ÌâÄ¿ÄÚÈÝ

¶ÌÖÜÆÚÔªËØW¡¢X¡¢Y¡¢Z¡¢ÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃÈçͼËùʾ£¬
W
 
 
 
 
 
 
 
 
 
 
X
Y
Z
 
 
ÆäÖÐX¡¢Y¡¢ZÈýÖÖÔªËصÄÖÊ×ÓÊýÖ®ºÍΪ21¡£?
(1)WÓëZÐγÉÔ­×Ó¸öÊý±ÈΪ1¡Ã1µÄ»¯ºÏÎÆäµç×ÓʽΪ           ¡£
(2)YµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÓëYµÄÇ⻯ÎïÇ¡ºÃÍêÈ«·´Ó¦£¬Éú³ÉÎïµÄË®ÈÜÒº³Ê
ËáÐÔ£¬ÆäÔ­ÒòÊÇ                                      (Óû¯Ñ§ÓÃÓï±íʾ)£»
¸ÃÈÜÒºÖи÷ÖÖÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ                              ¡£
(3)ÓÉX W4¡¢Z2ºÍKOHÈÜÒº×é³ÉµÄÐÂÐÍȼÁϵç³ØÖУ¬¸º¼«ÉÏ·¢Éú·´Ó¦µÄµç¼«·´Ó¦Ê½Îª
                                                  ¡£
(4)ÒÑÖª£º2YZ2(g)  Y2Z4(g)£»¡÷H£¼0¡£ÔÚºãκãÈÝÌõ¼þÏ£¬½«Ò»¶¨Á¿XZ2ºÍX2Z4µÄ»ìºÏÆøÌåͨÈëÈÝ»ýΪ2LµÄÃܱÕÈÝÆ÷ÖУ¬·´Ó¦¹ý³ÌÖи÷ÎïÖʵÄÎïÖʵÄÁ¿Å¨¶ÈcËæʱ¼ä
tµÄ±ä»¯¹ØϵÈçÓÒͼËùʾ¡£
¢Ù a¡¢b¡¢c¡¢dËĸöµãÖУ¬»¯Ñ§·´Ó¦
´¦ÓÚƽºâ״̬µÄÊÇ          µã¡£
¢Ú 25 minʱ£¬Ôö¼ÓÁË          
£¨ÌîÎïÖʵĻ¯Ñ§Ê½£©       mol¡£
¢Û a¡¢b¡¢c¡¢dËĸöµãÖÐËù±íʾµÄ·´Ó¦Ìåϵ
ÖУ¬ÆøÌåÑÕÉ«ÓÉÉdzµÄ˳ÐòÊÇ     __  
£¨Ìî×Öĸ£©¡£
(1)                                     £¨1·Ö£©
£¨2£©NH4+  +  H2  NH3¡¤H2O  +  H+             £¨1·Ö£©
c (NO3-£©£¾ c (NH4+) £¾ c (H+) £¾ c (OH-)                £¨2·Ö£©
£¨3£©CH4 - 8e- + 10OH -£½ 4CO32- +7H2O   £¨2·Ö£©
£¨4£©¢Ùb,d£¨2·Ö£©    ¢ÚNO2£»  0.8£¨2·Ö£©    ¢Ûcdba £¨2·Ö£©  
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨14·Ö£©Ô­×ÓÐòÊýÓÉСµ½´óÅÅÁеÄËÄÖÖ¶ÌÖÜÆÚÔªËØX¡¢Y¡¢Z¡¢W£¬ËÄÖÖÔªËصÄÔ­×ÓÐòÊýÖ®ºÍΪ32£¬ÔÚÖÜÆÚ±íÖÐXÊÇÔ­×Ӱ뾶×îСµÄÔªËØ£¬Y¡¢Z×óÓÒÏàÁÚ£¬Z¡¢WλÓÚͬÖ÷×å¡£
£¨1£©WÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃΪ              ;д³öYÔªËØÔ­×ӵļ۵ç×ÓÅŲ¼Ê½£º               £»
£¨2£©ÓÉX¡¢ZÁ½ÔªËØ¿ÉÒÔ×é³ÉA¡¢BÁ½ÖÖ»¯ºÏÎAÔÚÒ»¶¨Ìõ¼þÏ¿ÉÒÔ·Ö½â³ÉB£¬AµÄ·Ö×ÓÊôÓÚ              £¨Ìî¡°¼«ÐÔ¡±¡¢¡°·Ç¼«ÐÔ¡±£©·Ö×Ó¡£
£¨3£©Ò»¶¨Ìõ¼þÏ£¬YµÄµ¥ÖÊÆøÌåÓëXµÄµ¥ÖÊÆøÌå³ä·Ö·´Ó¦Éú³É6.8g CÆøÌ壨ÒÑÖªn(X):n(Y)=3:1)¿É·Å³ö18.44 kJÈÈÁ¿£¬Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ                    ¡£
£¨4£©ÓÉX¡¢Y¡¢Z¡¢WËÄÖÖÔªËØ×é³ÉµÄÒ»ÖÖÀë×Ó»¯ºÏÎïD
¢ÙÒÑÖª1mol DÄÜÓë×ãÁ¿NaOHŨÈÜÒº·´Ó¦Éú³É±ê×¼×´¿öÏÂ44.8LÆøÌ塣д³ö¼ÓÈÈÌõ¼þÏÂDÓëNaOHÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ                                    ¡£
¢ÚÓÖÖªD¼ÈÄÜÓëÑÎËá·´Ó¦£¬ÓÖÄÜÓëÂÈË®·´Ó¦£¬Ð´³öDÓëÂÈË®·´Ó¦µÄÀë×Ó·½³Ìʽ
                                                          ¡£
£¨5£©XµÄµ¥ÖÊÓëZµÄµ¥ÖÊÔÚKOHµÄŨÈÜÒºÖпÉÒÔÐγÉÔ­µç³Ø£¬Èç¹ûÒÔ½ðÊôMºÍ½ðÊôNΪ¶èÐԵ缫£¬ÔÚµç³ØµÄM¼«Í¨ÈëXµÄµ¥ÖÊÆøÌ壬N¼«Í¨ÈëZµÄµ¥ÖÊÆøÌ壬ÔòM¼«µÄµç¼«·´Ó¦Ê½Îª                                         ¡£
£¨15·Ö£©ÏÂͼÊÇÖÐѧ»¯Ñ§³£¼ûÎïÖʵÄת»¯¹Øϵ£¨Ä³Ð©·´Ó¦Ìõ¼þ¼°²¿·Ö²úÎïÒÑÂÔÈ¥£©£¬A¡¢GΪÈÕ³£Éú»îÖеij£¼û½ðÊô¡£B¡¢C¡¢E¡¢I¡¢JΪÆøÌ壬ÆäÖÐCΪ»ÆÂÌÉ«ÆøÌ壬MΪºìºÖÉ«½ºÌå¡£

£¨1£©ÒÑÖªAΪµÚ26ºÅÔªËØ£¬Çëд³öAÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃ__________¡£
£¨2£©DÓëG·´Ó¦µÄ»¯Ñ§·½³Ìʽ_________________________¡£
£¨3£©·´Ó¦¢ÚÀë×Ó·½³Ìʽ__________________________¡£
£¨4£©F¡úMµÄ²Ù×÷·½·¨_______________¡£
£¨5£©ÏÖ½«Ò»ÊÔ¹ÜJÆøÌåµ¹Á¢ÓÚË®²ÛÖÐÒ»¶Îʱ¼äºó£¬Ë®ÃæÉÏÉýµ«²»³äÂú£»Èôʹˮ³äÂúÕû¸öÊԹܣ¬Ó¦ÏòÊÔ¹ÜÖÐͨÈëÒ»¶¨Á¿__________£¨ÌîÆøÌåµÄ»¯Ñ§Ê½£©£¬´ËʱÊÔ¹ÜÖÐÈÜÒºµÄŨ¶ÈΪ________mol/L£¨ÆøÌåÌå»ý°´±ê×¼×´¿ö¼ÆË㣩£¨±£ÁôÁ½Î»ÓÐЧÊý×Ö£©¡£
£¨6£©¢ÙX¡¢Y¾ùΪ¶ÌÖÜÆÚÔªËØ£¬X×îÍâ²ãµç×ÓÊý±ÈCÆøÌåËùº¬ÔªËØ×îÍâ²ãµç×ÓÉÙ1¸öÇÒ²»Í¬ÖÜÆÚ£¬YÓëXͬÖ÷×壬ÏÂÁйØÓÚX¡¢Y¡¢CÈýÔªËØ˵·¨ÕýÈ·µÄÊÇ__________¡£
A£®Ô­×Ӱ뾶  X£¼Y£¼C          B£®Àë×Ӱ뾶  X£¼C£¼Y
C£®·Ç½ðÊôÐÔ  X£¼Y£¼C          D£®×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïËáÐÔ C£¾X£¾Y
E£®Ç⻯Îï·Ðµã X£¼Y£¼C
¢ÚÇëд³öXµÄÇ⻯ÎïÖÐÔ­×Ó¸öÊý±ÈΪ1£º1µÄ»¯ºÏÎïµÄµç×Óʽ_________¡£
£¨7£©DÓëG·´Ó¦Éú³ÉAµÄͬʱ£¬»¹ÓÐÁíÒ»ÖÖ²úÎ¹¤ÒµÉÏÓÃÂÁÍÁ¿ó£¨Ö÷Òª³É·ÖΪAl2O3¡¢¡¢SiO2¡¢Fe2O3£©ÌáÈ¡ÆäµÄ¹¤ÒÕÁ÷³ÌÈçÏ£º

½áºÏ·´Ó¦II£¬ÅжÏÏÂÁÐ΢Á£½áºÏÖÊ×Ó£¨H+£©µÄÄÜÁ¦ÓÉÇ¿µ½ÈõµÄ˳ÐòÊÇ_________£¨Ìî×ÖĸÐòºÅ£©¡£
A£®AlO2¡ª        B£®OH¡ª        C£®SiO32¡ª

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø