ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Îó²î
£¨1£©ÔÚתÒÆÈÜҺʱÓв¿·ÖÈÜÒº½¦³ö£¬ÔòÅäÖƵÄÈÜҺŨ¶È___________£¨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°²»±ä¡±£¬ÏÂͬ£©£»
£¨2£©×ªÒÆÈÜÒººó£¬Ã»ÓÐÓÃˮϴµÓÉÕ±ÄÚ±Ú£¬ÈÜҺŨ¶È½«__________£»
£¨3£©¼ÓË®³¬¹ýÈÝÁ¿Æ¿µÄ¿Ì¶ÈÏߣ¬ÈÜҺŨ¶È½«__________£¬´ËʱӦ¸Ã_______________£»
£¨4£©¼ÓË®¶¨ÈÝʱ¸©Êӿ̶ÈÏߣ¬ÈÜҺŨ¶È½«__________£»
£¨5£©¶¨Èݺó½«ÈÜÒºÒ¡ÔÈ£¬·¢ÏÖÒºÃæϽµ£¬ÓÖ¼ÓË®µ½¿Ì¶ÈÏߣ¬ÈÜҺŨ¶È½«_________¡£
£¨6£©ÉÕ¼îÈܽâºó£¬Ã»Óлָ´µ½ÊÒΣ¬¾ÍתÒƵ½ÈÝÁ¿Æ¿ÖнøÐÐÅäÖÆ£¬Å¨¶È½«____________¡£
¡¾´ð°¸¡¿Æ«µÍ Æ«µÍ Æ«µÍ ÖØÐÂÅäÖÆ Æ«¸ß Æ«µÍ Æ«¸ß
¡¾½âÎö¡¿
£¨1£©ÔÚתÒÆÈÜҺʱÓв¿·ÖÈÜÒº½¦³ö£¬ÈÜÖÊËðʧ£¬¸ù¾Ýc=¿ÉÖª£¬ÔòÅäÖƵÄÈÜҺŨ¶ÈÆ«µÍ£»
£¨2£©×ªÒÆÈÜÒººó£¬Ã»ÓÐÓÃˮϴµÓÉÕ±ÄÚ±Ú£¬ÈÜÖÊËðʧ£¬¸ù¾Ýc=¿ÉÖª£¬ÈÜҺŨ¶È½«Æ«µÍ£»
£¨3£©¼ÓË®³¬¹ýÈÝÁ¿Æ¿µÄ¿Ì¶ÈÏߣ¬ËùÅäÈÜÒºÌå»ýÆ«´ó£¬¸ù¾Ýc=¿ÉÖª£¬ÈÜҺŨ¶È½«Æ«µÍ£¬´ËʱӦ¸ÃÖØÐÂÅäÖÆ£»
£¨4£©¼ÓË®¶¨ÈÝʱ¸©Êӿ̶ÈÏߣ¬ËùÅäÈÜÒºÌå»ýÆ«ÉÙ£¬¸ù¾Ýc=¿ÉÖª£¬ÈÜҺŨ¶È½«Æ«¸ß£»
£¨5£©¶¨Èݺó½«ÈÜÒºÒ¡ÔÈ£¬·¢ÏÖÒºÃæϽµ£¬ÓÖ¼ÓË®µ½¿Ì¶ÈÏߣ¬Ôò¶à¼ÓÁËÕôÁóË®£¬¸ù¾Ýc=¿ÉÖª£¬ÈÜҺŨ¶È½«Æ«µÍ£»
£¨6£©ÉÕ¼îÈܽâºó£¬Ã»Óлָ´µ½ÊÒΣ¬¾ÍתÒƵ½ÈÝÁ¿Æ¿ÖнøÐÐÅäÖÆ£¬ÉÕ¼îÈÜÓÚË®·ÅÈÈ£¬¸ù¾ÝÈÈÕÍÀäËõµÄÔÀí£¬ËùÅäÈÜÒºÌå»ýƫС£¬¸ù¾Ýc=¿ÉÖª£¬Å¨¶È½«Æ«¸ß¡£
¡¾ÌâÄ¿¡¿Ïû¶¾¼ÁÔÚÉú²ú¡¢Éú»îÖÐÓÐÖØÒªµÄ×÷Ó㬳£¼ûµÄº¬ÂÈÏû¶¾¼ÁÓÐ NaClO2¡¢NaClO¡¢ClO2ºÍCl2¡£
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©»ù̬ Cl Ô×ÓºËÍâÓÐ______ÖÖ²»Í¬ÄÜÁ¿µÄµç×Ó£¬Cl ÔªËØ´¦ÓÚÔªËØÖÜÆÚ±íµÄ______Çø£¬Æä»ù̬Ô×ÓÖУ¬ºËÍâµç×ÓÕ¼¾ÝµÄµç×ÓÔÆÂÖÀªÍ¼ÎªÇòÐεÄÄܼ¶ÓÐ_______¸ö¡£
£¨2£©NaClO2 Ëùº¬µÄ»¯Ñ§¼üÀàÐÍÓÐ___________¡£
£¨3£©Ïû¶¾¼ÁͶÈëË®ÖУ¬Ò»¶Îʱ¼äºóÓë°±½áºÏµÃµ½Ò»ÖÖ½áºÏÐÔÂÈ°·(NH2C1)¡£NH2C1 ÔÚÖÐÐÔ»òËáÐÔÌõ¼þÏÂÒ²ÊÇÒ»ÖÖǿɱ¾úÏû¶¾¼Á£¬³£ÓÃÓÚ³ÇÊÐ×ÔÀ´Ë®Ïû¶¾¡£ÆäÀíÓÉÊÇ___________£¨Óû¯Ñ§·½³Ìʽ±íʾ£©¡£
£¨4£©¡°ÓÐЧÂȺ¬Á¿¡±¿ÉÓÃÀ´ºâÁ¿º¬ÂÈÏû¶¾¼ÁµÄÏû¶¾ÄÜÁ¦£¬Æ䶨ÒåÊÇÿ¿Ëº¬ÂÈÏû¶¾¼ÁµÄÑõ»¯ÄÜÁ¦Ï൱ÓÚ¶àÉÙ¿Ë Cl2 µÄÑõ»¯ÄÜÁ¦¡£ÉÏÊöËÄÖÖº¬ÂÈÏû¶¾¼ÁÖÐÏû¶¾ÄÜÁ¦×îÇ¿µÄÊÇ_____¡£
£¨5£©×ÔÀ´Ë®³§ÓÃClO2´¦ÀíºóµÄË®ÖУ¬ÒªÇóClO2µÄŨ¶ÈÔÚ0.1¡«0.8 mg¡¤L-1Ö®¼ä¡£ÓõâÁ¿·¨¼ì²â ClO2´¦ÀíºóµÄ×ÔÀ´Ë®ÖÐClO2 Ũ¶ÈµÄʵÑé²½ÖèÈçÏ£º
²½Öè I£®È¡Ò»¶¨Ìå»ýµÄË®Ñù£¬¼ÓÈë×ãÁ¿µâ»¯¼Ø£¬ÔÙÓÃÇâÑõ»¯ÄÆÈÜÒºµ÷ÖÁÖÐÐÔ£¬²¢¼ÓÈëµí·ÛÈÜÒº¡£
²½Öè¢ò£®Óà Na2S2O3 ÈÜÒºµÎ¶¨²½Öè I ÖÐËùµÃµÄÈÜÒº¡£
ÒÑÖª£ºa£®²Ù×÷ʱ£¬²»Í¬ pH »·¾³ÖÐÁ£×ÓÖÖÀàÈçϱíËùʾ¡£
pH | 2 | 7 |
Á£×ÓÖÖÀà | Cl- | ClO2 |
b. 2S2O32-+I2 =S4O62-+2I ¡£
¢Ù ²½Öè¢òÖз´Ó¦½áÊøʱÈÜÒº³Ê____£¨Ìî¡°À¶É«¡±»ò¡°ÎÞÉ«¡±£©¡£
¢Ú ÈôË®ÑùµÄÌå»ýΪ1.0L£¬ÔÚ²½Öè¢òÖÐÏûºÄ10mL1.0¡Á10-3mol¡¤L-lNa2S2O3ÈÜÒº£¬Ôò¸ÃË®ÑùÖÐc(ClO2)=____mg¡¤L-1¡£