ÌâÄ¿ÄÚÈÝ
ÏÂÁÐÓйØÈÈ»¯Ñ§·½³ÌʽµÄÐðÊöÕýÈ·µÄÊÇ( )
A£®ÒÑÖªC(ʯī£¬s)C(½ð¸Õʯ£¬s)£»¡÷H>0£¬Ôò½ð¸Õʯ±ÈʯīÎȶ¨ |
B£®ÒÑÖªC(s)+O2(g)=CO2(g)£»¡÷H1ºÍC(s)+1/2O2(g)=CO(g)£»¡÷H2£¬Ôò¡÷H1>¡÷H2 |
C£®101kPaʱ£¬2H2(g)+O2(g)=2H2O(l)£»¡÷H=-5716kJ/mol£¬ÔòÇâÆøµÄȼÉÕÈÈΪ285.8kJ/mol |
D£®º¬20.0gNaOHµÄÏ¡ÈÜÒºÓëÏ¡ÑÎËáÍêÈ«ÖкÍʱ·Å³ö28.7kJµÄÈÈÁ¿£¬Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£º NaOH(aq)+HCl(aq)="NaCl(aq)+" H2O(1)£»¡÷H="+57.4" kJ/mol |
C
ÊÔÌâ·ÖÎö£ºA¡¢ÓÉ·´Ó¦£ºC(ʯī£¬s)C(½ð¸Õʯ£¬s)£»¡÷H>0Öª£¬Ê¯Ä«¾ßÓеÄÄÜÁ¿µÍ£¬ÎïÖʾßÓеÄÄÜÁ¿Ô½µÍÔ½Îȶ¨£¬Ôòʯī±È½ð¸ÕʯÎȶ¨£¬´íÎó£»B¡¢¡÷H´óС±È½ÏÒª´ø·ûºÅ±È½Ï£¬¶ÔÓÚ·ÅÈÈ·´Ó¦¶øÑÔ£¬·Å³öµÄÈÈÁ¿Ô½¶à£¬¡÷HԽС£¬Ôò¡÷H1£¼¡÷H2£¬´íÎó£»C¡¢101kPaʱ£¬2H2(g)+O2(g)=2H2O(l)£»¡÷H=-5716kJ/mol£¬ÔòÇâÆøµÄȼÉÕÈÈΪ285.8kJ/mol£¬ÕýÈ·£»D¡¢º¬20.0gNaOHµÄÏ¡ÈÜÒºÓëÏ¡ÑÎËáÍêÈ«ÖкÍʱ·Å³ö28.7kJµÄÈÈÁ¿£¬Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ£º NaOH(aq)+HCl(aq)="NaCl(aq)+" H2O(1)£»¡÷H=¡ª57.4 kJ/mol£¬´íÎó¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿