ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿µÎ¶¨ÊµÑéÊÇ»¯Ñ§Ñ§¿ÆÖÐÖØÒªµÄ¶¨Á¿ÊµÑé¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ëá¼îÖк͵ζ¨¡ª¡ªÓÃŨ¶ÈΪ0.1000mol¡¤L£­1µÄ±ê×¼ÑÎËáµÎ¶¨Î´ÖªÅ¨¶ÈµÄNaOHÈÜÒº£¬±í¸ñÖмǼÁËʵÑéÊý¾Ý£º

µÎ¶¨´ÎÊý

´ý²âÒºÌå»ý(mL)

±ê×¼ÑÎËáÌå»ý(mL)

µÎ¶¨Ç°¶ÁÊý

µÎ¶¨ºó¶ÁÊý

µÚÒ»´Î

20.00

0.50

20.40

µÚ¶þ´Î

20.00

3.00

23.00

µÚÈý´Î

20.00

4.00

24.10

¢ÙÏÂÁвÙ×÷Ôì³É²â¶¨½á¹ûÆ«¸ßµÄÊÇ________(ÌîÑ¡Ïî×Öĸ)

A£®µÎ¶¨ÖÕµã¶ÁÊýʱ£¬¸©Êӵζ¨¹Ü¿Ì¶È£¬ÆäËû²Ù×÷ÕýÈ·¡£

B£®Ê¢×°Î´ÖªÒºµÄ׶ÐÎÆ¿ÓÃÕôÁóˮϴ¹ý£¬Î´ÓÃδ֪ҺÈóÏ´

C£®ËáʽµÎ¶¨¹ÜÓÃÕôÁóˮϴ¾»ºó£¬Î´Óñê×¼ÑÎËáÈóÏ´

D£®µÎ¶¨Ç°£¬Ê¢×°±ê×¼ÒºµÄµÎ¶¨¹Ü¼â×ìÓÐÆøÅÝ£¬µÎ¶¨ºóÆøÅÝÏûʧ

¢Ú¸ÃNaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ_____________mol/L¡££¨Ð¡Êýµãºó±£ÁôËÄλÓÐЧÊý×Ö£©

£¨2£©Ñõ»¯»¹Ô­µÎ¶¨¡ª¡ªÈ¡Ò»¶¨Á¿µÄ²ÝËᣨH2C2O4£©ÈÜÒºÖÃÓÚ׶ÐÎÆ¿ÖУ¬¼ÓÈëÊÊÁ¿Ï¡ÁòËᣬÓñê×¼ËáÐÔ¸ßÃÌËá¼ØÈÜÒºµÎ¶¨¡£µÎ¶¨Ê±KMnO4ÈÜҺӦװÔÚ______________(Ìî¡°Ëᡱ»ò¡°¼î¡±)ʽµÎ¶¨¹ÜÖУ¬µÎ¶¨ÖÕµãʱµÎ¶¨ÏÖÏóÊÇ_________________________________¡£

£¨3£©³ÁµíµÎ¶¨¨D¨DµÎ¶¨¼ÁºÍ±»µÎ¶¨ÎïµÄÉú³ÉÎï±ÈµÎ¶¨¼ÁÓëָʾ¼ÁµÄÉú³ÉÎï¸üÄÑÈÜ¡£²Î¿¼±íÖеÄÊý¾Ý£¬ÈôÓÃAgNO3µÎ¶¨NaSCNÈÜÒº£¬¿ÉÑ¡ÓõÄָʾ¼ÁÊÇ______(ÌîÑ¡Ïî×Öĸ)¡£

ÄÑÈÜÎï

AgCl

AgBr

AgCN

Ag2CrO4

AgSCN

ÑÕÉ«

°×

dzȮ

°×

שºì

°×

Ksp

1.77¡Á10£­10

5.35¡Á10£­13

1.21¡Á10£­16

1.12¡Á10£­12

1.0¡Á10£­12

A£®NaClB£®NaBrC£®NaCND£®Na2CrO4

¡¾´ð°¸¡¿CD 0.1000mol/L Ëá µÎÈë×îºóÒ»µÎ±ê×¼Òººó£¬×¶ÐÎÆ¿ÖÐÈÜÒºÓÉÎÞÉ«±äΪ×ϺìÉ«£¬ÇÒ°ë·ÖÖÓÄÚ²»ÍÊÉ« D

¡¾½âÎö¡¿

(1)¢ÙA£®µÎ¶¨ÖÕµã¶ÁÊýʱ£¬¸©Êӵζ¨¹Ü¿Ì¶È£¬µ¼Ö¶ÁÈ¡µÄ±ê×¼ÒºÌå»ýƫС£¬²â¶¨½á¹ûƫС£¬²»·ûºÏÌâÒ⣻

B£®Ê¢×°Î´ÖªÒºµÄ׶ÐÎÆ¿ÓÃÕôÁóˮϴ¹ý£¬Î´ÓÃδ֪ҺÈóÏ´²»»áÓ°ÏìÏûºÄµÄ±ê×¼ÒºÌå»ý£¬ËùÒÔ¶Ô½á¹ûÎÞÓ°Ï죬²»·ûºÏÌâÒ⣻

C£®ËáʽµÎ¶¨¹ÜÓÃÕôÁóˮϴ¾»ºó£¬Î´Óñê×¼ÑÎËáÈóÏ´£¬½«»áÏ¡Êͱê×¼Òº£¬µ¼Ö¶ÁÈ¡µÄ±ê×¼ÒºÌå»ýÆ«´ó£¬²â¶¨½á¹ûÆ«¸ß£¬·ûºÏÌâÒ⣻

D£®µÎ¶¨Ç°£¬Ê¢×°±ê×¼ÒºµÄµÎ¶¨¹Ü¼â×ìÓÐÆøÅÝ£¬µÎ¶¨ºóÆøÅÝÏûʧ£¬Ôò¶ÁÈ¡µÄ±ê×¼ÒºÌå»ýÆ«´ó£¬²â¶¨½á¹ûÆ«´ó£¬·ûºÏÌâÒ⣻

×ÛÉÏËùÊöÑ¡CD£»

¢Ú¸ù¾Ý±í¸ñ£¬µÚÒ»´ÎÏûºÄ±ê×¼ÒºÌå»ýΪ20.40mL-0.50mL=19.90mL£¬µÚ¶þ´ÎÏûºÄ±ê×¼ÒºÌå»ýΪ23.00mL-3.00mL=20.00mL£¬µÚÈý´ÎÏûºÄ±ê×¼ÒºÌå»ýΪ24.10mL-4.00mL=20.10mL£¬ËùÒÔÈý´ÎµÎ¶¨ÏûºÄµÄHCl±ê׼Һƽ¾ùÌå»ýΪ20.00mL£¬ÔòNaOHÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪc==0.1000mol/L£»

(2)ËáÐÔ¸ßÃÌËá¼ØÈÜÒºÏÔËáÐÔ£¬ÇÒ¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬ËùÒÔ×°ÔÚËáʽµÎ¶¨¹ÜÖУ»µÎ¶¨ÖÕµãʱËáÐÔ¸ßÃÌËá¼ØÈÜÒº¹ýÁ¿£¬ÈÜÒº±äΪ×ϺìÉ«£¬ËùÒÔÏÖÏóΪ£ºµÎÈë×îºóÒ»µÎ±ê×¼Òººó£¬×¶ÐÎÆ¿ÖÐÈÜÒºÓÉÎÞÉ«±äΪ×ϺìÉ«£¬ÇÒ°ë·ÖÖÓÄÚ²»ÍÊÉ«£»

(3)ÈôÓÃAgNO3È¥µÎ¶¨NaSCNÈÜÒº£¬¿ÉÑ¡Óõĵζ¨Ö¸Ê¾¼ÁµÄÎïÖʵÄÈܽâ¶ÈÓ¦±ÈAgSCN´ó£¬AgCl¡¢AgBr¡¢AgCNºÍAgSCN¾ùΪͬÀàÐͳÁµí£¬Ö»ÓÐAgClµÄÈܶȻý±ÈAgSCN´ó£¬µ«AgClͬΪ°×É«³Áµí£¬ÏÖÏó²»Ã÷ÏÔ£¬ËùÒÔÈýÖÖ³ÁµíÏàÓ¦µÄÑξù²»ºÏÊÊ£¬Ag2CrO4ÓëAgSCNÈܶȻýÏà²î²»´ó£¬µ«Ag2CrO4ΪA2BÐͳÁµí£¬ËùÒÔAg2CrO4µÄÈܽâ¶ÈÒª±ÈAgSCNµÄÈܽâ¶ÈС£¬ÇÒΪשºìÉ«£¬ÏÖÏóÃ÷ÏÔ£¬ËùÒÔ¿ÉÒÔÑ¡Na2CrO4×÷ָʾ¼Á£¬¼´Ñ¡D¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿»¯Ñ§ÓëÈËÀàÉú»îÃÜÇÐÏà¹Ø¡£Çë°´ÒªÇ󣬻شðÏÂÁÐÎÊÌ⣺

£¨1£©´ºÇïÄ©ÆÚ¹¤ÒÕ¹ÙÊ顶¿¼¹¤¼Ç¡·ÖмÇÔØÓС°ä³²¯¡±µÄ·½·¨£¬¼´ÀûÓú¬ÓÐ̼ËáÄƵÄË®ÈÜÒºÀ´Ï´µÓË¿²¯¡£Çëд³ö̼ËáÄÆË®ÈÜÒºÖÐͨÈëCO2ÆøÌåµÄ»¯Ñ§·½³Ìʽ____£¬½«54.8g Na2CO3ºÍNaHCO3 µÄ»ìºÏÎï·Ö³ÉµÈÁ¿µÄÁ½·Ý£¬Ò»·ÝÈÜÓÚË®ºó¼ÓÈë×ãÁ¿ÑÎËᣬÊÕ¼¯µ½ÆøÌåV L£¬ÁíÒ»·ÝÖ±½Ó¼ÓÈÈÖÁºãÖØ£¬Éú³ÉÆøÌå2.24L£¨ËùÓÐÆøÌåÌå»ý¾ùÔÚ±ê×¼×´¿öϲⶨ£©£¬ÔòÔ­¹ÌÌå»ìºÏÎïÖÐNa2CO3µÄÎïÖʵÄÁ¿£ºn£¨Na2CO3£©£½____£¬ÆøÌåV£½____¡£

£¨2£©¡°84¡±Ïû¶¾ÒºÔÚÉú»îÖÐʹÓù㷺£¬ÆäÓÐЧ³É·ÖÊÇ´ÎÂÈËáÄÆ¡£¿ÉÔÚ³£ÎÂϽ«ÂÈÆøͨÈëNaOHÈÜÒºÖƵ㬸÷´Ó¦µÄÀë×Ó·½³ÌʽΪ____£¬ÈôÓÐ2molÂÈÆø²ÎÓë¸Ã·´Ó¦£¬Ôò´ËʱתÒƵĵç×ÓÊýΪ____NA¡£

£¨3£©Ð¡ËÕ´ò¿ÉÓÃÓÚÖÎÁÆθËá¹ý¶à£¬Æä·´Ó¦µÄÀë×Ó·½³ÌʽΪ____¡£

£¨4£©³¤Ê¯ÊǵرíÑÒʯ×îÖØÒªµÄÔìÑÒ¿óÎijÖÖ³¤Ê¯µÄ»¯Ñ§×é³ÉKAlSi3O8Ôò½«Æä¸Äд³ÉÑõ»¯ÎïµÄ×éºÏÐÎʽΪ____¡£

£¨5£©ÆÏÌÑÌÇ(·Ö×ÓʽC6H12O6)ÊÇÈËÌå»îϸ°ûµÄÄÜÁ¿À´Ô´¡£ÒÑÖª1molµÈÓÚ1000mmol£¬Ä³Ìå¼ìµ¥µÄһЩָ±êÈçͼ£¬ÔòÿÉý¸ÃÑùÆ·Öк¬ÆÏÌÑÌǵÄÖÊÁ¿Îª____g£¨Çë±£ÁôÁ½Î»Ð¡Êý£©¡£

9

°×Çò±È

1.6

10

ÈéËáÍÑÇâø

161

U/L

11

Á×ËἡËἤø

56

U/L

12

¸ÊÓÍÈýõ¥

0.52

mmol/L

13

×ܵ¨¹Ì´¼

4.27

mmol/L

14

¸ßÃܶÈÖ¬µ°°×µ¨¹Ì´¼

1.57

mmol/L

15

µÍÃܶÈÖ¬µ°°×µ¨¹Ì´¼

1.40

mmol/L

16

ÆÏÌÑÌÇ

4.94

mmol/L

¡¾ÌâÄ¿¡¿°´ÒªÇó»Ø´ðÏÂÁÐÎÊÌâ¡£

I.ÎåÖÖÔªËصÄÔ­×Óµç×Ó²ã½á¹¹ÈçÏ£ºA£º1s22s22p63s23p63d54s2¡¢B£º1s22s22p63s2¡¢C£º1s22s22p6¡¢D£º1s22s22p63s23p2¡¢E£º[Ar]4s1¡£

Çë»Ø´ð£º(ÌîÔªËØ·ûºÅ)

£¨1£©________ÔªËØÊÇÏ¡ÓÐÆøÌå¡£º¬Î´³É¶Ôµç×ÓÊý×î¶àµÄÔªËØÊÇ________¡£

£¨2£©AÔªËØÔ­×ӵĺËÍâµç×Ó¹²ÓÐ________ÖÖÔ˶¯×´Ì¬£¬ÄÜÁ¿×î¸ßµÄÄܼ¶ÊÇ________£¨ÌîÄܼ¶·ûºÅ£©¡£

£¨3£©DÔªËØÔ­×ӵļ۲ãµç×ÓÅŲ¼Í¼ÊÇ________¡£

£¨4£©________ÔªËصĵ縺ÐÔ×î´ó£¬________ÔªËØÔ­×ӵĵÚÒ»µçÀëÄÜ×î´ó£¬________ÔªËØ×î¿ÉÄÜÉú³É¾ßÓд߻¯ÐÔÖʵÄÑõ»¯Îï¡£

II.Q¡¢R¡¢X¡¢Y¡¢ZÎåÖÖÔªËصÄÔ­×ÓÐòÊýÒÀ´ÎµÝÔö£¬³ýZÒÔÍ⣬ÆäÓàµÄ¾ùΪ¶ÌÖÜÆÚÖ÷×åÔªËØ¡£ÒÑÖª£º

¢ÙQÔ­×Ó2pÄܼ¶ÉÏÓÐÒ»¸ö¿Õ¹ìµÀ£»

¢ÚRÔ­×ÓºËÍâL²ãµç×ÓÊýΪÆæÊý£»

¢ÛXÔ­×Ó2p¹ìµÀÉÏÖ»ÓÐÒ»¶Ô×ÔÐýÏà·´µÄµç×Ó£»

¢ÜYÔ­×Ó¼Ûµç×Ó£¨ÍâΧµç×Ó£©ÅŲ¼msnmpn£»

¢ÝZÔ­×ÓM²ãËùÓйìµÀÈ«²¿³äÂú£¬N²ãÎ޳ɶԵç×Ó£¬Ö»ÓÐ1¸öδ³É¶Ôµç×Ó¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺

£¨5£©Z2£«µÄºËÍâµç×ÓÅŲ¼Ê½ÊÇ________£¬XÔªËØ»ù̬ԭ×ӵĺËÍâµç×ÓÅŲ¼Í¼ÊÇ____________¡£

£¨6£©QÓëY·Ö±ðÐγɵÄ×î¼òµ¥Æø̬Ç⻯ÎïÖУ¬Îȶ¨ÐÔ¸üÇ¿µÄÊÇ________£¨Ìѧʽ£©¡£

£¨7£©Q¡¢R¡¢X¡¢YÈýÖÖÔªËصĵÚÒ»µçÀëÄÜÊýÖµÓÉ´óµ½Ð¡µÄ˳ÐòΪ________£¨ÓÃÔªËØ·ûºÅ×÷´ð£©¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø