ÌâÄ¿ÄÚÈÝ

£¨10·Ö£©ÓÐÏÂÁл¯Ñ§ÒÇÆ÷£º
¢ÙÍÐÅÌÌìƽ¢Ú²£Á§°ô¢ÛÒ©³×¢ÜÉÕ±­¢ÝÁ¿Í²¢ÞÈÝÁ¿Æ¿¢ß½ºÍ·µÎ¹Ü¢àϸ¿ÚÊÔ¼ÁÆ¿¢á±êÇ©Ö½
£¨1£©ÏÖÐèÒªÅäÖÆ500m L 1mol/L H2SO4ÈÜÒº£¬ÐèÒªÖÊÁ¿·ÖÊýΪ98%£¬ÃܶÈΪ1.84g/cm3µÄŨH2SO4       £»
£¨2£©´ÓÉÏÊöÒÇÆ÷ÖУ¬°´ÊµÑéÒªÇóʹÓõÄÏȺó˳Ðò£¬Æä±àºÅÅÅÁÐÊÇ              £»
£¨3£©ÈÝÁ¿Æ¿Ê¹ÓÃÇ°¼ìÑé©ˮµÄ·½·¨ÊÇ                                  £»
£¨4£©ÈôʵÑéÓöµ½ÏÂÁÐÇé¿ö£¬¶ÔÁòËáÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈÓкÎÓ°Ï죨Ìî¡°Æ«¸ß¡±¡°Æ«µÍ¡±»ò¡°²»±ä¡±£©
¢ÙÓÃÒÔÏ¡ÊÍŨÁòËáµÄÉÕ±­Î´Ï´µÓ£¬         £»
¢Úδ¾­ÀäÈ´½«ÈÜҺעÈëÈÝÁ¿Æ¿ÖУ¬         £»
¢ÛÒ¡ÔȺó·¢ÏÖÒºÃæϽµÔÙ¼ÓË®£¬         £»
¢Ü¶¨ÈÝʱ¹Û²ìÒºÃ温ÊÓ£¬         ¡£
£¨1£©2.72 mL
£¨2£©¢Ý¢Ü¢Ú¢Þ¢ß¢à¢á
£¨3£©ÍùÈÝÁ¿Æ¿ÄÚ¼ÓÊÊÁ¿Ë®,ÈûºÃÆ¿Èû£¬ÓÃʳָ¶¥×¡Æ¿Èû£¬ÓÃÁíÒ»Ö»ÊÖµÄÎåÖ¸ÍÐסƿµ×£¬°ÑÆ¿µ¹Á¢¹ýÀ´£¬È粻©ˮ£¬°ÑÆ¿ÈûÐýת180?ºóÈû½ô£¬ÔÙ°ÑÆ¿µ¹Á¢¹ýÀ´£¬Èô²»Â©Ë®£¬²ÅÄÜʹÓá£
£¨4£©¢ÙÆ«µÍ¢ÚÆ«¸ß¢ÛÆ«µÍ¢ÜÆ«¸ß
½âÌâ̽¾¿£º±¾ÌâÖ÷Òª¿¼²éÁËÎïÖʵÄÁ¿Å¨¶È¡¢ÈÜÒºµÄÅäÖƼ°Îó²î·ÖÎö¡£±¾ÌâÄѵãÔÚÓÚÎó²î·ÖÎö£¬Àí½âÒýÆðÎó²îµÄÔ­ÒòÊǽâÌâµÄ¹Ø¼ü¡£
£¨1£©V£¨Å¨H2SO4£©¡Á1.84g/mL¡Á98%="0.500L¡Á1" mol/L¡Á98g/mol
£¨2£©ÅäÖÆ˳ÐòÊÇ£º¼ÆËã¡úÁ¿È¡¡úÏ¡ÊÍ¡úÒÆÒº¡ú¶¨ÈÝ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ijУ»¯Ñ§¿ÎÍâС×éÓÃÁòËáÌú·ÏÒº£¨º¬ÉÙÁ¿ÁòËáÍ­ºÍÏ¡ÁòËᣩ£¬ÖƱ¸ÁòËáÑÇÌú¾§Ìå²¢½øÐÐÈçÏÂʵÑé¡£ÖƱ¸ÁòËáÑÇÌú¾§ÌåÖ÷ÒªµÄ²Ù×÷Á÷³ÌÈçÏ£º

Çë¸ù¾ÝÌâÄ¿ÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©AµÄ»¯Ñ§Ê½Îª           £¬ÉÏÊö²Ù×÷¹ý³ÌÖÐÓõ½µÄ²£Á§ÒÇÆ÷ÓУº¢ÙÉÕ±­¡¢¢Ú¢Û²£Á§°ô¡¢¢Û¾Æ¾«µÆ¡¢¢Üζȼơ¢¢Ý            ¡£
£¨2£©³ÃÈȹýÂ˵ÄÄ¿µÄÊÇ          ¡£
£¨3£©½á¾§²Ù×÷¹ý³ÌÖÐÓ¦¿ØÖÆÂËÒºËáÐÔµÄÔ­ÒòÊÇ____              
£¨4£©ÒÑÖªÁòËáÑÇÌúï§[£¨NH4£©2Fe £¨SO4£©2]±ÈÁòËáÑÇÌúÎȶ¨£¬ÓÃÔÚ·ÖÎö»¯Ñ§ÖС£ÁòËáÑÇÌú刺ÉÓÃÁòËá狀ÍÁòËáÑÇÌú·´Ó¦ÖƵá£ÊµÑéÊÒÀûÓÃÁòËáÑÇÌúï§ÈÜÒººÍ²ÝËáÈÜÒº·´Ó¦Éú³É²ÝËáÑÇÌú³ÁµíÀ´ÖƱ¸²ÝËáÑÇÌú¡£Ð´³öÁòËáÑÇÌúï§ÈÜÒºÓë²ÝËáÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ____                    ¡£
£¨5£©²ÝËáÑÇÌú¾§Ì壨Ïà¶Ô·Ö×ÓÖÊÁ¿180£©ÊÜÈÈÒ׷ֽ⣬ij¿ÎÍâС×éÉè¼ÆÈçͼµÄʵÑé×°ÖÃÀ´¼ìÑéÆä·Ö½â²úÎï¡£

¢Ù¸Ã×°ÖÃÖÐ×î²»ºÏÀíµÄ²¿·Ö             £¨Ìî×Öĸ£©£¬Ô­ÒòÊÇ         ¡£
¢Ú¸ÄÓÃÕýÈ·×°ÖÃʵÑ鿪ʼºó£¬B´¦±äÀ¶£¬ËµÃ÷²ÝËáÑÇÌú¾§ÌåÖÐÓР         £»C´¦Óа×É«³Áµí£¬E´¦²¿·ÖºÚÉ«·ÛÄ©±äΪºìÉ«£¬ËµÃ÷²ÝËáÑÇÌú·Ö½â²úÉú   £¨Ìѧʽ£©¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø