ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÒøÖÆÆ÷Ãó±íÃæÈÕ¾ÃÒòÉú³ÉAg2S¶ø±äºÚ£¬¿É½øÐÐÈçÏ´¦Àí£º½«±íÃæ·¢ºÚµÄÒøÆ÷½þÈëÊ¢ÓÐʳÑÎË®µÄÂÁÖÊÈÝÆ÷ÖÐ(Èçͼ)£¬Ò»¶Îʱ¼äºóºÚÉ«ÍÊÈ¥¡£»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÒøÖÊÆ÷ÃóÈվñíÃæ»áÖð½¥±äºÚ£¬ÕâÊÇÉú³ÉÁËAg2SµÄÔµ¹Ê£¬¸ÃÏÖÏóÊôÓÚ__________¸¯Ê´(Ìî¡°»¯Ñ§¡±»ò¡°µç»¯Ñ§¡±)¡£
(2)ÂÁÖÊÈÝÆ÷×÷Ϊ__________¼«£¬ÒøÆ÷µÄµç¼«·´Ó¦Ê½Îª____________¡£
(3)´¦Àí¹ý³ÌÖÐ×Ü·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________¡£
(4)Èô½«ÂÁÖÊÈÝÆ÷ÖеÄʳÑÎË®ÓÃŨÏõËá´úÌ棬ÔòÂÁÖÊÈÝÆ÷¼«µÄµç¼«·´Ó¦Ê½Îª____________¡£
¡¾´ð°¸¡¿»¯Ñ§ ¸º Ag2S+2e-=2Ag+S2- 2Al+3Ag2S+6H2O=2Al(OH)3¡ý+6Ag+3H2S¡ü NO3-+e-+2H+=NO2¡ü+H2O
¡¾½âÎö¡¿
(1)AgºÍÁò»¯ÇâÖ±½Ó·´Ó¦Éú³ÉAg2S£¬ÊôÓÚ»¯Ñ§¸¯Ê´£»
(2)ÂÁ¡¢ÒøÆ÷ºÍÂÈ»¯ÄÆÈÜÒº¹¹³ÉÔµç³Ø£¬ÓÉÓÚÂÁµÄ»îÆÃÐÔ´óÓÚÒø£¬¹ÊÂÁΪ¸º¼«£¬ÒøÆ÷×÷Õý¼«£¬Õý¼«ÉÏÒøÀë×ӵõç×Ó·¢Éú»¹Ô·´Ó¦£¬Õý¼«µç¼«·´Ó¦Ê½ÎªAg2S+2e-=2Ag+S2-£»
(3)¸º¼«Alʧȥµç×ÓÉú³ÉÂÁÀë×Ó£¬µç¼«·´Ó¦Ê½Îª£ºAl-3e-=Al3+£¬Õý¼«·¢Éú»¹Ô·´Ó¦£¬Ag2S»ñµÃµç×ÓÉú³ÉAgÓëÁòÀë×Ó£¬µç¼«·´Ó¦Ê½Îª£º3Ag2S+6e-=6Ag+3S2-£¬ÂÁÀë×ÓÓëÁòÀë×Ó·¢ÉúË®½â·´Ó¦·´Ó¦Ê½Éú³ÉÇâÑõ»¯ÂÁÓëÁò»¯ÇâÆøÌ壬ËùÒÔ×ܵķ´Ó¦·½³ÌʽΪ£º2Al+3Ag2S+6H2O£½2Al(OH)3¡ý+6Ag+3H2S¡ü£¬
(4)³£ÎÂÏ£¬ÂÁÔÚŨÏõËáÖжۻ¯£¬Èô½«ÂÁÖÊÈÝÆ÷ÖеÄʳÑÎË®ÓÃŨÏõËá´úÌ棬ÔòÂÁΪÕý¼«£¬ÂÁÖÊÈÝÆ÷¼«µÄµç¼«·´Ó¦Ê½ÎªNO3-+e-+2H+=NO2¡ü+H2O¡£