ÌâÄ¿ÄÚÈÝ

ÔÚÈçͼÓÃʯī×÷µç¼«µÄµç½â³ØÖУ¬·ÅÈë500mLº¬Ò»ÖÖÈÜÖʵÄijÀ¶É«ÁòËáÑÎÈÜÒº½øÐеç½â£¬¹Û²ìµ½Aµç¼«±íÃæÓкìÉ«µÄ¹Ì̬ÎïÖÊÉú³É£¬Bµç¼«ÓÐÎÞÉ«ÆøÌåÉú³É¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Çëд³öB¼«°åµÄÃû³Æ£º             µç¼«·´Ó¦Ê½           

д³öµç½âʱ·´Ó¦µÄ×ÜÀë×Ó·½³Ìʽ                          

£¨2£©Èôµ±ÈÜÒºÖеÄÔ­ÓÐÈÜÖÊÍêÈ«µç½âºó£¬Í£Ö¹µç½â£¬È¡³öAµç¼«£¬Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿¡¢µç¼«ÔöÖØ1.6g¡£µç½âºóÈÜÒºµÄpHΪ          £»ÒªÊ¹µç½âºóÈÜÒº»Ö¸´µ½µç½âÇ°µÄ״̬£¬ÔòÐè¼ÓÈë        £¬ÆäÖÊÁ¿Îª         g¡££¨¼ÙÉèµç½âÇ°ºóÈÜÒºµÄÌå»ý²»±ä£©

£¨3£©ÈôÔ­ÈÜҺΪ1L  K2SO4¡¢CuSO4µÄ»ìºÏÈÜÒº£¬ÇÒc£¨SO42-£©= 2.0mol/L £»ÈçͼװÖõç½â£¬µ±Á½¼«¶¼ÊÕ¼¯µ½22.4LÆøÌ壨±ê×¼×´¿ö£©Ê±£¬Í£Ö¹µç½â¡£

ÔòÔ­ÈÜÒºÖеÄc(K+)£½                              

 

£¨1£©Ñô¼«£¨2·Ö£©4OH-- 4e-=2H2O+O2¡ü£¨2·Ö£©¡¢

 


            2Cu2+ +2H2O  =  2Cu +O2 ¡ü+ 4H+£¨2·Ö£©

£¨2£©PH=1£¨2·Ö£©  CuO £¨2·Ö£©; 2¿Ë£¨2·Ö£©   £¨»òCuCO3  3.1 £©

 

£¨3£© c£¨K+£©=2mol/L    £¨3·Ö£©

½âÎö:

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø