ÌâÄ¿ÄÚÈÝ

ÍéÌþAÖ»¿ÉÄÜÓÐÈýÖÖÒ»ÂÈ´úÎïB¡¢C¡¢D¡£CµÄ½á¹¹¼òʽÊÇ¡£BºÍD·Ö±ðÓëÇ¿¼îµÄ´¼ÈÜÒº¹²ÈÈ£¬¶¼Ö»Äܵõ½Óлú»¯ºÏÎïE¡£ÒÔÉÏ·´Ó¦¼°BµÄ½øÒ»²½·´Ó¦ÈçÏÂͼËùʾ¡£

Çë»Ø´ð£º
£¨1£©AµÄ½á¹¹¼òʽÊÇ__________________________¡£
£¨2£©FµÄ¹ÙÄÜÍÅÃû³ÆÊÇ_______£»EÔÚÒ»¶¨Ìõ¼þÏÂת»¯ÎªBÊôÓÚ_______·´Ó¦£¨Ìî·´Ó¦ÀàÐÍ£©¡£
£¨3£©Bת»¯ÎªEµÄ»¯Ñ§·½³ÌʽΪ£º______________________________________________________¡£
G¡úH·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º____________________________________________________________¡£
£¨4£©Ð´³ö±ÈFÉÙÁ½¸ö̼ԭ×ÓÇÒΪFͬϵÎïµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º
_____________________________________________________________________________________¡£

£¨1£©(CH3)3C¡ªCH2CH3£¨2·Ö£©£»£¨2£©ôÇ»ù£»¼Ó³É£»£¨¸÷1·Ö£©
£¨3£©(CH3)3C¡ªCH2CH2Cl+NaOH (CH3)3CCH=CH2+NaCl+H2O£»£¨2·Ö£©
(CH3)3CCH2CHO+2Ag(NH3)2++2OH- (CH3)3CCH2COO-+2Ag¡ý+ NH4++3NH3+H2O£»£¨2·Ö£©
£¨4£©CH3CH2CH2CH2OH¡¢CH3CH2CH(OH)CH3¡¢(CH3)2CHCH2OH¡¢(CH3)2C(OH)CH3£»
£¨4·Ö£¬Ã¿1·Ö£©

½âÎöÊÔÌâ·ÖÎö£ºÍéÌþAÖ»¿ÉÄÜÓÐÈýÖÖÒ»ÂÈÈ¡´ú²úÎïB¡¢CºÍD£¬CµÄ½á¹¹¼òʽÊÇCH3CH2C(CH3)2CH2Cl£¬ËùÒÔAµÄ½á¹¹¼òʽΪ(CH3)3CCH2CH3¡£BºÍD·Ö±ðÓëÇ¿¼îµÄ´¼ÈÜÒº¹²ÈÈ£¬¶¼Ö»Äܵõ½Óлú»¯ºÏÎïE£¬¹ÊEµÄ½á¹¹¼òʽΪ(CH3)3CCH£½CH2¡£BÔÚÇâÑõ»¯ÄÆË®ÈÜÒºÏÂÉú³ÉF£¬FΪ´¼£¬FÑõ»¯Éú³ÉG£¬GÄÜÓëÒø°±ÈÜÒº·´Ó¦£¬Gº¬ÓÐÈ©»ù£­CHO£¬¹ÊB¡¢F¡¢G¡¢H¡¢DµÄ½á¹¹¼òʽ·Ö±ðΪ(CH3)3CCH2CH2Cl¡¢(CH3)3CCH2CH2OH¡¢(CH3)3CCH2CHO¡¢(CH3)3CCH2COOH¡¢(CH3)3CCH2ClCH3£©¡£
£¨1£©¸ù¾ÝÒÔÉÏ·ÖÎö¿ÉÖª£¬AµÄ½á¹¹¼òʽÊÇ(CH3)3C¡ªCH2CH3¡£
£¨2£©¸ù¾ÝFµÄ½á¹¹¼òʽ¿ÉÖª£¬·Ö×ÓÖк¬ÓеĹÙÄÜÍÅÃû³ÆÊÇôÇ»ù£»E·Ö×ÓÖк¬ÓÐ̼̼˫¼ü£¬ÄܺÍÂÈ»¯Çâ·¢Éú¼Ó³É·´Ó¦Éú³ÉB£¬ÔòEÔÚÒ»¶¨Ìõ¼þÏÂת»¯ÎªBµÄ·´Ó¦ÊǼӳɷ´Ó¦¡£
£¨3£©Bת»¯ÎªEÊDZ´úÌþµÄÏûÈ¥·´Ó¦£¬Òò´ËBת»¯ÎªEµÄ»¯Ñ§·½³ÌʽΪ(CH3)3C¡ªCH2CH2Cl£«NaOH (CH3)3CCH=CH2£«NaCl£«H2O£»G¡úH·´Ó¦ÊÇÒø¾µ·´Ó¦£¬Æä·´Ó¦µÄÀë×Ó·½³ÌʽΪ(CH3)3CCH2CHO+2Ag(NH3)2++2OH- (CH3)3CCH2COO-+2Ag¡ý+ NH4++3NH3+H2O¡£
£¨4£©±ÈFÉÙÁ½¸ö̼ԭ×ÓÇÒΪFͬϵÎÕâ˵Ã÷¸ÃÓлúÎïÊǺ¬ÓÐ4¸ö̼ԭ×ӵı¥ºÍÒ»Ôª´¼£¬Ôò¿ÉÄܵĽṹ¼òʽΪCH3CH2CH2CH2OH¡¢CH3CH2CH(OH)CH3¡¢(CH3)2CHCH2OH¡¢(CH3)2C(OH)CH3¡£
¿¼µã£º¿¼²éÓлúÎïÍƶϡ¢¹ÙÄÜÍÅ¡¢Óлú·´Ó¦ÀàÐÍ¡¢Í¬·ÖÒì¹¹ÌåÅжÏÒÔ¼°·½³ÌʽµÄÊéдµÈ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø