ÌâÄ¿ÄÚÈÝ
£Û»¯Ñ§¡ªÑ¡ÐÞ»¯Ñ§Óë¼¼Êõ£Ý
ͨ³£Çé¿öÏ£¬µ±¿ÕÆøÖÐCO2µÄÌå»ý·ÖÊý³¬¹ý0£®050£¥Ê±£¬»áÒýÆðÃ÷ÏÔµÄÎÂÊÒЧӦ¡£Îª¼õСºÍÏû³ýCO2¶Ô»·¾³µÄÓ°Ï죬¸÷¹ú¶¼ÔÚÏÞÖÆCO2µÄÅÅÁ¿£¬Í¬Ê±Ò²¼ÓÇ¿¶ÔCO2´´ÐÂÀûÓõÄÑо¿¡£
£¨1£©Ä¿Ç°£¬ÍƹãÓó¬ÁÙ½çCO2(½éÓÚÆøÌ¬ºÍҺ̬֮ÎÊ)´úÌæ·úÀû°º×÷ÖÂÀä¼Á£¬ÕâÒ»×ö·¨¶Ô»·¾³µÄ»ý¼«ÒâÒåÊÇ___________________¡£
£¨2£©¿ÆÑ§¼ÒΪÌáÈ¡¿ÕÆøÖеÄCO2£¬°Ñ¿ÕÆø´µÈë̼Ëá¼ØÈÜÒº£¬È»ºóÔÙ°ÑCO2´ÓÈÜÒºÖÐÌáÈ¡³öÀ´£¬¾»¯Ñ§·´Ó¦Ê¹Ö®±äΪ¿ÉÔÙÉúȼÁϼ״¼¡£Á÷³ÌÈçÏ£º
![]()
¢Ù·Ö½â³ØÖз´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º_____________________________¡£
¢ÚºÏ³ÉËþÖУ¬ÈôÓÐ4.4g CO2Óë×ãÁ¿H2Ç¡ºÃ·´Ó¦Éú³ÉÆøÌ¬²úÎ·Å³ö4.947kJµÄÈÈÁ¿£¬Ð´³ö¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º________________________¡£
£¨3£©Ä³Í¬Ñ§ÄâÓóÁµí·¨²â¶¨¿ÕÆøÖÐCO2µÄÌå»ý·ÖÊý£¬Ëû²éµÃCaCO3¡¢BaCO3µÄÈܶȻýK(sp)·Ö±ðΪ4£®96¡Á10-9¡¢2£®58¡Á10-9¡£Ëû×îºÃ½«¿ÕÆøÍ¨Èë×ãÁ¿µÄ__________ÈÜÒº£¬ÊµÑéʱ³ý²â¶¨Î¶ȡ¢Ñ¹Ç¿ºÍ¿ÕÆøµÄÌå»ýÍ⣬»¹ÐèÒª²â¶¨_____________¡£
£¨1£©±£»¤³ôÑõ²ã(3·Ö)
£¨2£©¢Ù2KHCO3
K2CO3+CO2¡ü+H2O(3·Ö)
¢ÚCO2(g)+3H2(g)£½CH3OH(g)+H2O(g)£»¡÷H£½-49.47kJ£¯mol(3·Ö)
£¨3£©Ba(OH)2(»òNaOHºÍBaCl2»ìºÏÈÜÒº£©(3·Ö) Éú³É³ÁµíµÄÖÊÁ¿(3·Ö)
½âÎö:
ÏÂͼÊÇij¹¤³§¶Ôº£Ë®×ÊÔ´½øÐÐ×ÛºÏÀûÓõÄʾÒâͼ£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÇëÁоÙÒ»ÖÖº£Ë®µ»¯µÄ·½·¨
£¨2£©¹¤ÒµÉϳ£ÓÃÀë×Ó½»»»Ä¤µç½â²ÛÉú²úNaOH£¬µç½â¹ý³ÌÖдóÁ¿Í¨¹ýÀë×Ó½»»»Ä¤µÄÀë×ÓÊÇ
£¨3£©ºîÊÏÖÆ¼î·¨ÖÐÊ×ÏÈÏò±¥ºÍʳÑÎË®ÖÐͨÈëCO2ºÍNH3ÖÆµÃNaHCO3£¬ÏÈͨÈë
£¨Ìѧʽ£©£¬ÀíÓÉÊÇ
£¨4£©Ã¾ÊÇÒ»ÖÖÓÃ;ºÜ¹ã·ºµÄ½ðÊô²ÄÁÏ£¬Ä¿Ç°ÊÀ½çÉÏ60%µÄþ´Óº£Ë®ÖÐÌáÈ¡£®ÒÑÖªÓйØÎïÖʵÄÈ۷еãÊý¾ÝÈçÏ£º
| MgO | MgCl2 | |
| ÈÛµã/¡æ | 2852 | 714 |
| ·Ðµã/¡æ | 3600 | 1412 |