ÌâÄ¿ÄÚÈÝ
ÒÑÖªHAºÍHB¶¼ÊÇÈõËᣬÇÒ³£ÎÂÏÂÏàͬŨ¶ÈµÄÁ½ÖÖËáÈÜÒºÖУ¬HAÈÜÒºÖеÄÇâÑõ¸ùµÄŨ¶È´óÓÚHBÈÜÒº¡£ÏÂÁÐÐðÊö²»ÕýÈ·µÄÊÇ
A£®0.1 mol?L¡ª1HAÈÜÒºÖУºc(H£«)¡ª c(OH£)£½c(A£)
B£®½«pH=3µÄHBÓëpH£½11µÄÇâÑõ»¯ÄÆÈÜÒºµÈÌå»ý»ìºÏºóËùµÃÈÜÒºÏÔËáÐÔ
C£®0.2 mol¡¤L£1HBÈÜÒºÓë0.1 mol¡¤L£1 NaOHÈÜÒºµÈÌå»ý»ìºÏ£º2c(H£«)£2c(OH£)£½c(B¡ª)£c(HB)
D£®ÎïÖʵÄÁ¿Å¨¶È¾ùΪ0.01mol?L¡ª1µÄNaAºÍNaBµÄ»ìºÏÈÜÒºÖУºc(OH¡ª)> c(HB)> c(HA)>c(H+)
A£®0.1 mol?L¡ª1HAÈÜÒºÖУºc(H£«)¡ª c(OH£)£½c(A£)
B£®½«pH=3µÄHBÓëpH£½11µÄÇâÑõ»¯ÄÆÈÜÒºµÈÌå»ý»ìºÏºóËùµÃÈÜÒºÏÔËáÐÔ
C£®0.2 mol¡¤L£1HBÈÜÒºÓë0.1 mol¡¤L£1 NaOHÈÜÒºµÈÌå»ý»ìºÏ£º2c(H£«)£2c(OH£)£½c(B¡ª)£c(HB)
D£®ÎïÖʵÄÁ¿Å¨¶È¾ùΪ0.01mol?L¡ª1µÄNaAºÍNaBµÄ»ìºÏÈÜÒºÖУºc(OH¡ª)> c(HB)> c(HA)>c(H+)
D
³£ÎÂÏÂÏàͬŨ¶ÈµÄÁ½ÖÖËáÈÜÒºÖУ¬HAÈÜÒºÖеÄÇâÑõ¸ùµÄŨ¶È´óÓÚHBÈÜÒº£¬Õâ˵Ã÷HAµÄËáÐÔСÓÚHBµÄËáÐÔ£¬Òò´ËHAµÄµçÀë³Ì¶ÈСÓÚHBµÄ£¬Òò´ËNaAµÄË®½â³Ì¶È´óÓÚNaBµÄË®½â³Ì¶È£¬µ«ÓÉÓÚË®½â³Ì¶È¶¼ÊǺÜСµÄ£¬ËùÒÔÑ¡ÏîDÓ¦¸ÃÊÇc(OH¡ª)> c(HA)>c(HB)> c(H+)£¬D²»ÕýÈ·£¬ÆäÓ඼ÊÇÕýÈ·µÄ£¬´ð°¸Ñ¡D¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿