ÌâÄ¿ÄÚÈÝ
»·¾³Öг£¼ûµÄÖؽðÊôÎÛȾÎïÓУº¹¯¡¢Ç¦¡¢ÃÌ¡¢¸õ¡¢ïÓ¡£´¦Àí¹¤Òµ·ÏË®Öк¬ÓеÄCr2O72-ºÍCrO42-£¬³£Óõķ½·¨ÓÐÁ½ÖÖ¡£
·½·¨1¡¡»¹Ô³Áµí·¨
¸Ã·¨µÄ¹¤ÒÕÁ÷³ÌΪ¡£
ÆäÖеڢٲ½´æÔÚƽºâ2CrO42-£¨»ÆÉ«£©£«2H£«Cr2O72-£¨³ÈÉ«£©£«H2O¡£
£¨1£©Ð´³öµÚ¢Ù²½·´Ó¦µÄƽºâ³£Êý±í´ïʽ_________________________________¡£
£¨2£©¹ØÓÚµÚ¢Ù²½·´Ó¦£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ________¡£
A£®Í¨¹ý²â¶¨ÈÜÒºµÄpH¿ÉÒÔÅжϷ´Ó¦ÊÇ·ñÒÑ´ïƽºâ״̬
B£®¸Ã·´Ó¦ÎªÑõ»¯»¹Ô·´Ó¦
C£®Ç¿ËáÐÔ»·¾³£¬ÈÜÒºµÄÑÕɫΪ³ÈÉ«
£¨3£©µÚ¢Ú²½ÖУ¬»¹Ô0.1 mol Cr2O72-£¬ÐèÒª________molµÄFeSO4¡¤7H2O¡£
£¨4£©µÚ¢Û²½³ýÉú³ÉCr£¨OH£©3Í⣬»¹¿ÉÄÜÉú³ÉµÄ³ÁµíΪ________¡£ÔÚÈÜÒºÖдæÔÚÒÔϳÁµíÈܽâƽºâ£ºCr£¨OH£©3£¨s£©Cr3£«£¨aq£©£«3OH££¨aq£©£¬³£ÎÂÏ£¬Cr£¨OH£©3µÄÈܶȻýKsp£½10£32£¬µ±c£¨Cr3£«£©½µÖÁ10£5 mol¡¤L£1ʱ£¬ÈÏΪc£¨Cr3£«£©ÒѾÍêÈ«³Áµí£¬ÏÖ½«µÚ¢Û²½ÈÜÒºµÄpHµ÷ÖÁ4£¬Çëͨ¹ý¼ÆËã˵Ã÷Cr3£«ÊÇ·ñ³ÁµíÍêÈ«£¨Çëд³ö¼ÆËã¹ý³Ì£©£º____________________________________________________________________________¡£
·½·¨2¡¡µç½â·¨
£¨5£©ÊµÑéÊÒÀûÓÃÈçͼװÖÃÄ£Äâµç½â·¨´¦Àíº¬Cr2O72-µÄ·ÏË®£¬µç½âʱÑô¼«·´Ó¦Ê½Îª________£¬Òõ¼«·´Ó¦Ê½Îª________£¬µÃµ½µÄ½ðÊôÑôÀë×ÓÔÚÒõ¼«Çø¿É³ÁµíÍêÈ«£¬´ÓË®µÄµçÀëƽºâ½Ç¶È½âÊÍÆäÔÒòÊÇ___________________________________________________________¡£
£¨1£©K£½
£¨2£©AC
£¨3£©0.6
£¨4£©Fe£¨OH£©3¡¡µ±pHµ÷ÖÁ4ʱ£¬c£¨OH££©£½10£10 mol¡¤L£1£¬c£¨Cr3£«£©£½10£32/c3£¨OH££©£½10£2 mol¡¤L£1£¾10£5 mol¡¤L£1£¬Òò´ËCr3£«Ã»ÓгÁµíÍêÈ«
£¨5£©Fe£2e£=Fe2£«¡¡2H£«£«2e£=H2¡ü¡¡Ñô¼«Éú³ÉµÄ½ðÊôÑôÀë×ÓÏòÒõ¼«Òƶ¯£¬Òõ¼«·´Ó¦ÏûºÄÁËH£«£¬´òÆÆÁËË®µÄµçÀëƽºâ£¬´Ù½øÁËË®µÄµçÀ룬ʹÈÜÒºÖÐOH£µÄŨ¶ÈÔö´ó£¬ÈÜÒºÖ𽥳ʼîÐÔ
¡¾½âÎö¡¿£¨1£©Ï¡ÈÜÒºÖÐH2OµÄŨ¶È¿ÉÊÓΪ³£Êý£¬¹ÊµÚ¢Ù²½·´Ó¦µÄƽºâ³£Êý±í´ïʽΪK£½c£¨Cr2O72-£©/[c2£¨CrO42-£©¡¤c2£¨H£«£©]¡££¨2£©ÓÉ·´Ó¦¢Ù¿ÉÖª£¬Æ½ºâ·¢ÉúÒƶ¯£¬ÈÜÒºµÄpH·¢Éú±ä»¯£¬¹ÊpH²»±äʱ˵Ã÷·´Ó¦´ïµ½Æ½ºâ£¬AÏîÕýÈ·£»CrO42-ºÍCr2O72-ÖÐCr¾ùΪ£«6¼Û£¬¸Ã·´Ó¦²»ÊÇÑõ»¯»¹Ô·´Ó¦£¬BÏî´íÎó£»ÔÚËáÐÔ»·¾³ÖУ¬ÈÜÒºÖÐc£¨Cr2O72-£©½Ï´ó£¬ÈÜÒº³Ê³ÈÉ«£¬CÏîÕýÈ·¡££¨3£©ÔÚµÚ¢Ú²½·´Ó¦ÖÐCr2O72-±»»¹ÔΪCr3£«£¬0.1 mol Cr2O72-±»»¹ÔʱתÒƵç×ÓµÄÎïÖʵÄÁ¿Îª0.1 mol¡Á2¡Á£¨6£3£©£½0.6 mol£¬¶ø»¹Ô¼ÁFe2£«±»Ñõ»¯ÎªFe3£«£¬¹ÊÐèÒªÏûºÄ0.6 mol FeSO4¡¤7H2O¡££¨4£©ÔÚµÚ¢Ú²½·´Ó¦ÖÐFe2£«±»Ñõ»¯ÎªFe3£«£¬¹ÊµÚ¢Û²½»¹ÓÐFe£¨OH£©3Éú³É¡££¨5£©µç½â³ØµÄÑô¼«·¢ÉúÑõ»¯·´Ó¦£¬Fe×÷Ñô¼«£¬ÔòFeµç¼«±¾Éí±»Ñõ»¯£¬¹ÊÑô¼«·´Ó¦Ê½ÎªFe£2e£=Fe2£«£»Òõ¼«ÔòÊǵç½âÖÊÈÜÒºÖеÄH£«µÃµç×Ó£¬·¢Éú»¹Ô·´Ó¦Éú³ÉÇâÆø£¬¹ÊÒõ¼«·´Ó¦Ê½Îª2H£«£«2e£=H2¡ü£»Ñô¼«Éú³ÉµÄ½ðÊôÑôÀë×ÓÒÆÏòÒõ¼«£¬¶øÒõ¼«·´Ó¦ÏûºÄÁËH£«£¬´òÆÆÁËË®µÄµçÀëƽºâ£¬´Ù½øÁËË®µÄµçÀ룬ʹÈÜÒºÖеÄOH£Å¨¶ÈÔö´ó£¬ÈÜÒºÖ𽥳ʼîÐÔ£¬´Ó¶øʹ½ðÊôÑôÀë×ÓÔÚÒõ¼«ÇøÐγɳÁµí¡£
Ìå»ýΪ1 LµÄijÈÜÒºÖк¬ÓеÄÀë×ÓÈç±íËùʾ£º
Àë×Ó | Cu2£« | Al3£« | NO3- | Cl£ |
| 1 | 1 | a | 1 |
ÓÃPtµç¼«µç½â¸ÃÈÜÒº£¬µ±µç·ÖÐÓÐ3 molµç×Óͨ¹ýʱ£¨ºöÂÔµç½âʱÈÜÒºÌå»ýµÄ±ä»¯¼°µç½â²úÎï¿ÉÄÜ´æÔÚµÄÈܽâÏÖÏ󣩣¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ £¨¡¡¡¡£©¡£
A£®µç½âºóÈÜÒºµÄpH£½0
B£®a£½3
C£®Ñô¼«Éú³É1.5 mol Cl2
D£®Òõ¼«Îö³öµÄ½ðÊôÊÇÍÓëÂÁ
½«Ò»¶¨Á¿´¿¾»µÄ°±»ù¼×Ëá粒ÌÌåÖÃÓÚÌØÖƵÄÃܱÕÕæ¿ÕÈÝÆ÷ÖУ¨¼ÙÉèÈÝÆ÷Ìå»ý²»±ä£¬¹ÌÌåÊÔÑùÌå»ýºöÂÔ²»¼Æ£©£¬Ôں㶨ζÈÏÂʹÆä´ïµ½·Ö½âƽºâ£ºNH2COONH4£¨s£© 2NH3£¨g£©£«CO2£¨g£©
ʵÑé²âµÃ²»Í¬Î¶ÈϵÄƽºâÊý¾ÝÁÐÓÚÏÂ±í£º
ζÈ/¡æ | 15.0 | 20.0 | 25.0 | 30.0 | 35.0 |
ƽºâ×Üѹ Ç¿/kPa | 5.7 | 8.3 | 12.0 | 17.1 | 24.0 |
ƽºâÆøÌå×ÜŨ¶È/mol¡¤ L£1 | 2.4¡Á 10£3 | 3.4¡Á 10£3 | 4.8¡Á 10£3 | 6.8¡Á 10£3 | 9.4¡Á 10£3 |
£¨1£©¿ÉÒÔÅжϸ÷ֽⷴӦÒѾ´ïµ½Æ½ºâµÄÊÇ________¡£
A£®2v£¨NH3£©£½v£¨CO2£©
B£®ÃܱÕÈÝÆ÷ÖÐ×Üѹǿ²»±ä
C£®ÃܱÕÈÝÆ÷ÖлìºÏÆøÌåµÄÃܶȲ»±ä
D£®ÃܱÕÈÝÆ÷Öа±ÆøµÄÌå»ý·ÖÊý²»±ä
£¨2£©¸ù¾Ý±íÖÐÊý¾Ý£¬ÁÐʽ¼ÆËã25.0 ¡æʱµÄ·Ö½â·´Ó¦Æ½ºâ³£Êý£º_______________¡£
£¨3£©È¡Ò»¶¨Á¿µÄ°±»ù¼×Ëá粒ÌÌå·ÅÔÚÒ»¸ö´ø»îÈûµÄÃܱÕÕæ¿ÕÈÝÆ÷ÖУ¬ÔÚ25.0 ¡æÏ´ﵽ·Ö½âƽºâ¡£ÈôÔÚºãÎÂÏÂѹËõÈÝÆ÷Ìå»ý£¬°±»ù¼×Ëá粒ÌÌåµÄÖÊÁ¿½«________£¨Ìî¡°Ôö¼Ó¡±¡¢¡°¼õÉÙ¡±»ò¡°²»±ä¡±£©¡£