ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÊµÑéÊÒÓûÀûÓÃ̼ËáÄƾ§Ìå(Na2CO3¡¤10H2O)À´ÅäÖÆ0.5mol©qL-1µÄ̼ËáÄÆÈÜÒº1000mL¡£»Ø´ðÏÂÁÐÎÊÌâ
(1)ÐèÒª³ÆÁ¿Ì¼ËáÄƾ§ÌåµÄÖÊÁ¿Îª___________g£¬ËùÑ¡ÓÃÈÝÁ¿Æ¿µÄ¹æ¸ñΪ___________ mL¡£
(2)Ï´µÓ²Ù×÷ÖУ¬½«Ï´µÓÉÕ±ºóµÄÈÜÒºÒ²×¢ÈëÈÝÁ¿Æ¿£¬ÆäÄ¿µÄÊÇ__________________________________¡£
(3)¶¨ÈݵÄÕýÈ·²Ù×÷ÊǼÌÐø¼ÓÕôÁóË®ÖÁÀë¿Ì¶ÈÏßÏÂ1~2cmʱ£¬¸ÄÓÃ_________¼ÓË®ÖÁÒºÃæÓë¿Ì¶ÈÏßÏàÇС£
(4)ÓýºÍ·µÎ¹ÜÍùÈÝÁ¿Æ¿ÖмÓˮʱ£¬²»Ð¡ÐÄÒºÃ泬¹ýÁ˿̶ȣ¬´¦ÀíµÄ·½·¨ÊÇ__________(Ìî×Öĸ)¡£
a.ÖØÐÂÅäÖÆ
b.Îü³ö¶àÓàÒºÌ壬ʹ°¼ÒºÃæÓë¿Ì¶ÈÏßÏàÇÐ
c.¾¼ÆËã¼ÓÈëÒ»¶¨Á¿µÄ̼ËáÄƾ§Ìå
d.СÐļÓÈÈÈÝÁ¿Æ¿£¬¾Õô·¢ºó£¬Ê¹°¼ÒºÃæÓë¿Ì¶ÈÏßÏàÇÐ
(5)ÅäÖÆʱÏÂÁвÙ×÷»áµ¼ÖÂËùÅäÈÜҺŨ¶ÈÆ«¸ßµÄÊÇ_____________(Ìî×Öĸ)¡£
a.ת´«ÒÆʱÓÐÉÙÁ¿ÈÜÒº½¦³ö
b.¶¨ÈÝʱ¸©ÊÓ¶ÁÈ¡¿Ì¶È
c.ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºóδ¸ÉÔï
d.¶¨ÈÝʱҺÃ泬¹ýÁ˿̶ÈÏß
(6)´ÓÉÏÊöÅäÖƵÄÈÜÒºÖÐÈ¡³ö10mL£¬ÆäÖк¬Na2CO3µÄÖÊÁ¿ÊÇ_____________g¡£
¡¾´ð°¸¡¿143.0 1000 ʹÈÜÖÊÍêȫתÒƵ½ÈÝÁ¿Æ¿ÖÐ ½ºÍ·µÎ¹Ü a b 0.53
¡¾½âÎö¡¿
¸ù¾ÝÈÜÒºÅäÖƵIJÙ×÷²½Öè·ÖÎö½âÌ⣻½áºÏc=·ÖÎöÎó²î¡£
(1) ÒòÅäÖÆ0.5mol©qL-1µÄ̼ËáÄÆÈÜÒº1000mL£¬ÔòNa2CO3µÄÎïÖʵÄÁ¿n=cV=1L¡Á0.5molL-1=0.5mol£¬Na2CO310H2OµÄÎïÖʵÄÁ¿µÈÓÚNa2CO3µÄÎïÖʵÄÁ¿£¬ËùÒÔNa2CO310H2OµÄÖÊÁ¿0.5mol¡Á286g/mol=143.0g£¬ËùÑ¡ÓÃÈÝÁ¿Æ¿µÄ¹æ¸ñΪ1000mL£»
(2) ÒÀ¾Ýc=¿ÉÖª£¬ÒªÊ¹ÅäÖÆÈÜҺŨ¶È׼ȷ£¬ÔòÐèÒªÈÜÖÊÈ«²¿×ªÒƵ½ÈÝÁ¿Æ¿ÖУ¬ËùÒÔÏ´µÓ²Ù×÷ÖУ¬½«Ï´µÓÉÕ±ºóµÄÈÜÒºÒ²×¢ÈëÈÝÁ¿Æ¿£¬ÆäÄ¿µÄÊÇʹÈÜÖÊÍêȫתÒƵ½ÈÝÁ¿Æ¿ÖУ»
(3) ¶¨ÈݵÄÕýÈ·²Ù×÷ÊǼÌÐø¼ÓÕôÁóË®ÖÁÀë¿Ì¶ÈÏßÏÂ1-2cmʱ£¬¸ÄÓýºÍ·µÎ¹Ü¼ÓË®ÖÁÒºÃæÓë¿Ì¶ÈÏßÏàÇУ»
(4) ÓýºÍ·µÎ¹ÜÍùÈÝÁ¿Æ¿ÖмÓˮʱ£¬²»Ð¡ÐÄÒºÃ泬¹ýÁ˿̶ȣ¬µ¼ÖÂʵÑéʧ°Ü£¬ÎÞ·¨²¹¾È£¬ÐèÒªÖØÐÂÅäÖÆ,¹Ê´ð°¸Îªa£»
(5) a£®×ªÒÆʱÓÐÉÙÁ¿ÈÜÒº½¦³ö£¬µ¼Ö²¿·ÖÈÜÖÊËðºÄ£¬ÈÜÖʵÄÎïÖʵÄÁ¿Æ«Ð¡£¬ÈÜҺŨ¶ÈÆ«µÍ£¬¹Êa´íÎó£»
b£®¶¨ÈÝʱ¸©ÊÓ¶ÁÈ¡¿Ì¶È£¬µ¼ÖÂÈÜÒºÌå»ýƫС£¬ÈÜҺŨ¶ÈÆ«¸ß£¬¹ÊbÕýÈ·£»
c£®ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºóδ¸ÉÔ¶ÔÈÜÖʵÄÎïÖʵÄÁ¿ºÍÈÜÒºÌå»ý¶¼²»²úÉúÓ°Ï죬ÈÜҺŨ¶È²»±ä£¬¹Êc´íÎó£»
d£®¶¨ÈÝʱҺÃ泬¹ýÁ˿̶ÈÏߣ¬µ¼ÖÂÈÜÒºÌå»ýÆ«´ó£¬ÈÜҺŨ¶ÈÆ«µÍ£¬¹Êd´íÎó£»
¹Ê´ð°¸Îªb£»
(6) ÈÜÒº¾ßÓоùÒ»ÐÔ£¬Å¨¶ÈÓëÌå»ýÎ޹أ¬ËùÒÔ´ÓÉÏÊöÅäÖƵÄÈÜÒºÖÐÈ¡³ö10mL£¬ÆäÖÐNa2CO3µÄÎïÖʵÄÁ¿Å¨¶ÈÊÇ0.5mol/L£¬º¬Ì¼ËáÄƵÄÖÊÁ¿Îª£º0.01L¡Á0.5mol/L¡Á106g/mol=0.53g¡£
