ÌâÄ¿ÄÚÈÝ

ÏÖÓÐÒ»¿éÒÑÖªÖÊÁ¿µÄÂÁþºÏ½ð£¬Óû²â¶¨ÆäÖÐþµÄÖÊÁ¿·ÖÊý£¬¼¸Î»Í¬Ñ§Éè¼ÆÁËÒÔÏÂÈýÖÖ²»Í¬µÄʵÑé·½°¸

ʵÑéÉè¼Æ1£ºÂÁþºÏ½ð²â¶¨Éú³ÉµÄÆøÌåÔÚ±ê×¼×´¿öϵÄÌå»ý

ʵÑéÉè¼Æ2£ºÂÁþºÏ½ð²â¶¨Éú³ÉµÄÆøÌåÔÚ±ê×¼×´¿öϵÄÌå»ý

ʵÑéÉè¼Æ3£ºÂÁþºÏ½ðÈÜÒº¹ýÂË£¬²â¶¨µÃµ½³ÁµíµÄÖÊÁ¿

ÔòÄܲⶨ³öþµÄÖÊÁ¿·ÖÊýµÄÊÇ£¨ £©

A£®¶¼ÄÜ B£®¶¼²»ÄÜ C£® ¢Ù²»ÄÜ£¬ÆäËü¶¼ÄÜ D£® ¢Ú¢Û²»ÄÜ£¬ ¢ÙÄÜ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ÑÇÏõËáÄÆ£¨NaNO2)ÊÇÒ»ÖÖ³£¼ûµÄʳƷÌí¼Ó¼Á£¬Ê¹ÓÃʱ±ØÐëÑϸñ¿ØÖÆÆäÓÃÁ¿¡£Ä³ÐËȤС×éÓÃÈçͼËùʾװÁDÖƱ¸NaNO2²¢¶ÔÆäÐÔÖÊ×÷ÈçÏÂ̽¾¿(AÖмÓÈÈ×°ÁDÒÑÂÔÈ¥£©¡£

ÒÑÖª£º

¢Ù 2NO+Na2O2=2NaNO2¡£

¢Ú NOÄܱ»ËáÐÔKMnO4Ñõ»¯³ÉNO3-£¬MnO4-±»»¹Ô­ÎªMn2+¡£

¢Û ÔÚËáÐÔÌõ¼þÏ£¬NaNO2Äܽ«I-Ñõ»¯ÎªI2£»S2O32-Äܽ«I2»¹Ô­ÎªI-¡£

¢Ü ÔÚ´ËÌõ¼þÏ£¬Na2O2ÍêÈ«·´Ó¦£¬ÎÞÊ£Óà¡£

¡¾ÖƱ¸NaNO2¡¿

£¨1£© ×°ÖÃAµÄÈý¾±ÉÕÆ¿Öз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_____________¡£

£¨2£© ×°ÖÃBÖÐË®ºÍÍ­µÄ×÷Ó÷ֱðÊÇ__________¡¢__________¡£

£¨3£© ΪÁ˱£Ö¤ÖƵÃÑÇÏõËáÄƵĴ¿¶È£¬×°ÖÃCÖÐÊ¢·ÅµÄÊÔ¼Á¿ÉÄÜÊÇ_________(Ìî×Öĸ£©¡£

A£®P2O5 B£®¼îʯ»Ò C£®ÎÞË®CaCl2 D£®NaCl

£¨4£© ×°ÖÃEµÄ×÷ÓÃÊÇ_______________¡£

¡¾²â¶¨NaNO2´¿¶È¡¿

£¨5£© ¿É¹©Ñ¡ÔñµÄÊÔ¼ÁÓУº

A£®Ï¡ÁòËá b£®c1mol/LKIÈÜÒº C£®µí·ÛÈÜÒº D£®c2mol/LNa2S2O3ÈÜÒº e£®c3 mol/LËáÐÔKMnO4ÈÜÒº

¢Ù ÀûÓÃNaNO2µÄ»¹Ô­ÐÔÀ´²â¶¨Æä´¿¶È£¬¿ÉÑ¡ÔñµÄÊÔ¼ÁÊÇ________(Ìî×Öĸ)¡£

¢Ú ÀûÓÃNaNO2µÄÑõ»¯ÐÔÀ´²â¶¨Æä´¿¶ÈµÄ²½ÖèÈçÏ£º

׼ȷ³ÆÈ¡ÖÊÁ¿Îªm gµÄNaNO2ÑùÆ·£¬·ÅÈë׶ÐÎÆ¿ÖУ¬¼ÓÈëÊÊÁ¿Ë®Èܽ⣬_________(Çë²¹³äÍêÕûʵÑé²½Ö裩¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø