ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿Í­µÄÏà¹Ø»¯ºÏÎïÔÚÉú²úÉú»îÖоßÓÐÖØÒªµÄ×÷Ó᣻شðÏÂÁÐÎÊÌ⣺

(1)Í­ÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ______£¬»ù̬ͭԭ×ÓÖУ¬ºËÍâµç×ÓÕ¼¾Ý×î¸ßÄܲãµÄ·ûºÅÊÇ______£¬Õ¼¾Ý¸Ã×î¸ßÄܲãµÄµç×ÓÊýΪ__________¡£

(2)ÔÚÒ»¶¨Ìõ¼þÏ£¬½ðÊôÏ໥»¯ºÏÐγɵĻ¯ºÏÎï³ÆΪ½ðÊô»¥»¯ÎÈçCu9Al4¡¢Cu5Zn8µÈ¡£Ä³½ðÊô»¥»¯Îï¾ßÓÐ×Ô·¶ÐÔ£¬Ô­×ÓÔÚÈýά¿Õ¼äÀï³ÊÖÜÆÚÐÔÓÐÐòÅÅÁУ¬¸Ã½ðÊô»¥»¯ÎïÊôÓÚ__________(Ìî¡°¾§Ì塱»ò¡°·Ç¾§Ì塱)¡£

(3)Í­ÄÜÓëÀà±ËØ[(SCN)2]·´Ó¦Éú³ÉCu(SCN)2£¬1mol(SCN)2·Ö×ÓÖк¬ÓЦҼüµÄÊýĿΪ_____________¡£ÁòÇèËᣨH-S-C¡ÔN£©ºÍÒìÁòÇèËᣨH-N=C=S£©£¬ÕâÁ½ÖÖËáÖзеã½Ï¸ßµÄÊÇÒìÁòÇèËᣨH-N=C=S£©¡£ÀíÂÛÉÏÇ°Õ߷еãµÍÓÚºóÕߣ¬ÆäÔ­ÒòÊÇ____________________________¡£

(4)Í­¾§ÌåÖÐÍ­Ô­×ӵĶѻý·½Ê½ÎªÃæÐÄÁ¢·½¶Ñ»ý£¬Ã¿¸öÍ­Ô­×ÓÖÜΧ¾àÀë×î½üµÄÍ­Ô­×Ó¸öÊýΪ________¡£

(5)Í­Óë½ðÐγɵĽðÊô»¥»¯ÎïµÄ¾§°û½á¹¹ÈçͼËùʾ£¬Æ侧°û±ß³¤Îªa nm£¬¸Ã½ðÊô»¥»¯ÎïµÄÃܶÈΪ____Óú¬a¡¢NAµÄ´úÊýʽ±íʾ)gcm-3¡£

¡¾´ð°¸¡¿µÚËÄÖÜÆÚµÚIB×å N 1 ¾§Ìå 5NA ÒìÁòÇèËá·Ö×Ó¼ä¿ÉÐγÉÇâ¼ü£¬¶øÁòÇèËá·Ö×Ӽ䲻ÄÜÐγÉÇâ¼ü 12

¡¾½âÎö¡¿

£¨1£©Í­Ô­×Ӻ˵çºÉÊýΪ29£¬ºËµçµç×ÓÅŲ¼Îª1s22s22p63s23p64s13d10£¬ÔÚÖÜÆÚ±íÖеÄλÖÃÊǵÚËÄÖÜÆÚIB×壻»ù̬ͭԭ×ÓÖУ¬ºËÍâµç×ÓÕ¼¾Ý×î¸ßÄܲãµÄÊÇN²ã£»Õ¼¾Ý¸Ã×î¸ßÄܲãµÄµç×ÓÊýΪ1£»ÕýÈ·´ð°¸£ºµÚËÄÖÜÆÚIB×壻N£»1¡£

£¨2£©¾§ÌåÖÐÔ­×Ó³ÊÖÜÆÚÐÔÓÐÐòÅÅÁУ¬ÓÐ×Ô·¶ÐÔ£¬¶ø·Ç¾§ÌåÖÐÔ­×ÓÅÅÁÐÏà¶ÔÎÞÐò£¬ÎÞ×Ô·¶ÐÔ£¬ÌâÊö½ðÊô»¥»¯ÎïÊôÓÚ¾§Ì壻ÕýÈ·´ð°¸£º¾§Ìå¡£

£¨3£©Àà±ËØ(SCN)2µÄ½á¹¹Ê½ÎªN¡ÔC¡ªS¡ªS¡ªC¡ÔN£¬1mol(SCN)2Öк¬¦Ò¼üµÄÊýĿΪ5NA¡£ÒìÁòÇèËá(H¡ªN===C===S)·Ö×ÓÖÐNÔ­×ÓÉÏÁ¬½ÓÓÐHÔ­×Ó£¬·Ö×Ó¼äÄÜÐγÉÇâ¼ü£¬¹Ê·Ðµã¸ß£»ÕýÈ·´ð°¸;5NA(»ò5¡Á6.02¡Á1023)£»ÒìÁòÇèËá·Ö×Ó¼ä¿ÉÐγÉÇâ¼ü£¬¶øÁòÇèËá²»ÄÜ¡£

£¨4£©ÔÚ½ðÊô¾§ÌåµÄ×îÃܶѻýÖУ¬¶ÔÓÚÿ¸öÔ­×ÓÀ´Ëµ£¬ÔÚÆäÖÜΧµÄÔ­×ÓÓÐÓë֮ͬһ²ãÉÏÓÐÁù¸öÔ­×ÓºÍÉÏÒ»²ãµÄÈý¸ö¼°ÏÂÒ»²ãµÄÈý¸ö£¬¹Êÿ¸öÔ­×ÓÖÜΧ¶¼ÓÐ12¸öÔ­×ÓÓëÖ®ÏàÁ¬£»Í­¾§ÌåÖÐÍ­Ô­×ӵĶѻý·½Ê½ÎªÃæÐÄÁ¢·½¶Ñ»ý£¬Ã¿¸öÍ­Ô­×ÓÖÜΧ¾àÀë×î½üµÄÍ­Ô­×Ó¸öÊýΪ12£»ÕýÈ·´ð°¸£º12¡£

(5)¸ù¾Ý¾ù̯·¨£¬Í­Óë½ðÐγɵĽðÊô»¥»¯Îᄃ°ûÖÐCuµÄ¸öÊýΪ6¡Á1/2£½3£¬AuµÄ¸öÊýΪ8¡Á1/8£½1£¬¸Ã½ðÊô»¥»¯ÎïµÄ»¯Ñ§Ê½ÎªCu3Au£¬¸Ã½ðÊô»¥»¯ÎïµÄÃܶÈΪ£¨364+1197£©/NAa310-21g¡¤cm-3£½g¡¤cm-3£»ÕýÈ·´ð°¸£º

¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿»¯Ñ§Ð¡×é²ÉÓÃÀàËÆÖÆÒÒËáÒÒõ¥µÄ×°ÖÃ(ÈçÏÂͼ)£¬Óû·¼º´¼ÖƱ¸»·¼ºÏ©¡£

ÒÑÖª£º+H2O

ÃܶÈ

ÈÛµã

·Ðµã

ÈܽâÐÔ

»·¼º´¼

25

161

ÄÜÈÜÓÚË®

»·¼ºÏ©

83

ÄÑÈÜÓÚË®

(1)ÖƱ¸´ÖÆ·

½«12.5mL»·¼º´¼¼ÓÈëÊÔ¹ÜAÖУ¬ÔÙ¼ÓÈë1mLŨÁòËᣬҡÔȺó·ÅÈëËé´ÉƬ(·ÀÖ¹±©·Ð)£¬»ºÂý¼ÓÈÈÖÁ·´Ó¦ÍêÈ«£¬ÔÚÊÔ¹ÜCÄڵõ½»·¼ºÏ©´ÖÆ·¡£

µ¼¹ÜB³ýÁ˵¼ÆøÍ⻹¾ßÓеÄ×÷ÓÃÊÇ______¡£

¢ÚÊÔ¹ÜCÖÃÓÚ±ùˮԡÖеÄÄ¿µÄÊÇ______¡£

(2)ÖƱ¸¾«Æ·

¢Ù»·¼ºÏ©´ÖÆ·Öк¬Óл·¼º´¼ºÍÉÙÁ¿ËáÐÔÔÓÖʵȼÓÈë±¥ºÍʳÑÎË®£¬Õñµ´¡¢¾²Öᢷֲ㣬»·¼ºÏ©ÔÚ______²ã(Ìî¡°ÉÏ¡±»ò¡°Ï¡±)£¬·ÖÒººóÓÃ______(ÌîÈë±àºÅ)Ï´µÓ¡£

A.KMnO4ÈÜҺϡH2SO4 C.Na2CO3ÈÜÒº

¢ÚÔÙ½«»·¼ºÏ©°´ÉÏͼװÖÃÕôÁó£¬ÀäÈ´Ë®´Ó______¿Ú½øÈëÌî¡°g¡±»ò¡°f¡±)£¬ÕôÁóʱҪ¼ÓÈëÉúʯ»Ò£¬ÆäÄ¿µÄÊÇ______¡£

¢ÛÊÕ¼¯²úƷʱ£¬¿ØÖƵÄÎÂÓ¦ÔÚ______×óÓÒ£¬ÊµÑéÖƵõĻ·¼ºÏ©¾«Æ·ÖÊÁ¿µÍÓÚÀíÂÛ²úÁ¿£¬¿ÉÄܵÄÔ­ÒòÊÇ_____¡£

A.ÕôÁóʱ´Ó¿ªÊ¼ÊÕ¼¯²úÆ·

B.»·¼º´¼Êµ¼ÊÓÃÁ¿¶àÁË

C.ÖƱ¸´ÖƷʱ»·¼º´¼Ëæ²úÆ·Ò»ÆðÕô³ö

(3)ÒÔÏÂÇø·Ö»·¼ºÏ©¾«Æ·ºÍ´ÖÆ·µÄ·½·¨£¬ºÏÀíµÄÊÇ______¡£

A.·Ö±ð¼ÓÈëËáÐÔ¸ßÃÌËá¼ØÈÜÒº

B.·Ö±ð¼ÓÈëÓýðÊôÄÆ

C.·Ö±ð²â¶¨·Ðµã

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø