ÌâÄ¿ÄÚÈÝ
Óô¿¼îºÍË«ÑõË®»ìºÏ¿ÉÖÆ×÷ÐÂÐÍÒºÌåÏ´µÓ¼Á(2Na2CO3¡¤3H2O2)£¬Ëü¾ßÓÐɱ¾úÏû¶¾È¥ÓÍÎÛµÄÄÜÁ¦ÇÒ²»»áÎÛȾˮԴ¡£
(1)¼ìÑéÕâÖÖÐÂÐÍÏ´µÓ¼ÁÖнðÊôÑôÀë×ӵIJÙ×÷ºÍÏÖÏóÊÇ_______________________________________¡£
(2)ÕâÖÖÏ´µÓ¼ÁÖеÄË«ÑõË®¿ÉÒÔ½«·ÏË®ÖеÄÇ軯Îïת»¯ÎªÎÞ¶¾ÎïͬʱÉú³ÉNH3£¬Ð´³ö·´Ó¦µÄÀë×Ó·½³Ìʽ£º___________________________________
(3)Èç¹ûÅäÖÆÏ´µÓ¼ÁµÄË®Öк¬ÓÐÌúÀë×Ó£¬²»½ö»áÏ÷ÈõÏ´µÓ¼ÁµÄÈ¥ÎÛÄÜÁ¦£¬ÉõÖÁÍêȫʧȥɱ¾ú×÷Óá£ÊÔ·ÖÎöÆäÖеÄÔÒò(ÓÃÀë×Ó·½³ÌʽºÍ¼òÒªÎÄ×Ö±íÊö)£º__________________________________________________________________
(4)ij»¯Ñ§Ñ§Ï°Ð¡×éΪ¶¨ÐÔ̽¾¿ÌúÀë×Ó¶ÔÕâÖÖÐÂÐÍÏ´µÓ¼ÁµÄ²»Á¼Ó°Ï죬ȡ¸ÃÏ´µÓ¼Á100 mL£¬¼ÓÈë25 gFeCl3¹ÌÌ壬²úÉú´óÁ¿ÎÞÉ«ÎÞζÆøÌ壬ÓÃÖüÆøÆ¿ÊÕ¼¯ÆøÌå¡£ÇëÑ¡ÓÃÏÂÁÐÊÔ¼ÁºÍʵÑéÓÃÆ·Íê³ÉÆøÌå³É·ÖµÄ̽¾¿¹ý³Ì£º0.10 mol¡¤L£1 NaOHÈÜÒº¡¢8.0 mol¡¤L£1 NaOHÈÜÒº¡¢³ÎÇåʯ»ÒË®¡¢0.01 mol¡¤L£1 KMnO4ÈÜÒº¡¢BaCl2Ï¡ÈÜÒº¡¢Æ·ºìÈÜÒº¡¢ÕôÁóË®¡¢Ð¡Ä¾Ìõ¡¢¾Æ¾«µÆ¡¢»ð²ñ¡¢Ï´ÆøÆ¿¡£
¢ÙÌá³ö¼ÙÉ裺¶Ô¸ÃÆøÌå³É·ÖÌá³öºÏÀí¼ÙÉè¡£
¼ÙÉè1£ºÆøÌåÊÇO2£»
¼ÙÉè2£ºÆøÌåÊÇ________________£»
¼ÙÉè3£ºÆøÌåÊÇCO2¡£
¢ÚÉè¼Æ·½°¸£ºÉè¼ÆʵÑé·½°¸Ö¤Ã÷ÄãµÄ¼ÙÉ裬ÔÚϱíÖÐÍê³ÉʵÑé²½Öè¡¢Ô¤ÆÚÏÖÏóÓë½áÂÛ¡£
(1)¼ìÑéÕâÖÖÐÂÐÍÏ´µÓ¼ÁÖнðÊôÑôÀë×ӵIJÙ×÷ºÍÏÖÏóÊÇ_______________________________________¡£
(2)ÕâÖÖÏ´µÓ¼ÁÖеÄË«ÑõË®¿ÉÒÔ½«·ÏË®ÖеÄÇ軯Îïת»¯ÎªÎÞ¶¾ÎïͬʱÉú³ÉNH3£¬Ð´³ö·´Ó¦µÄÀë×Ó·½³Ìʽ£º___________________________________
(3)Èç¹ûÅäÖÆÏ´µÓ¼ÁµÄË®Öк¬ÓÐÌúÀë×Ó£¬²»½ö»áÏ÷ÈõÏ´µÓ¼ÁµÄÈ¥ÎÛÄÜÁ¦£¬ÉõÖÁÍêȫʧȥɱ¾ú×÷Óá£ÊÔ·ÖÎöÆäÖеÄÔÒò(ÓÃÀë×Ó·½³ÌʽºÍ¼òÒªÎÄ×Ö±íÊö)£º__________________________________________________________________
(4)ij»¯Ñ§Ñ§Ï°Ð¡×éΪ¶¨ÐÔ̽¾¿ÌúÀë×Ó¶ÔÕâÖÖÐÂÐÍÏ´µÓ¼ÁµÄ²»Á¼Ó°Ï죬ȡ¸ÃÏ´µÓ¼Á100 mL£¬¼ÓÈë25 gFeCl3¹ÌÌ壬²úÉú´óÁ¿ÎÞÉ«ÎÞζÆøÌ壬ÓÃÖüÆøÆ¿ÊÕ¼¯ÆøÌå¡£ÇëÑ¡ÓÃÏÂÁÐÊÔ¼ÁºÍʵÑéÓÃÆ·Íê³ÉÆøÌå³É·ÖµÄ̽¾¿¹ý³Ì£º0.10 mol¡¤L£1 NaOHÈÜÒº¡¢8.0 mol¡¤L£1 NaOHÈÜÒº¡¢³ÎÇåʯ»ÒË®¡¢0.01 mol¡¤L£1 KMnO4ÈÜÒº¡¢BaCl2Ï¡ÈÜÒº¡¢Æ·ºìÈÜÒº¡¢ÕôÁóË®¡¢Ð¡Ä¾Ìõ¡¢¾Æ¾«µÆ¡¢»ð²ñ¡¢Ï´ÆøÆ¿¡£
¢ÙÌá³ö¼ÙÉ裺¶Ô¸ÃÆøÌå³É·ÖÌá³öºÏÀí¼ÙÉè¡£
¼ÙÉè1£ºÆøÌåÊÇO2£»
¼ÙÉè2£ºÆøÌåÊÇ________________£»
¼ÙÉè3£ºÆøÌåÊÇCO2¡£
¢ÚÉè¼Æ·½°¸£ºÉè¼ÆʵÑé·½°¸Ö¤Ã÷ÄãµÄ¼ÙÉ裬ÔÚϱíÖÐÍê³ÉʵÑé²½Öè¡¢Ô¤ÆÚÏÖÏóÓë½áÂÛ¡£
ʵÑé²½Öè | Ô¤ÆÚÏÖÏóÓë½áÂÛ |
½«ÆøÌåÒÀ´ÎͨÈëÊ¢ÓÐ________¡¢________µÄÏ´ÆøÆ¿ÖУ¬________ | __________________ |
¡¡(1)ÓýྻµÄ²¬Ë¿ÕºÈ¡Ï´µÓ¼ÁÔھƾ«µÆ»ðÑæÉÏ×ÆÉÕ£¬»ðÑæ³Ê»ÆÉ«(ºÏÀí¼´¿É)
(2)H2O2£«CN££«H2O=HCO3¡ª£«NH3
(3)2H2O22H2O£«O2¡ü£¬ÌúÀë×Ó»á¼ÓËÙH2O2·Ö½â£¬Ê¹Ï´µÓ¼Áʧȥɱ¾ú×÷Óã»2Fe3£«£«3CO32¡ª£«3H2O=2Fe(OH)3¡ý£«3CO2¡ü£¬Fe3£«ÓëCO32¡ªË®½âÏ໥´Ù½ø£¬Ê¹Ï´µÓ¼ÁʧȥȥÎÛÄÜÁ¦
(4)¢ÙCO2ºÍO2
¢Ú
(2)H2O2£«CN££«H2O=HCO3¡ª£«NH3
(3)2H2O22H2O£«O2¡ü£¬ÌúÀë×Ó»á¼ÓËÙH2O2·Ö½â£¬Ê¹Ï´µÓ¼Áʧȥɱ¾ú×÷Óã»2Fe3£«£«3CO32¡ª£«3H2O=2Fe(OH)3¡ý£«3CO2¡ü£¬Fe3£«ÓëCO32¡ªË®½âÏ໥´Ù½ø£¬Ê¹Ï´µÓ¼ÁʧȥȥÎÛÄÜÁ¦
(4)¢ÙCO2ºÍO2
¢Ú
ʵÑé²½Öè | Ô¤ÆÚÏÖÏóÓë½áÂÛ |
³ÎÇåʯ»ÒË® 8.0 mol¡¤L£1 NaOHÈÜÒº¡¡²¢½«´ø»ðÐǵÄСľÌõ·ÅÔÚ×îºóÒ»¸öÏ´ÆøÆ¿µÄ³ö¿Ú´¦ | Èô³ÎÇåʯ»ÒË®²»±ä»ë×Ç£¬Ä¾Ìõ¸´È¼£¬Ôò¼ÙÉè1³ÉÁ¢£»Èô³ÎÇåʯ»ÒË®±ä»ë×Ç£¬Ä¾Ìõ¸´È¼£¬Ôò¼ÙÉè2³ÉÁ¢£»Èô³ÎÇåʯ»ÒË®±ä»ë×Ç£¬Ä¾Ìõ²»¸´È¼£¬Ôò¼ÙÉè3³ÉÁ¢ |
¡¡(1)ÕâÖÖÐÂÐÍÒºÌåÏ´µÓ¼ÁµÄÑôÀë×ÓΪNa£«£¬¿ÉÓÃÑæÉ«·´Ó¦½øÐмìÑé¡£(3)ÌúÀë×Ó¿ÉÒÔ×÷Ϊ¹ýÑõ»¯Çâ·Ö½âµÄ´ß»¯¼Á£¬´Ó¶øµ¼Ö¹ýÑõ»¯Çâ·Ö½â¶øʧЧ£»ÌúÀë×ÓÓë̼Ëá¸ùÀë×Ó·¢ÉúË®½âÏ໥´Ù½ø·´Ó¦£¬Ê¹Ï´µÓ¼ÁʧȥȥÎÛÄÜÁ¦¡£(4)¢Ù¸ÃÎÞÉ«ÎÞζÆøÌå»òÊÇÑõÆø¡¢»òÊǶþÑõ»¯Ì¼¡¢»òÊÇÁ½ÖÖÆøÌåµÄ»ìºÏÆøÌå¡£¢ÚÓóÎÇåʯ»ÒË®¼ìÑé¶þÑõ»¯Ì¼£¬ÓÃNaOHÈÜÒºÎüÊÕδ·´Ó¦ÍêµÄ¶þÑõ»¯Ì¼£¬×îºóͨ¹ý´ø»ðÐǵÄСľÌõ¼ìÑéÑõÆø¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿