ÌâÄ¿ÄÚÈÝ

£¨15·Ö£©ÖÐѧ»¯Ñ§Öм¸ÖÖ³£¼ûÎïÖʵÄת»¯¹ØϵÈçͼËùʾ£¬ÇÒÒÑÖª½«FµÄ±¥ºÍÈÜÒºµÎÈë·ÐË®ÖУ¬Öó·Ð¿ÉµÃµ½ÒÔHΪ·ÖÉ¢ÖʵĺìºÖÉ«½ºÌå¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©ºìºÖÉ«½ºÌåÖÐHÁ£×ÓµÄÖ±¾¶´óС·¶Î§                                  £»

£¨2£©Ð´³öDµÄÒ»ÖÖ¹¤ÒµÓÃ;£º                                            £»

£¨3£©¢Ùд³öH2O2µÄµç×Óʽ£º                                    £»

¢Úд³öB¡úGµÄÀë×Ó·½³Ìʽ                                 £»

£¨4£©ÈôA¡¢BÇ¡ºÃÍêÈ«·´Ó¦£¬½«²úÎïCÓë×ãÁ¿ÑÎËá·´Ó¦µÃµ½a molÆøÌ壬ÁíÈ¡µÈÖÊÁ¿BÓë×ãÁ¿ÑÎËá·´Ó¦µÃµ½b molÆøÌ壬a:b=5:7£¬ÔòAµÄ»¯Ñ§Ê½Îª                 £»

£¨5£©ÓÃʯī×÷µç¼«£¬µç½âG¼ÓÈë¹ýÁ¿ÑÎËáºóµÄÈÜÒº£¨ÈçÓÒͼ£©£¬Á½¼«²úÉúÆø ÅÝ¡£³ÖÐøµç½âÒ»¶Îʱ¼ä£¬ÔÚX¼«¸½½üµÄÈÜÒºÖл¹¿É¹Û²ìµ½µÄÏÖÏó ÊÇ                                 £¬½âÊÍ´ËÏÖÏóµÄÀë×Ó·½³ÌʽÊÇ                                     ¡£

¶Ï¿ªµçÔ´£¬½«µç½âºóµÄÈÜÒºµ¹ÈëÉÕ±­Öгä·Ö½Á°è£¬ÏÖÏóÊÇ                   £¬Ô­ÒòÊÇ                                    ¡£

 

£¨15·Ö£©

£¨1£©1nm ~ 100nm £¨1·Ö£©

£¨2£©µç½âÒ±Á¶ÂÁ¡¢Ä͸ßβÄÁϵȣ¨ÆäËûºÏÀí´ð°¸Ò²¿É£©£¨1·Ö£©

£¨3£© ¢Ù   £»£¨2·Ö£©¢Ú2Al+2OH-+2H2O=2AlO2-+3H2¡ü£¨2·Ö£©

£¨4£©Fe5O7£»£¨2·Ö£©

£¨5£©ÏȳöÏÖ°×É«»ë×Ç£¬ºóÓÖ±ä³ÎÇå £¨2·Ö£©  Al3++3OH-=3Al(OH)3¡ý£¬Al(OH)3+ OH-= AlO2-+2H2O£¨¸÷1·Ö£©³öÏÖ°×É«³Áµí £¨1·Ö£©   Ñô¼«ÇøµÄAl3+ÓëÒõ¼«ÇøÉú³ÉµÄAlO2-Ç¡ºÃ·´Ó¦Éú³ÉAl(OH)3£¨»òÕß´ð¡°¸ù¾Ý×Ü·´Ó¦£º2AlCl3+ 6H2O 2Al(OH)3+3H2¡ü+3Cl2¡ü£¬×îºóÇ¡ºÃÉú³ÉAl(OH)3³Áµí¡£¡±ÒàµÃ·Ö£©£¨2·Ö£©

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø