ÌâÄ¿ÄÚÈÝ

ÖÐѧ»¯Ñ§Öм¸ÖÖ³£¼ûÎïÖʵÄת»¯¹ØϵÈçÏÂͼËùʾ£º

ÒÑÖª£ºB¡¢C¡¢DΪ³£¼ûµ¥ÖÊ£¬ÆäÖÐCΪÆøÌ壬B¡¢DΪ½ðÊô£»FΪ³£¼ûµÄÇ¿Ë᣻K³£ÎÂÏÂΪÆøÌ壬ÇÒÄÜʹƷºìÈÜÒºÍÊÉ«£»½«EÈÜÒºµÎÈë·ÐË®¿ÉÖƵÃÒ»ÖÖºìºÖÉ«½ºÌå¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ÈôÓÃB×÷Ñô¼«£¬D×÷Òõ¼«£¬AÈÜҺΪµç½âÖÊÈÜÒº£¬Í¨µçÒ»¶Îʱ¼äºó£¬AÈÜÒºµÄpH_____£¨Ìî¡°±ä´ó¡±¡¢¡°±äС¡±»ò¡°²»±ä¡±£©¡£

£¨2£©Ð´³ö·´Ó¦¢ÛµÄÀë×Ó·½³Ìʽ________________________________________________£¬·´Ó¦¢ÜµÄ»¯Ñ§·½³Ìʽ________________________________________________¡£

£¨3£©Ð´³ö¼ìÑéGÈÜÒºÖÐÑôÀë×ӵķ½·¨____________________________________________

___________________________________________________________¡£

£¨4£©ÊµÑéÖб£´æEÈÜҺʱҪ¼ÓÈë_____________________£¬ÓñØÒªµÄÎÄ×ÖºÍÀë×Ó·½³Ìʽ½âÊÍÔ­Òò_____________________________________________________________¡£

£¨1£©²»±ä

£¨2£©2Fe3++Cu=2Fe2++Cu2+£¬Cu+2H2SO4(Ũ)CuSO4+SO2+2H2O

£¨3£©È¡GÈÜÒºÉÙÐíÓÚÊÔ¹ÜÖУ¬µÎ¼ÓKSCNÈÜÒº£¬Ã»Ã÷ÏÔÏÖÏó£¬ÔÙ¼ÓÈëÂÈË®ÈÜÒº±ä³ÉѪºìÉ«£¬Ö¤Ã÷GÈÜÒºÖꬶøFe2+¡££¨ÆäËüºÏÀí´ð°¸Ò²¿É£©

£¨4£©¼ÓÈëÊÊÁ¿µÄÏ¡ÑÎËá    Fe3++3H2OFe(OH)3+3H+£¬¼ÓÑÎËáÒÖÖÆFe3+µÄË®½â¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø