ÌâÄ¿ÄÚÈÝ

ºÏÀí¡¢¸ßЧÀûÓýðÊô¿óÎ½«ÆäÖеĽðÊô´ÓÆ仯ºÏÎïÖл¹Ô­³öÀ´ÓÃÓÚÉú²úºÍÖÆÔì¸÷ÖÖ½ðÊô²ÄÁÏ£¬ÕâÒ»¹ý³ÌÔÚ¹¤ÒµÉϳÆΪ½ðÊôµÄÒ±Á¶¡£
£¨1£©ÒÔHgOΪԭÁÏÒ±Á¶Hg£¬Ò±Á¶·½·¨ÊÇ                     ¡£
£¨2£©ÂÁÈÈ·¨ÊÇÒ±Á¶½ðÊôµÄ·½·¨Ö®Ò»£¬Ð´³öÂÁÈÈ·¨Á¶Ìú(Fe2O3)µÄ»¯Ñ§·½³Ìʽ£º                                               ¡£Òý·¢ÂÁÈÈ·´Ó¦µÄʵÑé²Ù×÷ÊÇ£º
                                                     ¡£
£¨3£©Ä³Ð©½ðÊôÑõ»¯Îï·ÛÄ©ºÍÂÁ·ÛÔÚÒ»¶¨Ìõ¼þÏ¿ÉÒÔ·¢ÉúÂÁÈÈ·´Ó¦¡£ÏÂÁз´Ó¦ËÙÂÊ£¨¦Ô£©ºÍζȣ¨T£©µÄ¹ØϵʾÒâͼÖÐÓëÂÁÈÈ·´Ó¦×î½Ó½üµÄÊÇ£º                  £¨Ìî×Öĸ£©¡£
£¨Ã¿¿Õ2·Ö£¬¹²8·Ö£©£¨1£©¼ÓÈȷֽⷨ
£¨2£©Al£«Fe2O3  Al2O3 £«2Fe¡£    ¼ÓÉÙÁ¿KClO3£¬²åÉÏMgÌõ²¢½«Æäµãȼ¡£ 
£¨3£©b
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨12·Ö£©¸ßÌúËá¼ØÊÇÒ»ÖÖ¸ßЧµÄ¶à¹¦ÄܵÄË®´¦Àí¼Á¡£¹¤ÒµÉϳ£²ÉÓÃNaClOÑõ»¯·¨Éú²ú£¬Ô­ÀíΪ£º
3NaClO + 2Fe(NO3)3 + 10NaOH£½2Na2FeO4¡ý+ 3NaCl + 6NaNO3 + 5H2O
Na2FeO4£«2KOH£½K2FeO4£«2NaOH
Ö÷ÒªµÄÉú²úÁ÷³ÌÈçÏ£º

£¨1£©Ð´³ö·´Ó¦¢ÙµÄÀë×Ó·½³Ìʽ_____________________________¡£
£¨2£©Á÷³ÌͼÖС°×ª»¯¡±ÊÇÔÚijµÍÎÂϽøÐеģ¬ËµÃ÷´ËζÈÏÂKsp(K2FeO4) _________ Ksp(Na2FeO4)£¨Ìî¡°£¾¡±»ò¡°£¼¡±»ò¡°£½¡±£©¡£
£¨3£©·´Ó¦µÄζȡ¢Ô­ÁϵÄŨ¶ÈºÍÅä±È¶Ô¸ßÌúËá¼ØµÄ²úÂʶ¼ÓÐÓ°Ïì¡£
ͼ1Ϊ²»Í¬µÄζÈÏ£¬Fe(NO3)3²»Í¬ÖÊÁ¿Å¨¶È¶ÔK2FeO4Éú³ÉÂʵÄÓ°Ï죻
ͼ2Ϊһ¶¨Î¶ÈÏ£¬Fe(NO3)3ÖÊÁ¿Å¨¶È×î¼Ñʱ£¬NaClOŨ¶È¶ÔK2FeO4Éú³ÉÂʵÄÓ°Ïì¡£

¢Ù¹¤ÒµÉú²úÖÐ×î¼ÑζÈΪ_______¡æ£¬´ËʱFe(NO3)3ÓëNaClOÁ½ÖÖÈÜÒº×î¼ÑÖÊÁ¿Å¨¶ÈÖ®±ÈΪ_______¡£
¢ÚÈôNaClO¼ÓÈë¹ýÁ¿£¬Ñõ»¯¹ý³ÌÖлáÉú³ÉFe(OH)3£¬Ð´³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º
____________________________________________________¡£
ÈôFe(NO3)3¼ÓÈë¹ýÁ¿£¬ÔÚ¼îÐÔ½éÖÊÖÐK2FeO4ÓëFe3+·¢ÉúÑõ»¯»¹Ô­·´Ó¦Éú³ÉK3FeO4£¬´Ë·´Ó¦µÄÀë×Ó·½³Ìʽ£º____________________________________¡£
£¨4£©K2FeO4 ÔÚË®ÈÜÒºÖÐÒ×Ë®½â£º4FeO42¡ª+10H2O4Fe(OH)3+8OH¡ª+3O2¡ü¡£ÔÚ¡°Ìá´¿¡±K2FeO4ÖвÉÓÃÖؽᾧ¡¢Ï´µÓ¡¢µÍκæ¸ÉµÄ·½·¨£¬ÔòÏ´µÓ¼Á×îºÃÑ¡ÓÃ_______ÈÜÒº£¨ÌîÐòºÅ£©¡£
A£®H2OB£®CH3COONa¡¢Òì±û´¼C£®NH4Cl¡¢Òì±û´¼D£®Fe(NO3)3¡¢Òì±û´¼
£¨16·Ö£©ÇâäåËáÔÚÒ½Ò©ºÍʯ»¯¹¤ÒµÉÏÓй㷺ÓÃ;¡£ÏÂͼÊÇÄ£Ä⹤ҵÖƱ¸ÇâäåËá´ÖÆ·²¢¾«ÖÆÁ÷³Ì£º

¸ù¾ÝÉÏÊöÁ÷³Ì»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©»ìºÏ¢ÙÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ         ¡£
£¨2£©»ìºÏ¢ÙÖÐʹÓñùË®µÄÄ¿µÄÊÇ              ¡£
£¨3£©²Ù×÷¢òºÍ²Ù×÷¢óµÄÃû³Æ·Ö±ðÊÇ        ¡¢       ¡£
²Ù×÷¢óÒ»°ãÊÊÓÃÓÚ·ÖÀë____________»ìºÏÎï¡££¨Ñ¡Ìî±àºÅ£©
a£®¹ÌÌåºÍÒºÌå     b£®¹ÌÌåºÍ¹ÌÌå     c£®»¥²»ÏàÈܵÄÒºÌå   d£®»¥ÈܵÄÒºÌå
£¨4£©»ìºÏ¢ÚÖмÓÈëNa2SO3µÄÄ¿µÄÊÇ                               ¡£
£¨5£©´¿¾»µÄÇâäåËáӦΪÎÞÉ«ÒºÌ壬µ«Êµ¼Ê¹¤ÒµÉú²úÖÐÖƵõÄÇâäåËᣨ¹¤ÒµÇâäåËᣩ´øÓе­µ­µÄ»ÆÉ«¡£ÓÚÊǼ×ÒÒÁ½Í¬Ñ§Éè¼ÆÁ˼òµ¥ÊµÑé¼ÓÒÔ̽¾¿£º
¼×ͬѧ¼ÙÉ蹤ҵÇâäåËá³Êµ­»ÆÉ«ÊÇÒòΪº¬Fe3£«£¬ÔòÓÃÓÚÖ¤Ã÷¸Ã¼ÙÉèËùÓõÄÊÔ¼ÁΪ            £¬Èô¼ÙÉè³ÉÁ¢¿É¹Û²ìµ½µÄÏÖÏóΪ                 ¡£
ÒÒͬѧ¼ÙÉ蹤ҵÇâäåËá³Êµ­»ÆÉ«ÊÇÒòΪ_______£¬ÆäÓÃÓÚÖ¤Ã÷¸Ã¼ÙÉèËùÓõÄÊÔ¼ÁΪ            ¡£
»¯·ÊÔÚÅ©ÒµÉú²úÖÐÕ¼ÓÐÖØҪλÖ᣹úÄÚÍâũѧר¼ÒÆÕ±éÈÏΪ£¬ÔÚÆäËûÉú²úÒòËز»±äµÄÇé¿öÏ£¬Å©×÷ÎïÊ©Óû¯·Ê¿ÉÔö²ú40£¥£­60£¥¡£ºÏ³É°±¹¤Òµ¿ÉÒÔÌṩ´óÁ¿µÄµª·Ê£¬ÊÇÂú×ãÈËÀà¶ÔÁ¸Ê³Ôö³¤ÐèÇóµÄ·Ç³£ÖØÒªµÄ»¯Ñ§¹¤Òµ¡£
£¨1£©ÔÚ¹¤ÒµºÏ³É°±µÄ·´Ó¦ÖУ¬ÓÉÓڸ÷´Ó¦ÔÚ³£Î³£Ñ¹Ï£¬ÂýµÃ¼¸ºõ²»Äܾõ²ì£¬ÒªÊµÏÖ¹¤Òµ»¯·Ç³£À§ÄÑ£¬Ðí¶à»¯Ñ§¼ÒΪ´Ë½øÐÐÁ˲»Ð¸µÄŬÁ¦¡£ËûÃÇÏÈ´ÓζȺÍѹǿ×ÅÊÖ£¬Î¶ÈÉý¸ß¶ÔÌá¸ß»¯Ñ§·´Ó¦ËÙÂÊ         £¨ÌîÓÐÀû¡¢²»Àû»òÎ޹أ©£¬Ôö¼Óѹǿ¶ÔÌá¸ß»¯Ñ§·´Ó¦ËÙÂÊ      £¨ÌîÓÐÀû¡¢²»Àû»òÎ޹أ©£¬¿Æѧ¼ÒÃÇËäȻѡÔñÁ˺ÏÊʵÄζȺÍѹǿ£¬µ«Ð§¹û²»¼Ñ£¬ÈÔÎÞ·¨Í¶È빤ҵ»¯Éú²ú¡£µÂ¹ú»¯Ñ§¼Ò¹þ²®£¨Fritz Haber£¬1868£­1934£©Í¨¹ýŬÁ¦£¬ÔÚʹÓúÏÊÊ´ß»¯¼ÁµÄÇé¿öÏÂÖÕÓÚ½â¾öÁËÕâ¸öÎÊÌ⣬ʵÏÖÁ˺ϳɰ±µÄ¹¤Òµ»¯Éú²ú¡£ÄãÈÏΪ¸Ã·´Ó¦Äܹ¤Òµ»¯Éú²úµÄ¹Ø¼üÊÇ       
£¨2£©ºÏ³É°±ÊÇÖØÒªµÄÈ˹¤¹Ìµª·½·¨£¬³ýÈ˹¤¹ÌµªÍ⣬»¹ÓÐ×ÔÈ»¹Ìµª£¬ÉÁµç¹Ìµª¾ÍÊÇ×ÔÈ»¹ÌµªµÄÒ»ÖÖ·½Ê½£¬¿ÎÌÃÉÏ¿ÉÓøßѹ·¢ÉúÆ÷Ä£ÄâÕâÒ»¹ý³Ì£¬×°ÖÃÈçͼËùʾ£º

ʵÑ鿪ʼºó£¬¿ÉÒÔ¿´µ½ÊªÈóµÄÀ¶É«Ê¯ÈïÊÔÖ½±äºìÉ«£¬Çë½âÊÍÔ­Òò£¨Ó÷´Ó¦µÄ»¯Ñ§·½³Ìʽ±íʾ£©
                                             
                                              
                                              
ÑÇÂÈËáÄÆ£¨NaClO2£©ÊÇÒ»ÖÖÖØÒªµÄº¬ÂÈÏû¶¾¼Á£¬Ö÷ÒªÓÃÓÚË®µÄÏû¶¾ÒÔ¼°É°ÌÇ¡¢ÓÍÖ¬µÄƯ°×Óëɱ¾ú¡£ÒÔÏÂÊǹýÑõ»¯Çâ·¨Éú²úÑÇÂÈËáÄƵŤÒÕÁ÷³Ìͼ£º

ÒÑÖª£º¢ÙNaClO2µÄÈܽâ¶ÈËæζÈÉý¸ß¶øÔö´ó£¬Êʵ±Ìõ¼þÏ¿ɽᾧÎö³öNaClO2?3H2O¡£
¢Ú´¿ClO2Ò׷ֽⱬը£¬Ò»°ãÓÃÏ¡ÓÐÆøÌå»ò¿ÕÆøÏ¡Ê͵½10£¥ÒÔÏ°²È«¡£
¢Û160 g/L NaOHÈÜÒºÊÇÖ¸160 gNaOH¹ÌÌåÈÜÓÚË®ËùµÃÈÜÒºµÄÌå»ýΪ1L¡£
£¨1£©160 g/L NaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ    ¡¡¡¡¡£ÈôÒª¼ÆËã¸ÃÈÜÒºµÄÖÊÁ¿·ÖÊý£¬
»¹ÐèÒªµÄÒ»¸öÌõ¼þÊÇ¡¡¡¡¡¡¡¡¡¡¡¡               ¡¡¡¡¡¡¡¡¡¡¡¡£¨ÓÃÎÄ×Ö˵Ã÷£©¡£
£¨2£©·¢ÉúÆ÷ÖйÄÈë¿ÕÆøµÄ×÷ÓÿÉÄÜÊÇ¡¡¡¡¡¡£¨Ñ¡ÌîÐòºÅ£©¡£
a£®½«SO2Ñõ»¯³ÉSO3£¬ÔöÇ¿ËáÐÔ£» b£®Ï¡ÊÍClO2ÒÔ·ÀÖ¹±¬Õ¨£»c£®½«NaClO3Ñõ»¯³ÉClO2
£¨3£©ÎüÊÕËþÄڵķ´Ó¦µÄ»¯Ñ§·½³ÌʽΪ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£
ÎüÊÕËþµÄζȲ»Äܳ¬¹ý20¡æ£¬ÆäÄ¿µÄÊÇ¡¡¡¡                               ¡£
£¨4£©ÔÚ¼îÐÔÈÜÒºÖÐNaClO2±È½ÏÎȶ¨£¬ËùÒÔÎüÊÕËþÖÐӦά³ÖNaOHÉÔ¹ýÁ¿£¬ÅжÏNaOHÊÇ
·ñ¹ýÁ¿µÄ¼òµ¥ÊµÑé·½·¨ÊÇ                                              ¡£
£¨5£©ÎüÊÕËþÖÐΪ·ÀÖ¹NaClO2±»»¹Ô­³ÉNaCl£¬ËùÓû¹Ô­¼ÁµÄ»¹Ô­ÐÔÓ¦ÊÊÖС£³ýH2O2Í⣬»¹¿ÉÒÔÑ¡ÔñµÄ»¹Ô­¼ÁÊÇ¡¡    ¡¡¡¡£¨Ñ¡ÌîÐòºÅ£©¡£
a£®Na2O2         b£®Na2S          c£®FeCl2      
£¨6£©´ÓÂËÒºÖеõ½NaClO2?3H2O´Ö¾§ÌåµÄʵÑé²Ù×÷ÒÀ´ÎÊÇ¡¡¡¡¡¡¡¡¡¡£¨Ñ¡ÌîÐòºÅ£©¡£
a£®ÕôÁó    b£®Õô·¢   c£®×ÆÉÕ   d£®¹ýÂË    e£®ÀäÈ´½á¾§
ÒªµÃµ½¸ü´¿µÄNaClO2?3H2O¾§Ìå±ØÐë½øÐеIJÙ×÷ÊÇ¡¡¡¡¡¡¡¡¡¡  ¡¡¡¡£¨Ìî²Ù×÷Ãû³Æ£©¡£
¼õÉÙSO2µÄÅÅ·Å¡¢»ØÊÕÀûÓÃSO2³ÉΪÊÀ½çÐÔµÄÑо¿¿ÎÌâ¡£ÎÒ¹úÑо¿ÈËÔ±ÑÐÖƵÄÀûÓõÍƷλÈíÃÌ¿ó½¬(Ö÷Òª³É·ÖÊÇMnO2)ÎüÊÕ·ÏÔü¸ßαºÉÕ²úÉúµÄSO2£¬ÖƱ¸ÁòËáÃ̵ÄÉú²úÁ÷³ÌÈçÏ£º

½þ³öÒºµÄpH£¼2£¬ÆäÖеĽðÊôÀë×ÓÖ÷ÒªÊÇMn2£«£¬»¹º¬ÓÐÉÙÁ¿µÄFe2£«¡¢Al3£«¡¢Ca2£«¡¢Pb2£«µÈÆäËû½ðÊôÀë×Ó¡£
ÓйؽðÊôÀë×ӵİ뾶ÒÔ¼°ÐγÉÇâÑõ»¯Îï³ÁµíʱµÄpH¼ûÏÂ±í£¬ÑôÀë×ÓÎü¸½¼ÁÎü¸½½ðÊôÀë×ÓµÄЧ¹û¼ûÏÂͼ¡£

Àë×Ó
Àë×Ӱ뾶(pm)
¿ªÊ¼³ÁµíʱµÄpH
ÍêÈ«³ÁµíʱµÄpH
Fe2£«
74
7.6
9.7
Fe3£«
64
2.7
3.7
Al3£«
50
3.8
4.7
Mn2£«
80
8.3
9.8
Pb2£«
121
8.0
8.8
Ca2£«
99
£­
£­
 
ÒÑÖªPbO2µÄÑõ»¯ÐÔ´óÓÚMnO2¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢Å д³ö½þ³ö¹ý³ÌÖÐÖ÷Òª·´Ó¦µÄ»¯Ñ§·½³Ìʽ   £¬Ñõ»¯¹ý³ÌÖÐÖ÷Òª·´Ó¦µÄÀë×Ó·½³Ìʽ   ¡£
¢Æ ÔÚÑõ»¯ºóµÄÒºÌåÖмÓÈëʯ»Ò½¬£¬ÓÃÓÚµ÷½ÚpH£¬pHÓ¦µ÷½ÚÖÁ   ¡£
¢Ç ÑôÀë×ÓÎü¸½¼ÁÓÃÓÚ³ýÈ¥ÔÓÖʽðÊôÀë×Ó¡£¾ö¶¨ÑôÀë×ÓÎü¸½¼ÁÎü¸½Ð§¹ûµÄÒòËØÊÇ   £¨ÌîдÐòºÅ£©¡£
a£®ÈÜÒºµÄpH      b£®½ðÊôÀë×ӵĵçºÉ      c£®½ðÊôÀë×ӵİ뾶      d£®Îü¸½Ê±¼ä
¢È ²Ù×÷a°üÀ¨   µÈ¹ý³Ì¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø