ÌâÄ¿ÄÚÈÝ
10£®´Óº£Ë®ÖÐÌáÈ¡äåµÄÖ÷Òª¹¤ÒÕÁ÷³ÌÓУ¨1£©ÏòËữµÄº£Ë®ÖÐͨÈëÊÊÁ¿µÄÂÈÆø£¬Ê¹äåÀë×Óת»¯Îªµ¥ÖÊä壺2NaBr+Cl2¨TBr2+2NaCl
£¨2£©ÏòÎüÊÕËþÄÚµÄÈÜÒºÖÐͨÈëÊÊÁ¿µÄÂÈÆø£º2HBr+Cl2¨T2HCl+Br2
£¨3£©ÕôÁ󷨽«º£Ë®Å¨Ëõ£¬ÓÃÁòËὫŨËõµÄº£Ë®Ëữ
£¨4£©Ïòº¬ÓÐäåµ¥ÖʵÄË®ÈÜÒºÖÐͨÈë¿ÕÆøºÍË®ÕôÆø£¬½«äåµ¥ÖÊ´µÈëÊ¢ÓжþÑõ»¯ÁòÈÜÒºµÄÎüÊÕËþÄÚÒÔ´ïµ½¸»¼¯µÄÄ¿µÄ£ºBr2+SO2+2H2O¨T2HBr+H2SO4
£¨5£©ÓÃËÄÂÈ»¯Ì¼£¨»ò±½£©ÝÍÈ¡ÎüÊÕËþÄÚµÄÈÜÒºÖеÄäåµ¥ÖÊ£®
ÕýÈ·µÄ˳ÐòÊÇ£¨¡¡¡¡£©
A£® | £¨1£©£¨2£©£¨3£©£¨4£©£¨5£© | B£® | £¨3£©£¨1£©£¨4£©£¨2£©£¨5£© | C£® | £¨5£©£¨1£©£¨3£©£¨2£©£¨4£© | D£® | £¨5£©£¨4£©£¨3£©£¨2£©£¨1£© |
·ÖÎö º£Ë®ÓÃÕôÁó·½·¨Å¨Ëõº£Ë®£¬¼ÓÈëÁòËὫŨËõµÄº£Ë®Ëữ£»ËữµÄº£Ë®ÖÐͨÈëÊÊÁ¿µÄÂÈÆø£¬ºÍäåÀë×Ó·¢ÉúÑõ»¯»¹Ô·´Ó¦Éú³Éäåµ¥ÖÊ£»Ïòº¬äåµ¥ÖʵÄË®ÈÜÒºÖÐͨÈë¿ÕÆøºÍË®ÕôÆø£¬½«äåµ¥ÖÊ´µÈëÊ¢¶þÑõ»¯ÁòµÄÈÜÒºÖб»»¹ÔΪä廯Ç⣬ÏòÎüÊÕËþÄÚÖÐÈÜÒºÄÚͨÈëÊÊÁ¿µÄÂÈÆøÑõ»¯äåÀë×ÓΪäåµ¥ÖÊ£»ÀûÓÃÝÍÈ¡·ÖÒº·½·¨ÝÍÈ¡äåµ¥ÖÊ£®
½â´ð ½â£º´Óº£Ë®ÖÐÌáÈ¡äåµÄÖ÷Òª¹¤ÒÕÁ÷³ÌµÄ˳ÐòΪ£º
£¨3£©º£Ë®ÓÃÕôÁó·½·¨Å¨Ëõº£Ë®£¬¼ÓÈëÁòËὫŨËõµÄº£Ë®Ëữ£»
£¨1£©ËữµÄº£Ë®ÖÐͨÈëÊÊÁ¿µÄÂÈÆø£¬ºÍäåÀë×Ó·¢ÉúÑõ»¯»¹Ô·´Ó¦Éú³Éäåµ¥ÖÊ£¬2Br-+Cl2=Br2+2Cl-£»
£¨4£©Ïòº¬äåµ¥ÖʵÄË®ÈÜÒºÖÐͨÈë¿ÕÆøºÍË®ÕôÆø£¬½«äåµ¥ÖÊ´µÈëÊ¢¶þÑõ»¯ÁòµÄÈÜÒºÖб»»¹ÔΪä廯Ç⣬Br2+SO2+2H2O=H2SO4+2HBr£¬
£¨2£©ÏòÎüÊÕËþÄÚÖÐÈÜÒºÄÚͨÈëÊÊÁ¿µÄÂÈÆøÑõ»¯äåÀë×ÓΪäåµ¥ÖÊ£¬2HBr+Cl2=Br2+2HCl£»
£¨5£©ÀûÓÃÝÍÈ¡·ÖÒº·½·¨ÝÍÈ¡äåµ¥ÖÊ£¬
¹ÊÁ÷³Ì˳ÐòΪ£º£¨3£©£¨1£©£¨4£©£¨2£©£¨5£©£¬
¹ÊÑ¡B£®
µãÆÀ ±¾Ì⿼²éÁ˺£Ë®ÌáäåµÄ¹¤ÒµÉú²ú¹ý³ÌºÍÊÔ¼ÁÑ¡Ôñ£¬×¢ÒâÔÀíµÄ·ÖÎöÅжϣ¬»¯Ñ§·½³ÌʽÊéдÊǹؼü£¬ÌâÄ¿½Ï¼òµ¥£®
A£® | A3BC4 | B£® | A2£¨BC4£©3 | C£® | A2BC3 | D£® | A2BC4 |
A£® | ´ÓÉϵ½ÏÂÇ⻯ÎïµÄÈ۷еãÖð½¥Éý¸ß | |
B£® | ´ÓÉϵ½Ïµ¥ÖʵĻ¹ÔÐÔÖð½¥¼õÈõ | |
C£® | ´ÓÉϵ½ÏÂ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïËáÐÔÖð½¥¼õÈõ | |
D£® | ´ÓÉϵ½ÏÂÔ×ӵõç×ÓµÄÄÜÁ¦Öð½¥ÔöÇ¿ |
A£® | ±½ÓëäåË®»ìºÏ£¬Õñµ´¾²Öã¬äåË®²ãÍÊÉ« | |
B£® | ÒÒϩͨÈëËáÐÔó{ÃÌËá¼ØÈÜÒºÖУ¬ÈÜÒºÍÊÉ« | |
C£® | ÒÒϩͨÈëäåµÄËÄ·Õ»¯Ì¼ÈÜÒºÖУ¬ÈÜÒºÍÊÉ« | |
D£® | ¼×ÍéÓëÂÈÆø»ìºÏ¹âÕÕ£¬ÆøÌåÑÕÉ«±ädz |
ÔªËرàºÅ | ÔªËØÐÔÖÊ»òÔ×ӽṹ |
A | ÓÐÈý¸öµç×Ӳ㣬K¡¢M²ãµç×ÓÊýÖ®ºÍµÈÓÚL²ãµç×ÓÊý |
B | ¶ÌÖÜÆÚÖнðÊôÐÔ×îÇ¿ |
C | ³£ÎÂϵ¥ÖÊΪ˫Ô×Ó·Ö×Ó£¬Ç⻯ÎïµÄË®ÈÜÒº³Ê¼îÐÔ |
D | ÔªËØ×î¸ßÕý¼ÛÊÇ+7¼Û |
¢ÙAÔªËØÔÚÖÜÆÚ±íÖеÄλÖõÚÈýÖÜÆÚ¢öA×壻
¢ÚBÔªËØÔ×ӽṹʾÒâͼ£»
¢ÛCµ¥ÖÊ·Ö×ӵĵç×Óʽ£»Óõç×Óʽ±íʾAºÍBÔªËØ×é³ÉµÄ»¯ºÏÎïµÄÐγɹý³Ì£»
¢ÜDÔªËØÔÚ×ÔÈ»½çÓÐÁ½ÖÖºËËØ£¬ÓÃÔ×Ó·ûºÅ±íʾÆäÖÐ×ÓÊýΪ20µÄºËËØ£®
£¨2£©ÔªËØDÓëÔªËØAÏà±È£¬·Ç½ðÊôÐÔ½ÏÇ¿µÄÊÇCl£¨ÓÃÔªËØ·ûºÅ±íʾ£©£¬ÏÂÁбíÊöÖÐÄÜÖ¤Ã÷ÕâÒ»ÊÂʵµÄÊÇbde£¨ÌîÑ¡ÏîÐòºÅ£©£®
a£®³£ÎÂÏÂDµÄµ¥ÖʺÍAµÄµ¥ÖÊ״̬²»Í¬
b£®DµÄÇ⻯Îï±ÈAµÄÇ⻯ÎïÎȶ¨
c£®Ò»¶¨Ìõ¼þÏÂDºÍAµÄµ¥Öʶ¼ÄÜÓëÄÆ·´Ó¦
d£®AµÄ×î¸ß¼Ûº¬ÑõËáËáÐÔÈõÓÚDµÄ×î¸ß¼Ûº¬ÑõËá
e£®Dµ¥ÖÊÄÜÓëAµÄÇ⻯Îï·´Ó¦Éú³ÉAµ¥ÖÊ
£¨3£©Ì½Ñ°ÎïÖʵÄÐÔÖʲîÒìÐÔÊÇѧϰµÄÖØÒª·½·¨Ö®Ò»£®A¡¢B¡¢C¡¢DËÄÖÖÔªËصÄ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïÖл¯Ñ§ÐÔÖÊÃ÷ÏÔ²»Í¬ÓÚÆäËûÈýÖÖµÄÊÇNaOH£¨Ð´»¯Ñ§Ê½£©£®
£¨4£©XÊÇÓÉA¡¢B¡¢C¡¢DËÄÖÖÔªËØÖеÄijÖÖÔªËØ×é³ÉµÄµ¥ÖÊ£¬ÄܾÏÂͼËùʾµÄ¹ý³Ìת»¯ÎªW£¨ÆäËûÌõ¼þÂÔÈ¥£©£®
X$\stackrel{O_{2}}{¡ú}$Y$\stackrel{O_{2}}{¡ú}$Z$\stackrel{H_{2}O}{¡ú}$W
¢ÙÈôYÊÇÓд̼¤ÐÔÆøζµÄÎÞÉ«ÆøÌ壬°ÑYͨÈëBaCl2ÈÜÒºÖУ¬È»ºóµÎ¼ÓÊÊÁ¿H2O2ÈÜÒº£¬Óа×É«³ÁµíÉú³É£¬´Ë°×É«³ÁµíµÄ»¯Ñ§Ê½Îª£ºBaSO4£»Éú³É¸Ã°×É«³ÁµíµÄ»¯Ñ§·½³ÌʽΪBaCl2+SO2+H2O2=BaSO4¡ý+2HCl£¨»òBa2++SO2+H2O2=BaSO4¡ý+2H+£©£»
¢ÚÈôZÊǺì×ØÉ«ÆøÌ壬ÔòZ¡úWµÄ·´Ó¦ÖÐÑõ»¯¼ÁÓ뻹ԼÁÎïÖʵÄÁ¿Ö®±ÈΪ£º1£º2£®
A£® | NH4HCO3ÈÜÓÚ¹ýÁ¿µÄNaOHÈÜÒºÖУºHCO3-+OH-¨TCO32-+H2O | |
B£® | ÂÈ»¯ÑÇÌúÈÜÒººÍÏ¡ÏõËá»ìºÏ£º3Fe2++4H++NO3-¨T3Fe3++2H2O+NO¡ü | |
C£® | AlCl3ÈÜÒºÖмÓÈë×ãÁ¿µÄ°±Ë®£ºAl3++4OH-¨TAlO2-+2H2O | |
D£® | NO2ÈÜÓÚË®£º3NO2+H2O¨T2H++2NO3-+NO |