõ¼þÏ·¢Éúõ¥»¯·´Ó¦£¬»¯Ñ§·½³ÌʽΪCH3CH2COOH + CH3CH2OH CH3CH2COOCH2CH3 + H2O£»ÕýÈ·´ð°¸£ºCH3CH2COOH + CH3CH2OH CH3CH2COOCH2CH3 + H2O¡£
¡¾ÌâÄ¿¡¿(1)2017ÄêÖпÆԺijÑо¿ÍŶÓͨ¹ýÉè¼ÆÒ»ÖÖÐÂÐÍNa-Fe3O4/HZSM-5¶à¹¦Äܸ´ºÏ´ß»¯¼Á£¬³É¹¦ÊµÏÖÁËCO2Ö±½Ó¼ÓÇâÖÆÈ¡ÐÁÍéÖµÆûÓÍ£¬¸ÃÑо¿³É¹û±»ÆÀ¼ÛΪ¡°CO2´ß»¯×ª»¯ÁìÓòµÄÍ»ÆÆÐÔ½øÕ¹¡±¡£
ÒÑÖª£ºH2(g)+1/2O2(g)=H2O(l) ¦¤H1 = £aKJ/mol
C8H18(1)+25/2O2(g)=8CO2(g)+9H2O(1) ¦¤H2= £bKJ/mol
ÊÔд³ö25¡æ¡¢101kPaÌõ¼þÏ£¬CO2ÓëH2·´Ó¦Éú³ÉÆûÓÍ(ÒÔC8H18±íʾ)µÄÈÈ»¯Ñ§·½³Ìʽ_________________________________¡£
(2)ÀûÓÃCO2¼°H2ΪÔÁÏ£¬ÔÚºÏÊʵĴ߻¯¼Á(ÈçCu/ZnO´ß»¯¼Á)×÷ÓÃÏ£¬Ò²¿ÉºÏ³ÉCH3OH£¬Éæ¼°µÄ·´Ó¦ÓУº
¼×£ºCO2(g)+3H2(g) CH3OH(g)+H2O(g) ¡÷H= ¡ª 53.7kJ¡¤mol-1 ƽºâ³£ÊýK1
ÒÒ£ºCO2(g)+H2(g) CO(g)+H2O(g) ¡÷H= + 41.2kJ¡¤mol-1 ƽºâ³£ÊýK2
¢ÙCO(g)+2H2(g) CH3OH(g)µÄƽºâ³£ÊýK=______(Óú¬K1¡¢K2µÄ±í´ïʽ±íʾ)£¬¸Ã·´Ó¦¡÷H_____0(Ìî¡°´óÓÚ¡±»ò¡°Ð¡ÓÚ¡±)¡£
¢ÚÌá¸ßCO2ת»¯ÎªCH3OHƽºâת»¯ÂʵĴëÊ©ÓÐ___________(ÌîдÁ½Ïî)¡£
¢Û´ß»¯¼ÁºÍ·´Ó¦ÌåϵµÄ¹Øϵ¾ÍÏñËøºÍÔ¿³×µÄ¹ØϵһÑù£¬¾ßÓи߶ȵÄÑ¡ÔñÐÔ¡£ÏÂÁÐËÄ×éʵÑ飬¿ØÖÆCO2ºÍH2³õʼͶÁϱȾùΪ1£º2.2£¬¾¹ýÏàͬ·´Ó¦Ê±¼ä(t1min)¡£
ζÈ(K) | ´ß»¯¼Á | CO2ת»¯ÂÊ(%) | ¼×´¼Ñ¡ÔñÐÔ(%) | ×ÛºÏÑ¡Ïî |
543 | Cu/ZnOÄÉÃ×°ô²ÄÁÏ | 12.3 | 42.3 | A |
543 | Cu/ZnOÄÉÃ×Ƭ²ÄÁÏ | 11.9 | 72.7 | B |
553 | Cu/ZnOÄÉÃ×°ô²ÄÁÏ | 15.3 | 39.1 | C |
553 | Cu/ZnOÄÉÃ×Ƭ²ÄÁÏ | 12.0 | 70.6 | D |
Óɱí¸ñÖеÄÊý¾Ý¿ÉÖª£¬ÏàͬζÈϲ»Í¬µÄ´ß»¯¼Á¶ÔCO2µÄת»¯ÎªCH3OHµÄÑ¡ÔñÐÔÓÐÏÔÖøÓ°Ï죬¸ù¾ÝÉϱíËù¸øÊý¾Ý½áºÏ·´Ó¦ÔÀí£¬ËùµÃ×îÓÅÑ¡ÏîΪ___________(Ìî×Öĸ·ûºÅ)¡£
(3)ÒÔCO¡¢H2ΪÔÁϺϳɼ״¼µÄ·´Ó¦Îª£ºCO(g)+2H2(g)CH3OH(g)¡£ÔÚÌå»ý¾ùΪ2LµÄÈý¸öºãÈÝÃܱÕÈÝÆ÷¢ñ¡¢¢ò¡¢¢óÖУ¬·Ö±ð¶¼³äÈë1molCOºÍ2molH2£¬Èý¸öÈÝÆ÷µÄ·´Ó¦Î¶ȷֱðΪT1¡¢T2¡¢T3ÇҺ㶨²»±ä¡£ÏÂͼΪÈý¸öÈÝÆ÷Öеķ´Ó¦¾ù½øÐе½5minʱH2µÄÌå»ý·ÖÊýʾÒâͼ£¬ÆäÖÐÓÐÒ»¸öÈÝÆ÷·´Ó¦Ò»¶¨´ïµ½Æ½ºâ״̬¡£
¢Ù0¡«5minʱ¼äÄÚÈÝÆ÷¢òÖÐÓÃCH3OH±íʾµÄ»¯Ñ§·´Ó¦ËÙÂÊΪ_________________¡£
¢ÚÈý¸öÈÝÆ÷ÖÐÒ»¶¨´ïµ½Æ½ºâ״̬µÄÊÇÈÝÆ÷________(ÌîдÈÝÆ÷´úºÅ)¡£