ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÇâäåËáÔÚÒ½Ò©ºÍʯ»¯¹¤ÒµÉÏÓй㷺µÄÓÃ;¡£ÏÂͼÊǹ¤ÒµÖƱ¸ÇâäåËá´ÖÆ·²¢¾«ÖƵÄÁ÷³Ì£º£¨·Ðµã£ºBr2£º58.5¡æ£»HBr£º£66.8¡æ£»H2SO4£º338¡æ£©
£¨1£©»ìºÏ¢ÙÖз´Ó¦µÄÀë×Ó·½³ÌʽÊÇ__________________________________¡£
£¨2£©»ìºÏ¢ÙÖв»Ö±½ÓÓÃË®¶øʹÓñùË®µÄÄ¿µÄÊÇ________________________¡£
£¨3£©²Ù×÷bÊÊÓÃÓÚ______»ìºÏÎïµÄ·ÖÀ루ÌîÐòºÅ£©¡£
A£®¹ÌÌåºÍÒºÌå B£®¹ÌÌåºÍ¹ÌÌå C£®»¥²»ÏàÈܵÄÒºÌå D£®»¥ÈܵÄÒºÌå
£¨4£©»ìºÏ¢ÚÖмÓÈëÑÇÁòËáÄƵÄÄ¿µÄÊÇ__________________¡£
£¨5£©´¿¾»µÄÇâäåËáӦΪÎÞÉ«ÒºÌ壬µ«¹¤ÒµÉú²úÖÐÖƵõÄÇâäåËᣨ¹¤ÒµÇâäåËᣩ³£´øÓлÆÉ«£¬¼×ͬѧ²Â²â¿ÉÄÜÊǺ¬ÓÐFe3£«£¬ÒÒͬѧ²Â²â¿ÉÄÜÊǺ¬ÓÐBr2¡£Çëд³ö֤ʵÒÒͬѧ²ÂÏëµÄʵÑé·½·¨ÊÇ________________________¡£
£¨6£©ÈôÆðʼʹÓÃm kgäåµ¥ÖÊ×÷ÔÁÏ£¬Íê³ÉÉú²úºó£¬µÃµ½¾«ÖÆÇâäåËáÈÜÒº250 L¡£È¡2.5 mL¾«ÖÆÈÜҺϡÊÍ£¬ÔÚÏ¡ÊÍÒºÖмÓÈë×ãÁ¿µÄÏõËáÒøÈÜÒº³ä·Ö·´Ó¦£¬Èô³ä·Ö·´Ó¦ºóµÃµ½n gµ»ÆÉ«³Áµí£¬Ôòµ¥ÖÊäåµÄÀûÓÃÂÊΪ__________¡£
¡¾´ð°¸¡¿SO2£«Br2£«2H2O = 4H£«£«2Br££«SO42£ ½µµÍÌåϵζȣ¬·ÀÖ¹äå»Ó·¢£¬Ìá¸ßÔÁϵÄÀûÓÃÂÊ D ³ýÈ¥´ÖÆ·ÖеÄäå È¡ÑùÆ·¼ÓÈëÉÙÁ¿±½£¬Õñµ´ºó¹Û²ìÉϲãÊÇ·ñÓгȻÆÉ« 2000n/47m¡Á100%
¡¾½âÎö¡¿
±¾ÌâµÄÁ÷³Ì±È½ÏÖ±¹Û£¬ÏÈÀûÓõĻ¹ÔÐÔÀ´ÖƱ¸£¬ºóÀûÓà ¡°²»»Ó·¢ÐÔËáÖÆÈ¡Ò×»Ó·¢ÐÔËᡱµÄÔÀíÕôÁó³ö£¬ÔÙ½øÐÐһϵÁеÄÌá´¿¼´¿É£¬ÄѶÈÒ»°ã¡£
£¨1£©»ìºÏ¢Ù¼´¶þÑõ»¯ÁòºÍµ¥ÖÊäåÖ®¼äµÄÑõ»¯»¹Ô·´Ó¦£¬×¢ÒâÆøÌå²»Äܲ𣺣»
£¨2£©äåÊÇÒ»ÖÖÈÝÒ×»Ó·¢µÄÒºÌ壬Òò´ËÓñùË®À´×÷·´Ó¦½éÖÊ¿ÉÒÔÓÐЧ¼õÇáäåµÄ»Ó·¢£¬Ìá¸ßÔÁÏÀûÓÃÂÊ£»
£¨3£©²Ù×÷b½«¾«ÖƵÄÇâäåËáÓë»ìºÏÈÜÒº·ÖÀ룬ÔÙ½áºÏÌâ¸É¸øµÄ·Ðµã¿ÉÖª£¬²Ù×÷bÊÇÕôÁó²Ù×÷£¬³£³£ÓÃÀ´·ÖÀë¶àÖÖ»¥ÈÜÇҷеãÏà²î½Ï´óµÄÒºÌ壬Òò´ËÑ¡D£»
£¨4£©ÑÇÁòËáÄƾßÓл¹ÔÐÔ£¬½áºÏÌâ¸É¸øµÄ·Ðµã¿ÉÖªµ¥ÖÊäå·Ðµã½ÏµÍ£¬ÔÚÕôÁóʱ»á»ìÈë²úÆ·ÖУ¬Òò´Ë¿É¼ÓÈëÑÇÁòËáÄÆÀ´Í¨¹ýÑõ»¯»¹ÔµÄ·½·¨³ýÈ¥µ¥ÖÊä壻
£¨5£©ÈôҪ֤ʵÈÜÒºÖÐÊÇ·ñÓе¥ÖÊä壬×î¼òµ¥µÄ·½·¨ÊÇÈ¡ÉÙÁ¿²úÆ·¼ÓÈë±½£¬Õñµ´ºóÈôÉϲ㱽ÏàÖÐÓгȻÆÉ«£¬Ôò¿ÉÖ¤Ã÷²úÆ·ÖÐÓе¥ÖÊä壻
£¨6£©n¿Ëµ»ÆÉ«³Áµí¼´molä廯Òø£¬2.5mLÈÜÒºÖÐÓÐmolä廯Òø£¬Òò´Ë250L¾«ÖÆÇâäåËáÖоÍÓÐmoläåÀë×Ó£¬ÕâЩ²úÆ·ÖеÄäåÒ»¹²ÖØkg£¬Òò´ËÀûÓÃÂÊΪ£¬»¯¼ò¼´¿É¡£
¡¾ÌâÄ¿¡¿Ê³ÓöþÑõ»¯ÁòƯ°×¹ýµÄʳƷ£¬¶ÔÈËÌåµÄ¸Î¡¢ÉöÔàµÈÓÐÑÏÖØË𺦡£Ä³¿ÆÑÐС×éÉè¼ÆʵÑé¼ìÑé¶þÑõ»¯ÁòµÄƯ°×ÐÔ¡£»Ø´ðÏÂÁÐÎÊÌ⣺
(Ò»)¶þÑõ»¯ÁòµÄÖƱ¸
ʵÑéÊÒÒ»°ã²ÉÓÃÑÇÁòËáÄÆÓëÁòËá(ŨÁòËáÓëË®1:1»ìºÏ)·´Ó¦ÖÆÈ¡¶þÑõ»¯Áò
(1)д³öʵÑéÊÒÖÆSO2µÄ»¯Ñ§·½³Ìʽ________________________________;
(2)ÓûÊÕ¼¯Ò»Æ¿¸ÉÔïµÄ¶þÑõ»¯Áò£¬Ñ¡ÔñÉÏͼÖеÄ×°Öã¬Æä×î¼ÑÁ¬½Ó˳ÐòΪ£º_______________________________________(°´ÆøÁ÷·½Ïò£¬ÓÃСд×Öĸ±íʾ)¡£
(¶þ)¶þÑõ»¯ÁòÐÔÖʵļìÑé
½«ÉÏÊöÊÕ¼¯µ½µÄSO2ͨÈëÏÂÁÐ×°ÖÃÖУ¬ÔÚÒ»¶¨Î¶ÈÏ°´Í¼Ê¾×°ÖýøÐÐʵÑé¡£
(2)¸ù¾ÝÉÏÊöʵÑ飬»Ø´ðÏÂÁÐÎÊÌ⣺
ÐòºÅ | ʵÑéÏÖÏó | ½âÊÍÔÒò |
¢Ù | _________________________ | _________________________ |
¢Ú | Æ·ºìÊÔÒºÍÊÉ« | SO2¾ßÓÐƯ°×ÐÔ |
¢Û | ________________________ | ·´Ó¦µÄÀë×Ó·½³Ìʽ____________________ |
¢Ü | ÈÜÒº±ä»ë×Ç£¬ÓлÆÉ«³ÁµíÉú³É | SO2+2H2S=3S¡ý+2H2O |
(3)ÓÃSO2Ư°×¹ýµÄʳƷÖÐÒ»°ã²ÐÁôÓÐÑÇÁòËáÑΣ¬¿ÆÑÐС×éÉè¼ÆÁ˼ìÑéʳƷÖÐÊÇ·ñº¬ÓÐÑÇÁòËáÑεļòµ¥·½·¨£º½«Ê³Æ·¼ô³ÉËéÄ©·ÅÈëÉÕ±£¬¼ÓÈëÊÊÁ¿µÄË®£¬¼ÓÈÈÒ»»á¶ù£¬ÀäÈ´ÖÁÊÒΣ¬µÎ¼ÓÑÎËáºÍÊÔ¼ÁA£¬¹Û²ìÒºÌåµÄÑÕÉ«±ä»¯¼È¿É¡£
¢ÙÉÏÊö¼ìÑéÖÐÊÔ¼ÁAÊÇ_____________¡£
¢Ú¼ÓÈȵÄ×÷ÓÃÊǼӿ췴ӦËÙÂÊ(»ò¼Ó¿ìʳƷµÄÈܽâ)£¬¼ÓÈÈʱ¼ä²»ÄÜÌ«³¤µÄÔÒòÊÇ_________________________________________________________________¡£