ÌâÄ¿ÄÚÈÝ

17£®¢ñÒÑÖª»¯Ñ§·´Ó¦¢Ù£ºFe£¨s£©+CO2£¨g£©?FeO£¨s£©+CO£¨g£©£¬Æäƽºâ³£ÊýΪK1£»»¯Ñ§·´Ó¦¢Ú£ºFe£¨s£©+H2O£¨g£©?FeO£¨s£©+H2£¨g£©£¬Æäƽºâ³£ÊýΪK2£®ÔÚζÈ973KºÍ1173KÇé¿öÏ£¬K1¡¢K2µÄÖµ·Ö±ðÈç±í£º
ζÈK1K2
973K1.472.33
1173K2.151.67
£¨1£©Í¨¹ý±í¸ñÖеÄÊýÖµ¿ÉÒÔÍƶϣº·´Ó¦¢ÙÊÇÎüÈÈ£¨Ìî¡°ÎüÈÈ¡±»ò¡°·ÅÈÈ¡±£©·´Ó¦£®
£¨2£©ÏÖÓз´Ó¦¢Û£ºCO2£¨g£©+H2£¨g£©?CO£¨g£©+H2O£¨g£©£¬ÇëÄãд³ö¸Ã·´Ó¦µÄƽºâ³£ÊýK3µÄÊýѧ
±í´ïʽ£ºK3=$\frac{[CO]•[{H}_{2}O]}{[{H}_{2}]•[C{O}_{2}]}$£®
£¨3£©¸ù¾Ý·´Ó¦¢ÙÓë¢Ú¿ÉÍƵ¼³öK1¡¢K2ÓëK3Ö®¼äµÄ¹ØϵʽK3=$\frac{{K}_{1}}{{K}_{2}}$£®¸ù¾Ý´Ë¹Øϵʽ¼°±í¸ñÊý¾Ý£¬Ò²ÄÜÍƶϳö·´Ó¦¢ÛÊÇÎüÈÈ£¨Ìî¡°ÎüÈÈ¡±»ò¡°·ÅÈÈ¡±£©·´Ó¦£®
¢òÔÚÒ»ÃܱÕÈÝÆ÷Öз¢Éú·´Ó¦N2+3H2?2NH3¡÷H£¼0£¬´ïµ½Æ½ºâºó£¬Ö»¸Ä±äijһ¸öÌõ¼þʱ£¬·´Ó¦ËÙÂÊÓ뷴Ӧʱ¼äµÄ¹ØϵÈçͼËùʾ£º»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©´¦ÓÚƽºâ״̬µÄʱ¼ä¶ÎÊÇACDF£¨ÌîÑ¡Ïî×Öĸ£©£®
A£®t0¡«t1¡¡ B£®t1¡«t2 C£®t2¡«t3 D£®t3¡«t4¡¡ E£®t4¡«t5  F£®t5¡«t6
£¨2£©t1¡¢t3¡¢t4ʱ¿Ì·Ö±ð¸Ä±äµÄÒ»¸öÌõ¼þÊÇ£¨ÌîÑ¡Ï£®
A£®Ôö´óѹǿ   B£®¼õСѹǿ   C£®Éý¸ßζȠ D£®½µµÍζȡ¡ E£®¼Ó´ß»¯¼Á¡¡ F£®³äÈ뵪Æø
t1ʱ¿ÌC£»t4ʱ¿ÌB£®
£¨3£©ÒÀ¾Ý£¨2£©ÖеĽáÂÛ£¬ÏÂÁÐʱ¼ä¶ÎÖУ¬°±µÄ°Ù·Öº¬Á¿×îµÍµÄÊÇD£¨ÌîÑ¡Ïî×Öĸ£©£®
A£®t0¡«t1¡¡B£®t2¡«t3 C£®t3¡«t4  D£®t5¡«t6£®

·ÖÎö ¢ñ¡¢£¨1£©¸ù¾ÝζÈÉý¸ßƽºâ³£ÊýµÄ±ä»¯Åжϣ»
£¨2£©ÒÀ¾Ýƽºâ³£Êý¸ÅÄîд³ö·´Ó¦µÄƽºâ³£Êý¼ÆËãʽ£»
£¨3£©ÀûÓøÇ˹¶¨ÂɼÆËãƽºâ³£ÊýÖ®¼äµÄ¹Øϵ£»
¢ò¡¢£¨1£©¸ù¾Ýͼʾ½áºÏvÕý=vÄ棬ÅжÏÊÇ·ñ´¦ÓÚƽºâ״̬£»
£¨2£©ÓÉͼ¿ÉÖª£¬t1ÕýÄæ·´Ó¦ËÙÂʾùÔö´ó£¬ÇÒÄæ·´Ó¦ËÙÂÊ´óÓÚÕý·´Ó¦ËÙÂÊ£»t4ʱÕýÄæ·´Ó¦ËÙÂʾù¼õС£¬ÇÒÄæ·´Ó¦ËÙÂÊ´óÓÚÕý·´Ó¦ËÙÂÊ£»
£¨3£©ÓÉͼ¿ÉÖª£¬t1ƽºâÄæÏòÒƶ¯£¬t3²»Òƶ¯£¬t4ƽºâÄæÏòÒƶ¯£¬¸ù¾ÝÒƶ¯½á¹û·ÖÎö£®

½â´ð ½â£º¢ñ¡¢£¨1£©ÓɱíÖÐÊý¾Ý¿ÉÖª£¬Î¶ÈÉý¸ß£¬¢ÙµÄƽºâ³£ÊýÔö´ó£¬ËµÃ÷ƽºâÏòÕý·´Ó¦·½ÏòÒƶ¯£¬ÔòÕý·´Ó¦ÎüÈÈ£¬
¹Ê´ð°¸Îª£ºÎüÈÈ£»
£¨2£©ÒÀ¾Ý·´Ó¦CO2£¨g£©+H2£¨g£©=CO£¨g£©+H2O£¨g£©£¬¸ù¾Ýƽºâ³£ÊýµÄ¸ÅÄ¸Ã·´Ó¦µÄƽºâ³£ÊýK3µÄÊýѧ±í´ïʽ£ºK=$\frac{[CO]•[{H}_{2}O]}{[{H}_{2}]•[C{O}_{2}]}$£¬¹Ê´ð°¸Îª£º$\frac{[CO]•[{H}_{2}O]}{[{H}_{2}]•[C{O}_{2}]}$£»
£¨3£©ÒÑÖª£º¢ÙFe£¨s£©+CO2£¨g£©?FeO£¨s£©+CO£¨g£©£»
¢ÚFe£¨s£©+H2O£¨g£©?FeO£¨s£©+H2£¨g£©£»
ÀûÓøÇ˹¶¨Âɽ«¢Ù-¢Ú¿ÉµÃ£º¢ÛH2£¨g£©+CO2£¨g£©?CO£¨g£©+H2O£¨g£©£»
ÔòK3=$\frac{[CO]•[{H}_{2}O]}{[{H}_{2}]•[C{O}_{2}]}$=$\frac{{K}_{1}}{{K}_{2}}$£¬ÒÀ¾Ýͼ±íƽºâ³£ÊýÊý¾Ý·ÖÎö£¬Î¶ÈÉý¸ß$\frac{{K}_{1}}{{K}_{2}}$Ôö´ó£¬ËµÃ÷ƽºâÕýÏò½øÐУ¬·´Ó¦ÊÇÎüÈÈ·´Ó¦£»
¹Ê´ð°¸Îª£ºK3=$\frac{{K}_{1}}{{K}_{2}}$£»ÎüÈÈ£»
¢ò¡¢£¨1£©¸ù¾Ýͼʾ¿ÉÖª£¬t0¡«t1¡¢t2¡«t3¡¢t3¡«t4¡¢t5¡«t6ʱ¼ä¶ÎÄÚ£¬vÕý¡¢vÄæÏàµÈ£¬·´Ó¦´¦ÓÚƽºâ״̬£¬¹Ê´ð°¸Îª£ºACDF£»
£¨2£©ÓÉN2£¨g£©+3H2£¨g£©?2NH3£¨g£©¡÷H£¼0£¬¿ÉÖª£¬¸Ã·´Ó¦Îª·ÅÈÈ·´Ó¦£¬ÇÒΪÆøÌåÌå»ý¼õСµÄ·´Ó¦£¬ÔòÓÉͼ¿ÉÖª£¬t1ÕýÄæ·´Ó¦ËÙÂʾùÔö´ó£¬ÇÒÄæ·´Ó¦ËÙÂÊ´óÓÚÕý·´Ó¦ËÙÂÊ£¬¸Ä±äÌõ¼þӦΪÉý¸ßζȣ»
t4ʱÕýÄæ·´Ó¦ËÙÂʾù¼õС£¬ÇÒÄæ·´Ó¦ËÙÂÊ´óÓÚÕý·´Ó¦ËÙÂÊ£¬¸Ä±äÌõ¼þӦΪ¼õСѹǿ£¬
¹Ê´ð°¸Îª£ºC£»B£»
£¨3£©ÓÉͼ¿ÉÖª£¬t1ƽºâÄæÏòÒƶ¯£¬t3²»Òƶ¯£¬t4ƽºâÄæÏòÒƶ¯£¬¾ùʹ°±ÆøµÄº¬Á¿¼õÉÙ£¬Ôòt0¡«t1°±ÆøµÄº¬Á¿×î´ó£¬t5¡«t6°±ÆøµÄº¬Á¿×îС£®
¹Ê´ð°¸Îª£ºD£®

µãÆÀ ±¾Ì⿼²é»¯Ñ§Æ½ºâÓ°ÏìÒòËصķÖÎöÅжϣ¬Æ½ºâ³£ÊýµÄ¼ÆËãÓ¦Óã¬Êý¾Ý´¦ÀíµÄÄÜÁ¦£¬ÌâÄ¿ÄѶÈÖеȣ®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø