ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿µâ»¯Çâ³£ÓÃÓÚÖƱ¸µâµÄ»¯ºÏÎïºÍÓÃ×÷Óлú·´Ó¦µÄ»¹Ô¼Á¡£µâ»¯Çâ²»Îȶ¨£¬Ò׷ֽ⣬µâ»¯Ç⼫Ò×ÈÜÓÚË®£¬ÆäË®ÈÜÒº³ÆΪÇâµâËᣬÇâµâËáÊÇÇ¿ËᣬÓнÏÇ¿µÄ»¹ÔÐÔ¡£
(1)ÇâµâËáÈôÔÚ¿ÕÆøÖг¤ÆÚ·ÅÖã¬ÈÜÒº»á±ä³É»ÆÉ«£¬ÆäÔÒòÊÇ___£¨Óû¯Ñ§·½³ÌʽÀ´±íʾ£©¡£
(2)ʵÑéÊÒÖг£ÓøÉÔïµÄºìÁ׺͵âÏ໥½Ó´¥£¬¼ÓÉÙÁ¿Ë®Î¢ÈÈ£¬¼´¿ÉÉú³Éµâ»¯ÇâºÍÑÇÁ×ËᣨH3PO3£©£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ___¡£
(3)ÇâÆøºÍµâÕôÆøÄÜÖ±½Ó·´Ó¦Éú³Éµâ»¯Ç⣬H2(g)£«I2(g)2HI(g) ¦¤H£¼0¡£T¡æʱ£¬Ïò1LºãÈÝÃܱÕÈÝÆ÷ÖгäÈë0.2molH2ºÍ0.2molI2(g)£¬5minʱ·´Ó¦´ïµ½Æ½ºâ£¬H2¡¢I2(g)ºÍHIµÄÎïÖʵÄÁ¿Å¨¶È(c)Ëæʱ¼ä(t)±ä»¯µÄÇúÏßÈçͼlËùʾ£º
¢Ù0¡«5minÄÚ£¬ÒÔHI±íʾµÄ¸Ã·´Ó¦ËÙÂÊv(HI)=___¡£
¢ÚT¡æʱ£¬¸Ã·´Ó¦µÄƽºâ³£ÊýK=___¡£
¢Û6minʱ£¬¸Ä±äµÄÍâ½çÌõ¼þΪ___¡£
¢Ü10minʱ£¬±£³ÖÆäËûÌõ¼þ²»±ä£¬ÔÙÏòÈÝÆ÷ÖгäÈë0.1molH2¡¢0.1molI2(g)¡¢0.2molHI(g)£¬12minʱ´ïµ½ÐÂƽºâ¡£ÔÚͼ2Öл³ö10¡«12min£¬H2ºÍHIµÄŨ¶È±ä»¯ÇúÏß___£¨ÇúÏßÉϱêÃ÷H2ºÍHI£©£»0¡«5minºÍ0¡«2minʱ¼ä¶Î£¬H2µÄת»¯ÂÊ·Ö±ðÓæÁ1¡¢¦Á2±íʾ£¬Ôò¦Ál___¦Á2£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°=¡±£©¡£
¡¾´ð°¸¡¿4HI£«O2=2H2O£«2I2 2P£«3I2£«6H2O=2H3PO3£«6HI 0.064mol¡¤L-1¡¤min-1 64 ½µÎ £¼
¡¾½âÎö¡¿
(1)ÇâµâËá¾ßÓнÏÇ¿µÄ»¹ÔÐÔ£¬Â¶ÖÃÔÚ¿ÕÆøÖлᱻ¿ÕÆøÖеÄÑõÆøÑõ»¯Îªµâµ¥ÖÊ£¬´Ó¶øʹÈÜÒº±ä»Æ£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º4HI£«O2=2H2O£«2I2¡£´ð°¸Îª£º4HI£«O2=2H2O£«2I2£»
(2)¸ù¾ÝÌâÒâºÍÑõ»¯»¹Ô·´Ó¦·½³ÌʽµÄÅäƽÔÔò£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º2P£«3I2£«6H2O=2H3PO3£«6HI¡£´ð°¸Îª£º2P£«3I2£«6H2O=2H3PO3£«6HI£»
(3)¢ÙÓÉͼÏñ¿ÉÖª£¬0¡«5minÄÚ£¬¦¤c(HI)=0.32mol¡¤L-1£¬v(HI)= =0.064mol¡¤L-1¡¤min-1¡£´ð°¸Îª£º0.064mol¡¤L-1¡¤min-1£»
¢ÚT¡æʱ£¬¸Ã·´Ó¦ÔÚ5minʱ´ïµ½Æ½ºâ£¬ÓÉͼÏñ¿ÉÖª£¬Æ½ºâʱ£¬c(HI)=0.32mol¡¤L-1£¬c(H2)=c(I2)=0.04mol¡¤L-1£¬ÔòT¡æʱ¸Ã·´Ó¦µÄƽºâ³£ÊýK===64¡£´ð°¸Îª£º64£»
¢Û6minʱ£¬·´Ó¦Îï¡¢²úÎïŨ¶È˲¼ä²»±ä£¬µ«Ëæ×Å·´Ó¦µÄ½øÐУ¬·´Ó¦ÎïŨ¶È¼õÉÙ£¬Éú³ÉÎïŨ¶ÈÔö¼Ó£¬ËµÃ÷ƽºâÕýÏòÒƶ¯£¬ÓÉÓÚ¸ÃÕý·´Ó¦Îª·ÅÈÈ·´Ó¦£¬¹Ê6minʱ¸Ä±äµÄÌõ¼þÊǽµµÍζȡ£´ð°¸Îª£º½µÎ£»
¢Ü10minʱ£¬ÒѴﵽеÄƽºâ£¬´Ëʱc(H2)=c(I2)=0.02mol¡¤L-1£¬c(HI)=0.36mol¡¤L-1£¬ÔòK===324¡£±£³ÖÆäËûÌõ¼þ²»±ä£¬ÔÙÏòÈÝÆ÷ÖгäÈë0.1molH2¡¢0.1molI2(g)¡¢0.2molHI£¬´Ëʱ£¬c(H2)=c(I2)=0.12mol¡¤L-1£¬c(HI)=0.56mol¡¤L-1£¬Qc===£¼K=324£¬Æ½ºâÕýÏòÒƶ¯£¬c(H2)ºÍc(I2)¼õС£¬c(HI)Ôö´ó£¬12minʱ£¬·´Ó¦´ïµ½ÐÂƽºâ£¬Éè10min¡«12min¹ý³ÌÖЦ¤c(H2)=¦¤c(I2)=xmol¡¤L-1£¬Ôò12minʱ£¬c(H2)=c(I2)=(0.12£x)mol¡¤L-1£¬c(HI)=(0.56£«2x)mol¡¤L-1£¬ÔòK===324£¬½âµÃ£ºx=0.08£¬¹Ê12minʱ£¬c(H2)=c(I2)=(0.12£0.08)mol¡¤L-1=0.04mol¡¤L-1£¬c(HI)=(0.56£«0.16)mol¡¤L-1=0.72mol¡¤L-1£¬¹Ê10¡«12min£¬H2ºÍHIµÄŨ¶È±ä»¯ÇúÏßÈçͼËùʾ¡£
ÓÉͼʾ¿ÉÖª£¬0¡«5minʱ£¬H2µÄת»¯ÂʦÁ1=¡Á100%=80%£¬0¡«12minʱ£¬¹²³äÈëµÄn(H2)=0.3mol£¬12minʱ£¬Ê£Óàn(H2)=0.04mol¡¤L-1¡Á1L=0.04mol£¬Ôò0¡«12minʱ£¬H2µÄת»¯ÂʦÁ2=¡Á100%¡Ö86.7%£¬¹Ê¦Á1£¼¦Á2¡£´ð°¸Îª£º£»£¼¡£
¡¾ÌâÄ¿¡¿Ï±íÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£¬¶ÔÓÚ±íÖÐÔªËآ١«¢à£¬Ìî¿Õ»Ø´ð£º
×å ÖÜÆÚ | ¢ñA | ¢òA | ¢óA | ¢ôA | ¢õA | ¢öA | ¢õ¢òA | 0 |
¶þ | ¢Ù | ¢Ú | ¢Û | ¢Ü | ||||
Èý | ¢Ý | ¢Þ | ¢ß | ¢à |
(1)µØ¿ÇÖк¬Á¿×î¶àµÄÔªËØÊÇ______£¬·Ç½ðÊôÐÔ×îÇ¿µÄÔªËØÊÇ______¡£
(2)д³ö¢ÙµÄ×î¼òµ¥µÄÆø̬Ç⻯ÎïµÄµç×Óʽ______¡£
(3)ÔÚµÚÈýÖÜÆÚÖ÷×åÔªËØÖУ¬µ¥ÖÊÑõ»¯ÐÔ×îÇ¿µÄÊÇ_____£¬ÄÜÐγɵĶþԪǿËáÊÇ________¡£
(4)д³ö¢ÚµÄÆø̬Ç⻯ÎïÓë¢ÚµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯Îï·´Ó¦µÄ»¯Ñ§·½³Ìʽ_____¡£
¡¾ÌâÄ¿¡¿¸ß´¿ÁòËáÃÌ×÷ΪºÏ³ÉÄøîÜÃÌÈýÔªÕý¼«²ÄÁϵÄÔÁÏ£¬¹¤ÒµÉÏ¿ÉÓÉÌìÈ»¶þÑõ»¯ÃÌ·ÛÓëÁò»¯Ã̿󣨻¹º¬Fe¡¢Al¡¢Mg¡¢Zn¡¢Ni¡¢SiµÈÔªËØ£©ÖƱ¸£¬¹¤ÒÕÈçÏÂͼËùʾ¡£»Ø´ðÏÂÁÐÎÊÌ⣺
Ïà¹Ø½ðÊôÀë×Ó[c0(Mn+)=0.1 mol¡¤L1]ÐγÉÇâÑõ»¯Îï³ÁµíµÄpH·¶Î§ÈçÏ£º
½ðÊôÀë×Ó | Mn2+ | Fe2+ | Fe3+ | Al3+ | Mg2+ | Zn2+ | Ni2+ |
¿ªÊ¼³ÁµíµÄpH | 8.1 | 6.3 | 1.5 | 3.4 | 8.9 | 6.2 | 6.9 |
³ÁµíÍêÈ«µÄpH | 10.1 | 8.3 | 2.8 | 4.7 | 10.9 | 8.2 | 8.9 |
£¨1£©¡°ÂËÔü1¡±º¬ÓÐSºÍ__________________________£»Ð´³ö¡°Èܽþ¡±ÖжþÑõ»¯ÃÌÓëÁò»¯ÃÌ·´Ó¦µÄ»¯Ñ§·½³Ìʽ_______________________________________¡£
£¨2£©¡°Ñõ»¯¡±ÖÐÌí¼ÓÊÊÁ¿µÄMnO2µÄ×÷ÓÃÊǽ«________________________£¬¼ìÑéÉú³ÉÀë×ÓÊÔ¼Á___________¡£
£¨3£©¡°µ÷pH¡±³ýÌúºÍÂÁ£¬ÈÜÒºµÄpH·¶Î§Ó¦µ÷½ÚΪ_______¡«6Ö®¼ä£¬³ýÂÁµÄÀë×Ó·´Ó¦·½³ÌʽÊÇ__________¡£
£¨4£©¡°³ýÔÓ1¡±µÄÄ¿µÄÊdzýÈ¥Zn2+ºÍNi2+£¬¡°ÂËÔü3¡±µÄÖ÷Òª³É·ÖÊÇ______________¡£
£¨5£©Ñõ»¯ÖгýÁËÌí¼ÓÊÊÁ¿MnO2»¹¿ÉÒÔÓÃH2O2À´Ñõ»¯£¬Ð´³ö¸ÃÀë×Ó·´Ó¦_______________¡£
£¨6£©Ð´³ö¡°³ÁÃÌ¡±µÄÀë×Ó·½³Ìʽ_______________________________________¡£
£¨7£©²ã×´ÄøîÜÃÌÈýÔª²ÄÁÏ¿É×÷Ϊï®Àë×Óµç³ØÕý¼«²ÄÁÏ£¬Æ仯ѧʽΪLiNixCoyMnzO2£¬ÆäÖÐNi¡¢Co¡¢MnµÄ»¯ºÏ¼Û·Ö±ðΪ+2¡¢+3¡¢+4¡£µ±x=y=ʱ£¬z=___________¡£
£¨8£©Ð´³öFe2+ºÍHNO3µÄÀë×Ó·´Ó¦__________¡£