ÌâÄ¿ÄÚÈÝ

A¡¢BÁ½ÖÖÓлúÎï¾ùÊÇÓлúºÏ³ÉµÄÖмäÌ壬ÆäÖÐAµÄ·Ö×ÓʽΪC4H7O2Br£¬B·Ö×ÓÖк¬2¸öÑõÔ­×Ó£¬ÆäȼÉÕ²úÎïn£¨CO2£©£ºn£¨H2O£©=2£º1£¬ÖÊÆ×ͼ±íÃ÷BµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª188¡£AºÍB´æÔÚÈçÏÂת»¯¹Øϵ£º

ÒÑÖª£º¢ÙÒ»¸ö̼ԭ×ÓÉÏÁ¬ÓÐÁ½¸öôÇ»ùʱ£¬Ò×·¢ÉúÏÂÁÐת»¯£º

¢Úͬһ¸ö̼ԭ×ÓÉÏÁ¬ÓÐÁ½¸öË«¼üµÄ½á¹¹²»Îȶ¨¡£
Çë»Ø´ð£º
£¨1£©C¸úÐÂÖƵÄÇâÑõ»¯Í­·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ      ¡£
£¨2£©AµÄ½á¹¹¼òʽÊÇ      ¡£
£¨3£©BµÄ·Ö×ÓʽÊÇ      ¡£
£¨4£©F¾ßÓÐÈçÏÂÌص㣺¢Ù¾ßÓÐÈõËáÐÔ£»¢ÚºË´Å¹²ÕñÇâÆ×ÖÐÏÔʾÎåÖÖÎüÊշ壻¢Û±½»·ÉϵÄÒ»ÂÈ´úÎïÖ»ÓÐÁ½ÖÖ£»¢Ü³ý±½»·Í⣬²»º¬ÓÐÆäËû»·×´½á¹¹¡£Ð´³ö·ûºÏÉÏÊöÌõ¼þÇÒ¾ßÓÐÎȶ¨½á¹¹µÄÈÎÒâÁ½ÖÖͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º             ¡¢             ¡£

£¨1£©CH3CHO+2Cu(OH)2 CH3COOH+Cu2O¡ý+2H2O£¨2·Ö£©
£¨2£©CH3COOCHBrCH3£¨2·Ö£©£»£¨3£©C12H12O2£¨1·Ö£©
£¨4£©¡¢¡¢¡¢£¨ÈÎдÁ½¸ö£¬Ã¿¸ö2·Ö£©

½âÎöÊÔÌâ·ÖÎö£ºC¡¢D¶¼ÄÜת»¯³ÉE£¬ËµÃ÷C¡¢Dº¬ÓеÄ̼ԭ×ÓÊýÏàµÈ£¬¶¼º¬ÓÐ2¸ö̼ԭ×Ó£¬CÄÜÓëÐÂÖƱ¸ÇâÑõ»¯Í­·´Ó¦£¬CΪCH3CHO£¬EΪCH3COOH£¬ÔòDΪCH3COONa£¬½áºÏAµÄ·Ö×ÓʽÒÔ¼°Ìâ¸øÐÅÏ¢¿ÉÖªAΪCH3COOCHBrCH3£¬B·Ö×ÓÖк¬2¸öÑõÔ­×Ó£¬ÆäȼÉÕ²úÎïn£¨CO2£©£ºn£¨H2O£©=2£º1£¬ËµÃ÷·Ö×ÓÖÐC¡¢HÔ­×ÓÊýÏàµÈ£¬ÖÊÆ×ͼ±íÃ÷BµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª188£¬Éè·Ö×ÓʽΪCnHnO2£¬Ôò13n+32=188£¬n=12£¬Ôò·Ö×ÓʽΪC12H12O2£¬ÔòFµÄ·Ö×ÓʽΪC10H10O£¬¦¸==6£¬
£¨1£©CΪCH3CHO£¬ÓëÇâÑõ»¯Í­·´Ó¦µÄ·½³ÌʽΪCH3CHO+2Cu(OH)2CH3COOH+Cu2O¡ý+2H2O£»
£¨2£©ÓÉÒÔÉÏ·ÖÎö¿ÉÖªAΪCH3COOCHBrCH3£»
£¨3£©BµÄ·Ö×ÓʽÊÇC12H12O2£¬£»
£¨4£©FµÄ·Ö×ÓʽΪC10H10O£¬¦¸= =6£¬¢Ù¾ßÓÐÈõËáÐÔ£¬Ó¦º¬ÓзÓôÇ»ù£»
¢ÚºË´Å¹²ÕñÇâÆ×ÖÐÏÔʾÎåÖÖÎüÊշ壻¢Û±½»·ÉϵÄÒ»ÂÈ´úÎïÖ»ÓÐÁ½ÖÖ£¬Ó¦Îª¶Ô³Æ½á¹¹£»¢Ü³ý±½»·Í⣬²»º¬ÓÐÆäËû»·×´½á¹¹£¬·Ö×ÓÖÐÓ¦º¬ÓÐ1¸öC¡ÔC»ò2¸öC=C£¬Ôò¿ÉÄܵĽṹΪ¡¢¡¢¡¢
¿¼µã£º¿¼²é¿¼²éÓлúÎïµÄÍƶϡ£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¢ñ.2009ÄêÄ«Î÷¸ç¡¢ÃÀ¹úµÈµØ³öÏÖ¼×ÐÍH1N1Á÷¸ÐÒßÇ飬ÒýÆðÈ«ÊÀ½çµÄ¹Ø×¢£¬ÕâÖÖÁ÷¸ÐÒßÇéÊÇÓɼ×ÐÍH1N1²¡¶¾ÒýÆðµÄ¡£ÃÀ¹ú¼²²¡¿ØÖƺÍÔ¤·ÀÖÐÐÄÍƼöʹÓÃÈðÊ¿ÂÞÊÏÖÆÒ©¹«Ë¾Éú²úµÄ¡°´ï·Æ¡±½ºÄÒºÍÓ¢¹ú¸ðÀ¼ËØ¡ªÊ·¿Ë¹«Ë¾Éú²úµÄÅçÎíʽҩ¼Á¡°ÀÖ¸ÐÇ塱Á½¿îÒ©Îï¡£
´ï·ÆºÍÀÖ¸ÐÇåµÄ½á¹¹¼òʽÈçÏÂͼËùʾ£º
      
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÀÖ¸ÐÇåµÄ·Ö×ÓʽÊÇ____ ¡£
£¨2£©ºÏ³É´ï·ÆµÄÖ÷ÒªÔ­ÁÏç²ÝËá(½á¹¹¼òʽΪ    )´æÔÚÓÚÎÒ¹úÊ¢²úµÄ°Ë½ÇÜîÏãÖС£¹ØÓÚç²ÝËáÐÔÖʵÄÃèÊö£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨  £©
A. 1 molç²ÝËáÓë×ãÁ¿µÄ½ðÊôÄÆ·´Ó¦¿ÉÉú³É4mol H2¡£
B. 1 molç²ÝËáÓë×ãÁ¿ÇâÑõ»¯ÄÆÈÜÒº·´Ó¦£¬×î¶à¿ÉÏûºÄÇâÑõ»¯ÄÆ4 mol¡£
C. 1 molç²ÝËáÓë×ãÁ¿µÄ̼ËáÄÆÈÜÒº·´Ó¦¿ÉÉú³É¶þÑõ»¯Ì¼ÆøÌå1 mol¡£
D. 1 molç²ÝËáÓë×ãÁ¿µÄ̼ËáÇâÄÆÈÜÒº·´Ó¦¿ÉÉú³É¶þÑõ»¯Ì¼ÆøÌå1 mol
£¨3£©ÏÂÁÐÿ×éÖи÷ÓÐÈý¶ÔÎïÖÊ£¬ËüÃǶ¼ÄÜÓ÷ÖҺ©¶··ÖÀëµÄÊÇ
A£®ÒÒËáÒÒõ¥ºÍË®£¬¾Æ¾«ºÍË®£¬Ö²ÎïÓͺÍË®
B£®ËÄÂÈ»¯Ì¼ºÍË®£¬äå±½ºÍË®£¬Ïõ»ù±½ºÍË®
C£®¸ÊÓͺÍË®£¬ÒÒËáºÍË®£¬ÒÒËáºÍÒÒ´¼
D£®ÆûÓͺÍË®£¬±½ºÍË®£¬ÒÒ¶þ´¼ºÍË®
¢ò.ÏÂͼÖÐA¡¢B¡¢C¡¢D¡¢E¾ùΪÓлú»¯ºÏÎï¡£ÒÑÖª£ºCÄܸúNaHCO3ÈÜÒº·¢Éú·´Ó¦£¬CºÍDµÄÏà¶Ô·Ö×ÓÖÊÁ¿ÏàµÈ£¬ÇÒEΪÎÞÖ§Á´µÄ»¯ºÏÎï¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©C·Ö×ÓÖйÙÄÜÍŵÄÃû³ÆÊÇ¡¡¡¡¡¡¡¡¡¡£»»¯ºÏÎïB²»ÄÜ·¢ÉúµÄ·´Ó¦ÊÇ¡¡¡¡¡¡¡¡(Ìî×ÖĸÐòºÅ)¡£
a£®¼Ó³É·´Ó¦          ¡¡b£®È¡´ú·´Ó¦     ¡¡c£®ÏûÈ¥·´Ó¦¡¡
d£®õ¥»¯·´Ó¦             e£®Ë®½â·´Ó¦¡¡      f£®Ñõ»¯·´Ó¦
£¨2£©·´Ó¦¢ÚµÄ»¯Ñ§·½³ÌʽÊÇ___________________________¡££¨3£© AµÄ½á¹¹¼òʽÊÇ_________________¡£
£¨4£©Í¬Ê±·ûºÏÏÂÁÐÈý¸öÌõ¼þµÄBµÄͬ·ÖÒì¹¹ÌåµÄÊýÄ¿ÓÐ______¸ö¡£
aº¬Óмä¶þÈ¡´ú±½»·½á¹¹¡¡    b.ÊôÓÚ·Ç·¼ÏãËáõ¥      c.¿ÉÓëFeCl3ÈÜÒº·¢ÉúÏÔÉ«·´Ó¦
д³öÆäÖÐÈÎÒâÒ»¸öͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ__________________________________¡£

¢ñ.ÓлúÎïA¿ÉÊÓΪÊÇÌþB·Ö×ÓÖеÄËùÓÐÇâÔ­×Ó±»ÌþC·Ö×ÓÖÐ×î¼òµ¥µÄÌþ»ùÈ¡´ú¶øµÃµ½µÄ¡£ÇÒÒÑÖª£º¢ÙAÓöBr2µÄCCl4ÈÜÒº²»ÍÊÉ«£¬ÆäÒ»ÂÈ´úÎïÖ»ÓÐÒ»ÖÖ¡£¢ÚÒ»¶¨Á¿µÄBÍêȫȼÉÕ£¬²úÎïÖÐn£¨CO2£©:n£¨H2O£©£½2:1£¬ÇÒ26<M£¨B£©<78¡£¢ÛÌþCΪ±¥ºÍÁ´Ìþ£¬Í¨³£Çé¿ö³ÊÆø̬£¬Æäͬ·ÖÒì¹¹Ìå²»³¬¹ý2ÖÖ£¬Æä¶þäå´úÎïÓÐ3ÖÖ¡£ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©ÌþBµÄ×î¼òʽΪ______£¬·Ö×ÓʽΪ______¡£
£¨2£©ÌþCµÄÃû³ÆΪ                   ¡£
£¨3£©AµÄ·Ö×ÓʽΪ________¡£
¢ò.1,2-¶þäåÒÒÍé¿É×÷ÆûÓÍ¿¹±¬¼ÁµÄÌí¼Ó¼Á,³£ÎÂÏÂËüÊÇÎÞÉ«ÒºÌå,ÃܶÈÊÇ2.18¿Ë/ÀåÃ×3,·Ðµã131.4¡æ,ÈÛµã9.79¡æ,²»ÈÜÓÚË®,Ò×ÈÜÓÚ´¼¡¢ÃÑ¡¢±ûͪµÈÓлúÈܼÁ¡£ÔÚʵÑéÖпÉÒÔÓÃÏÂͼËùʾװÖÃÖƱ¸1,2-¶þäåÒÒÍé¡£ÆäÖзÖҺ©¶·ºÍÉÕÆ¿aÖзֱð×°ÓÐŨÁòËáºÍÒÒ´¼ÈÜÒº£¬ÊÔ¹ÜdÖÐ×°ÓÐŨä壨±íÃ渲¸ÇÉÙÁ¿Ë®£©¡£ÇëÌîдÏÂÁпհףº

£¨1£©Çëд³öÉÕÆ¿aÖз¢ÉúµÄ»¯Ñ§·´Ó¦·½³Ìʽ£º                        ¡£
£¨2£©°²È«Æ¿b¿ÉÒÔ·ÀÖ¹µ¹Îü,²¢¿ÉÒÔ¼ì²éʵÑé½øÐÐʱÊÔ¹ÜdÊÇ·ñ·¢Éú¶ÂÈû¡£Çëд³ö·¢Éú¶ÂÈûʱƿbÖеÄÏÖÏ󣺠                                     ¡£
£¨3£©c×°ÖÃÄÚNaOHÈÜÒºµÄ×÷ÓÃÊÇ        £»e×°ÖÃÄÚNaOHÈÜÒºµÄ×÷ÓÃÊÇ       ¡£

»¯ºÏÎïGÊǺϳɿ¹°©Ò©ÎïÃÀ·¨Â×µÄÖмäÌ壬ËüµÄ½á¹¹¼òʽΪ£º
Ëü¿ÉÓÉÖÐѧ³£¼ûµÄ¼òµ¥ÓлúÎïΪÖ÷ÒªÔ­ÁϺϳɣ¬ÆäºÏ³ÉÏß·ÈçÏ£º

£¨1£©DÓëA×é³ÉµÄÔªËØÏàͬ£¬Ô­×Ó¸öÊý±ÈÒ²Ïàͬ£¬°´ÒªÇóд³ö·ûºÏÌõ¼þµÄDµÄ½á¹¹¼òʽ£º
¢Ù·Ö×ӵĿռ乹ÐÍΪֱÏßÐ͵ķÖ×Ó              £»
¢Ú·Ö×ÓÖÐËùÓеÄ̼ԭ×Ó¾ùΪsp3ÔÓ»¯µÄ·Ö×Ó         £»
¢ÛNMRͼÆ×ÖÐÓÐ5¸ö·å£¬²¨·åÃæ»ýÖ®±ÈΪ2:1:2:2:1µÄ·Ö×Ó           £»
£¨2£©BµÄÒ»ÂÈ´úÎïÓÐÈýÖÖͬ·ÖÒì¹¹Ì壬BÓë×ãÁ¿ÇâÆøÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦Éú³É±¥ºÍÓлúÎïY£¬ÔòY»·ÉϵÄÒ»ÂÈ´úÎïµÄͬ·ÖÒì¹¹ÌåÓР        ÖÖ£»
£¨3£©ÒÑÖª°±ÆøÓë´¼ÔÚÒ»¶¨Ìõ¼þÏÂÄÜ·¢Éú·Ö×Ó¼äµÄÍÑË®·´Ó¦¡£Çëд³ö°±ÆøÓëÎïÖÊCÒÔÎïÖʵÄÁ¿Ö®±ÈΪ1:3·´Ó¦Éú³ÉµÄ²úÎïµÄ½á¹¹¼òʽ           £¬¸ÃÓлúÎïÖк¬ÓеĹÙÄÜÍŵÄÃû³ÆÊÇ     £¬
£¨4£©Ð´³öÔÚ¼ÓÈÈÇÒÓÐŨÁòËá´æÔÚÌõ¼þÏ£¬HÓëÒÒ¶þËáÒÔÎïÖʵÄÁ¿±ÈΪ1:1·´Ó¦µÄ»¯Ñ§·½³Ìʽ   £¬
¸Ã·´Ó¦µÄÀàÐÍÊÇ              ¡£
£¨5£©»¯ºÏÎïHµÄÒ»ÖÖͬ·ÖÒì¹¹ÌåX£¬ÄÜÓëÂÈ»¯ÌúÈÜÒº·¢ÉúÏÔÉ«·´Ó¦£¬ÇÒÄÜÓëŨäåË®·´Ó¦£¬1 mol X×î¶àÏûºÄ3 mol Br2£¬Ð´³öXµÄ½á¹¹¼òʽ            ¡££¨ÒªÇóд³öÁ½ÖÖ£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø