ÌâÄ¿ÄÚÈÝ

¢ñ¡¢¼×ͬѧÓûÅäÖÆ0.55 mo1¡¤L¡ª1 µÄNaOHÈÜÒº200mL£¨´æÔÚ200mLÈÝÁ¿Æ¿£©¡£³ÆÁ¿²Ù×÷ÈçÏ£º
¢ÙÏÈÓÃÍÐÅÌÌìƽ³ÆÁ¿ÉÕ±­µÄÖÊÁ¿¡£³ÆÁ¿Ç°Ïȵ÷½ÚÌìƽÁãµã¡£Óá°¡ý¡±±íʾÔÚÌìƽÓÒÅÌÉÏ·ÅÖÃíÀÂ룬Óá°¡ü¡±±íʾ´ÓÌìƽÓÒÅÌÉÏÈ¡ÏÂíÀÂ롣ȡÓÃíÀÂëÇé¿öºÍÓÎÂë¶ÁÊýÈçÏ£º
íÀÂëÖÊÁ¿
50
20
20
10
5
È¡ÓÃíÀÂëÇé¿ö
ÏÈ¡ýºó¡ü
¡ý
ÏÈ¡ýºó¡ü
¡ý
ÏÈ¡ýºó¡ü
 

ÉÕ±­µÄÖÊÁ¿Îª              g¡£
¢Ú³ÆÁ¿ÉÕ±­ºÍNaOH¹ÌÌåµÄÖÊÁ¿¡£ÔÙÔÚÌìƽÓÒÅÌÉÏ·ÅÖà         gíÀÂ룬½«ÓÎÂëµÄλÖÃÒƵ½        gµÄλÖã¬ÍùÉÕ±­ÖÐÖð½¥¼ÓÈëNaOH¹ÌÌ壬ֱµ½Ììƽ´ïµ½Æ½ºâ¡£
¢ò¡¢ÒÒͬѧÓûÓÃÓÃ18mol/L ŨÁòËáÅäÖÆ100 ml 3.0mol/L Ï¡ÁòËáµÄʵÑé²½ÖèÈçÏ£º
¢Ù ¼ÆËãËùÓÃŨÁòËáµÄÌå»ý  ¢Ú Á¿È¡Ò»¶¨Ìå»ýµÄŨÁòËá ¢Û Èܽ⠠¢Ü תÒÆ 
¢ÝÏ´µÓ ¢Þ¶¨ÈÝ  ¢ßÒ¡ÔÈ
»Ø´ðÏÂÁÐÎÊÌâ
£¨1£©ËùÐèŨÁòËáµÄÌå»ýÊÇ         £¬Á¿È¡Å¨ÁòËáËùÓõÄÁ¿Í²µÄ¹æ¸ñÊÇ    £¨ÇëÌî±àºÅ£©£¨´ÓÏÂÁÐÖÐÑ¡Óà A£®10ml   B£®25ml   C£®50ml   D£®100ml£©
£¨2£©¶¨ÈÝʱ¸©ÊÓÈÜÒºµÄ°¼ÒºÃæ¶ÔËùÅäÖƵÄÏ¡ÁòËáŨ¶ÈÓкÎÓ°Ïì               
£¨ÓÃÆ«´ó¡¢Æ«Ð¡¡¢ÎÞÓ°ÏìÌîд£©
¢ñ¡¢¢Ù33.2g ¢Ú5  2.6       ¢ò¡¢¢Å16.7ml  B  ¢ÆÆ«´ó

ÊÔÌâ·ÖÎö£º³ÆÁ¿À×ó±ß·ÅÎïÌ壬Óұ߷ÅíÀÂ룬ÎïÌåµÄÖÊÁ¿µÈÓÚíÀÂë¼ÓÓÎÂëµÄÖÊÁ¿¡£ÈÜÒºµÄÏ¡ÊÍ×ñÑ­Ï¡ÊͶ¨ÂÉ¡£¼´£ºc(ŨÁòËá)¡ÁV(ŨÁòËá)= c(Ï¡ÁòËá)¡ÁV(Ï¡ÁòËá)
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÏÂÃæÊǼ¸ÖÖʵÑéÖг£ÓõÄÒÇÆ÷£º
A.       B.       C.       D.
£¨1£©Ð´³öÐòºÅËù´ú±íµÄÒÇÆ÷µÄÃû³Æ£ºB___________£»C___________£»D___________
ʵÑéÊÒÒªÅäÖÆ500 mL 0.2 mol/L NaOHÈÜÒº£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨2£©ÓÃÍÐÅÌÌìƽ³ÆÈ¡ÇâÑõ»¯ÄÆ£¬ÆäÖÊÁ¿Îª_______________g¡£
£¨3£©ÏÂÁÐÖ÷Òª²Ù×÷²½ÖèµÄÕýȷ˳ÐòÊÇ_______________£¨ÌîÐòºÅ£©¡£
¢Ù³ÆÈ¡Ò»¶¨ÖÊÁ¿µÄÇâÑõ»¯ÄÆ£¬·ÅÈëÉÕ±­ÖУ¬ÓÃÊÊÁ¿ÕôÁóË®Èܽ⣻
¢Ú¡°¶¨ÈÝ¡±
¢Û´ýÀäÈ´ÖÁÊÒκ󣬽«ÈÜҺתÒƵ½500 mL ÈÝÁ¿Æ¿ÖУ»
¢Ü¸ÇºÃÆ¿Èû£¬·´¸´ÉÏϵߵ¹£¬Ò¡ÔÈ£»
¢ÝÓÃÉÙÁ¿µÄÕôÁóˮϴµÓÉÕ±­ÄڱںͲ£Á§°ô2¡ª3´Î£¬Ï´µÓҺתÒƵ½ÈÝÁ¿Æ¿ÖС£
£¨4£©ÔÚÅäÖƹý³ÌÖУ¬ÆäËû²Ù×÷¶¼ÊÇÕýÈ·µÄ£¬ÏÂÁвÙ×÷»áÒýÆðËùÅäŨ¶ÈÆ«¸ßµÄÊÇ__________¡£
¢ÙûÓÐÏ´µÓÉÕ±­ºÍ²£Á§°ô              ¢ÚתÒÆÈÜҺʱ²»É÷ÓÐÉÙÁ¿È÷µ½ÈÝÁ¿Æ¿ÍâÃæ
¢ÛÈÝÁ¿Æ¿²»¸ÉÔº¬ÓÐÉÙÁ¿ÕôÁóË®      ¢Ü¶¨ÈÝʱ¸©Êӿ̶ÈÏß
¢ÝδÀäÈ´µ½ÊÒξͽ«ÈÜҺתÒƵ½ÈÝÁ¿Æ¿²¢¶¨ÈÝ
£¨5£©Ð´³ö²½Öè¢Ú¡°¶¨ÈÝ¡±µÄ¾ßÌå²Ù×÷£º                                        
£¨6£©º£ÑóÖ²ÎïÈ纣´ø¡¢º£ÔåÖк¬ÓзḻµÄµâÔªËØ£¬µâÔªËØÒÔµâÀë×ÓµÄÐÎʽ´æÔÚ¡£Ä³Ñ§Éú¿Î
Íâ»î¶¯Ð¡×éÓû´Óº£ÔåÖÐÌáÈ¡µâ£¬Éè¼ÆÈçϵÄÁ÷³Ì£º
£¨ÒÑÖª¹ý³Ì¢ÚÖз´Ó¦µÄÀë×Ó·½³ÌʽΪ£º2I£­ + Cl2 = 2Cl£­ + I2£©

¢ñ.Ö¸³öÌáÈ¡µâµÄ¹ý³ÌÖÐÓйصÄʵÑé²Ù×÷µÄÃû³Æ£º¢Ù        £¬ ¢Û           ¡£
¢ò.ÌáÈ¡µâµÄ¹ý³ÌÖУ¬¿ÉÑ¡ÔñµÄÓлúÈܼÁÊÇ        (ÌîÐòºÅ) ¡£
A¡¢¾Æ¾«       B¡¢´×Ëá        C ¡¢ËÄÂÈ»¯Ì¼ 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø