ÌâÄ¿ÄÚÈÝ

£¨12·Ö£©ÏÖÓмס¢ÒÒ¡¢±û¡¢¶¡ËÄÖÖÎïÖÊ£¬ÒÒ¡¢¶¡µÄÑæÉ«·´Ó¦¾ùΪ»ÆÉ«¡£±ûÊÇÒ»ÖÖÇ¿ËáµÄËáʽÑΣ¬½«±û¼ÓÈëBaCl2ÈÜÒºÓв»ÈÜÓÚÑÎËáµÄ°×É«³ÁµíÉú³É£¬¶¡¾§ÌåÔÚ¸ÉÔï¿ÕÆøÖÐÈÝÒ×Öð½¥Ê§È¥½á¾§Ë®±ä³É°×É«·ÛÄ©¡£¶Ô¼×¡¢ÒÒ¡¢±û¡¢¶¡½øÐÐÏÂÁÐʵÑ飬ʵÑé¹ý³ÌºÍ¼Ç¼ÈçÏÂͼËùʾ£¨ÎÞ¹ØÎïÖÊÒÑÂÔÈ¥£©£¬Çë»Ø´ð£º

£¨1£©½«DÈÜÒºÕô¸ÉµÃµ½µÄ¹ÌÌåÊÇ£º¡¡          ¡¡ (д»¯Ñ§Ê½)¡£
£¨2£©CµÄ½á¹¹Ê½ÊÇ¡¡¡¡ ¡¡¡¡¡¡£¬BµÄµç×ÓʽΪ                  ¡£
£¨3£©Ð´³öDÈÜÒºÓë¹ýÁ¿µÄC·´Ó¦µÄÀë×Ó·½³Ìʽ                                  ¡£
£¨4£©µç½âÎìµÄË®ÈÜÒºÒ»¶Îʱ¼äºó£¬ÊÕ¼¯µ½µÄÈýÖÖÆøÌ壬ÆäһΪÎÞÉ«ÆøÌåB£¬ÁíÁ½ÖÖÊǵ¥ÖÊ£¬Ð´³öµç½âÎìÈÜÒºµÄ×Ü·½³Ìʽ£º                            ¡£
£¨5£©ÓÐÈËÉèÏëÔÚÊʵ±´óСµÄ¹ÜµÀÖÐÌî³äÒ»¶¨Á¿µÄ¶¡µÄ¾§Ì壨Ħ¶ûÖÊÁ¿ÔÚ280¡«300Ö®¼ä£©£¬¹ÜµÀ»·ÈÆÔÚÒ»¸ö·¿×ÓµÄÖÜΧ£¬ÕâÑùµÄ·¿×Ó°×ÌìÍíÉÏÊÒÄÚζȿɱ£³ÖÏà¶Ôºã¶¨£¬Çë¼òÊöÆäÔ­Àí£º¡¡¡¡¡¡                                  ¡£
£¨1£©  NaAlO2 £¨2£©      

ͨµç

 
£¨3£©  CO2 +AlO2£­+2H2O==Al(OH)3¡ý+ HCO3£­

£¨4£©  2NH4Cl ="===" H2¡ü+ Cl2¡ü+ 2NH3¡ü
£¨5£©°×ÌìNa2CO3¡¤10H2O·Ö½âÎüÈÈ,£¬ÍíÉÏH2OºÍNa2CO3ÔÙ½áºÏ³É¾§Ìå·ÅÈÈ£¬¿ÉÒÔµ÷½ÚζÈ
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨8·Ö£©Ä³Ñ§Ï°Ð¡×éÓÃÏÂͼװÖòⶨÂÁþºÏ½ðÖÐÂÁµÄÖÊÁ¿·ÖÊýºÍÂÁµÄÏà¶ÔÔ­×ÓÖÊÁ¿.

£¨Ìáʾ£ºÃ¾¡¢ÂÁ¾ùÓëËá·´Ó¦£¬ÂÁ»¹ÄܺͼӦ£º2Al+2NaOH+2H2O=2NaAlO2+3H2¡ü£©
ʵÑéÇ°£¬ÏȽ«ÂÁþºÏ½ðÔÚÏ¡ËáÖнþÅÝƬ¿Ì£¬ÆäÄ¿µÄÊdzýÈ¥ÂÁþºÏ½ð±íÃæµÄÑõ»¯Ä¤¡£
£¨1£©AÖÐÊÔ¼ÁΪ      .
£¨Ìî¡°NaOHÈÜÒº¡±»ò¡°Ï¡ÑÎËᡱ£©
£¨2£©¼ì²éÆøÃÜÐÔ£¬½«Ò©Æ·ºÍË®×°Èë¸÷ÒÇÆ÷ÖУ¬Á¬½ÓºÃ×°Öúó£¬Ðè½øÐеIJÙ×÷»¹ÓУº¢Ù¼Ç¼
CµÄÒºÃæλÖ㻢ڽ«BÖÐÊ£Óà¹ÌÌå¹ýÂË£¬Ï´µÓ£¬¸ÉÔ³ÆÖØ£»¢Û´ýBÖв»ÔÙÓÐÆøÌå²úÉú²¢»Ö¸´ÖÁÊÒΣ»¢ÜÓÉAÏòBÖеμÓ×ãÁ¿ÊÔ¼Á£»¢Ý¼ì²éÆøÃÜÐÔ£»¢Þµ÷ÕûÏð½ºÈí¹ÜʹDºÍCµÄÒºÃæÏàƽ¡£
ÉÏÊö²Ù×÷µÄ˳ÐòÊÇ          £»£¨ÌîÐòºÅ£©
£¨3£©BÖз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ                 .
£¨4£©ÊµÑé¹ý³ÌÖУ¬ÈôδϴµÓ¹ýÂËËùµÃµÄ²»ÈÜÎÔò²âµÃÂÁµÄÖÊÁ¿·ÖÊý½«           .
£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±¡¢¡°²»ÊÜÓ°Ï족£©
£¨5£©ÈôʵÑéÓÃÂÁþºÏ½ðµÄÖÊÁ¿Îªa g,²âµÃÇâÆøÌå»ýΪb ml£¨ÒÑ»»ËãΪ±ê×¼×´¿ö£©£¬BÖÐÊ£Óà¹ÌÌåµÄÖÊÁ¿Îªc g£¬ÔòÂÁµÄÏà¶ÔÔ­×ÓÖÊÁ¿Îª          .£¨Óú¬a¡¢b¡¢cµÄ´úÊýʽ±íʾ£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø