ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿(1)ÔÚ»¯Ñ§·´Ó¦ÖУ¬Ö»Óм«ÉÙÊýÄÜÁ¿±Èƽ¾ùÄÜÁ¿¸ßµÃ¶àµÄ·´Ó¦Îï·Ö×Ó·¢ÉúÅöײʱ²Å¿ÉÄÜ·¢Éú»¯Ñ§·´Ó¦£¬ÕâЩ·Ö×Ó³ÆΪ»î»¯·Ö×Ó£¬Ê¹ÆÕͨ·Ö×Ó±ä³É»î»¯·Ö×ÓËùÐèÌṩµÄ×îµÍÏ޶ȵÄÄÜÁ¿½Ð»î»¯ÄÜ£¬Æ䵥λͨ³£ÓÃkJ/mol±íʾ¡£ÇëÈÏÕæ¹Û²ìͼʾ£¬È»ºó»Ø´ðÎÊÌ⣺
¢ÙͼÖÐËùʾ·´Ó¦ÊÇ_____(Ìî¡°ÎüÈÈ¡±»ò¡°·ÅÈÈ¡±)·´Ó¦£¬¸Ã·´Ó¦µÄ¦¤H=____ (Óú¬E1¡¢E2µÄ´úÊýʽ±íʾ)¡£
¢ÚÓÉÉÏͼ¿ÉÖªÇúÏߢò½ÏÇúÏߢñµÍ£¬ÕâÊÇÓÉÓÚ________¡£
(2)¼×´¼¼ÈÊÇÖØÒªµÄ»¯¹¤ÔÁÏ,ÓÖ¿É×÷ΪȼÁÏ¡£ÀûÓúϳÉÆø(Ö÷Òª³É·ÖΪCO¡¢CO2ºÍH2)ÔÚ´ß»¯¼Á×÷ÓÃϺϳɼ״¼,·¢ÉúµÄÖ÷Òª·´Ó¦ÈçÏÂ:¢ÙCO(g)+2H2(g)CH3OH(g)¦¤H1 ¢ÚCO2(g)+3H2(g)
CH3OH(g)+H2O(g)¦¤H2¢ÛCO2(g)+H2(g)
CO(g)+H2O(g)¦¤H3¡£ÒÑÖª·´Ó¦¢ÙÖÐÏà¹ØµÄ»¯Ñ§¼ü¼üÄÜÊý¾ÝÈçÏÂ:
»¯Ñ§¼ü | H-H | C-O | H-O | C-H | |
E/ kJ¡¤mol-1 | 436 | 343 | 1076 | 465 | 413 |
Óɴ˼ÆË㦤H1= _____kJ¡¤mol-1£»ÒÑÖª¦¤H2=£58 kJ¡¤mol-1£¬Ôò¦¤H3=___kJ¡¤mol-1¡£
¡¾´ð°¸¡¿·ÅÈÈ ¡ª£¨E1-E2£©kJ/mol »ò £¨E2-E1£©kJ/mol ¼ÓÈë´ß»¯¼Á -99 +41
¡¾½âÎö¡¿
£¨1£©¢ÙÓÉͼ¿ÉÖª£¬¸Ã·´Ó¦·´Ó¦ÎïµÄ×ÜÄÜÁ¿¸ßÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿£¬¦¤H=Éú³ÉÎïµÄ×ÜÄÜÁ¿-·´Ó¦ÎïµÄ×ÜÄÜÁ¿£»
¢Ú¼ÓÈë´ß»¯¼Á¿É½µµÍ·´Ó¦µÄ»î»¯ÄÜ£»
£¨2£©¸ù¾Ý¦¤H=·´Ó¦ÎïµÄ×ܼüÄÜ-Éú³ÉÎïµÄ×ܼüÄܼÆË㦤H1£¬¸ù¾Ý¸Ç˹¶¨ÂɽøÐмÆËã¡£
£¨1£©¢ÙÓÉͼ¿ÉÖª£¬¸Ã·´Ó¦·´Ó¦ÎïµÄ×ÜÄÜÁ¿¸ßÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿£¬Îª·ÅÈÈ·´Ó¦£¬¦¤H=Éú³ÉÎïµÄ×ÜÄÜÁ¿-·´Ó¦ÎïµÄ×ÜÄÜÁ¿= (E2-E1)kJ/mol£»
¢ÚÓÉͼ¿ÉÖªÇúÏߢò½ÏÇúÏߢñµÍ£¬·´Ó¦µÄ»î»¯ÄܽµµÍ£¬Òò´ËÊǼÓÈë´ß»¯¼ÁÔì³ÉµÄ£»
£¨2£©¦¤H1=1076kJ/mol+2¡Á436kJ/mol-3¡Á413kJ/mol-343kJ/mol-465kJ/mol=-99 kJ¡¤mol-1£»
¸ù¾Ý¸Ç˹¶¨ÂÉ£¬¢Ú-¢Ù=¢Û£¬Ôò¦¤H3=-58kJ/mol-(-99kJ/mol)=+41 kJ¡¤mol-1¡£
![](http://thumb2018.1010pic.com/images/loading.gif)
¡¾ÌâÄ¿¡¿Ä³Î¶Èʱ£¬ÔÚ2LµÄÃܱÕÈÝÆ÷ÖУ¬X¡¢Y¡¢Z(¾ùΪÆøÌå)ÈýÖÖÎïÖʵÄÁ¿Ëæʱ¼äµÄ±ä»¯ÇúÏßÈçͼËùʾ£º
(1)ÓÉͼÖÐËù¸øÊý¾Ý½øÐзÖÎö£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________¡£
(2)ÈôÉÏÊö·´Ó¦ÖÐX¡¢Y¡¢Z·Ö±ðΪH2¡¢N2¡¢NH3£¬Ä³Î¶ÈÏ£¬ÔÚÈÝ»ýºã¶¨Îª2.0LµÄÃܱÕÈÝÆ÷ÖгäÈë2.0mol N2ºÍ2.0mol H2£¬Ò»¶Îʱ¼äºó·´Ó¦´ïƽºâ״̬£¬ÊµÑéÊý¾ÝÈç±íËùʾ£º
t/s | 0 | 50 | 150 | 250 | 350 |
n(NH3) | 0 | 0.36 | 0.48 | 0.50 | 0.50 |
0~50sÄÚµÄƽ¾ù·´Ó¦ËÙÂÊv(N2)=__________¡£
(3)ÒÑÖª£º¼üÄÜÖ¸ÔÚ±ê×¼×´¿öÏ£¬½«1molÆø̬·Ö×ÓAB(g)½âÀëΪÆø̬Ô×ÓA(g)¡¢B(g)ËùÐèµÄÄÜÁ¿£¬Ó÷ûºÅE±íʾ£¬µ¥Î»ÎªkJ/mol¡£H-HµÄ¼üÄÜΪ436kJ/mol£¬N-HµÄ¼üÄÜΪ391kJ/mol£¬Éú³É1mol NH3¹ý³ÌÖзųö46kJµÄÈÈÁ¿¡£ÔòN¡ÔNµÄ¼üÄÜΪ_________kJ/mol¡£