ÌâÄ¿ÄÚÈÝ
ÌúÊÇÈËÌå²»¿ÉȱÉÙµÄ΢Á¿ÔªËØ£¬ÉãÈ뺬ÌúµÄ»¯ºÏÎï¿É²¹³äÌú¡£¡°ËÙÁ¦·Æ¡±ÊÇÊг¡ÉÏÒ»ÖÖ³£¼ûµÄ²¹ÌúÒ©Æ·£¬Ï±íÊÇ˵Ã÷ÊéµÄ²¿·ÖÄÚÈÝ¡£
£¨1£©¸ÃÒ©Æ·ÖÐFe2+»á»ºÂýÑõ»¯¡£¹ú¼Ò¹æ¶¨¸ÃÒ©ÎïÖÐFe2+µÄÑõ»¯ÂÊ£¨ÒѾ±»Ñõ»¯Fe2+µÄÖÊÁ¿ÓëFe2+×ÜÖÊÁ¿µÄ±ÈÖµ£©³¬¹ý10.00% ¼´²»ÄÜÔÙ·þÓá£
¢ÙʵÑéÊҿɲÉÓÃH2SO4ËữµÄKMnO4ÈÜÒº£¬¶Ô¡°ËÙÁ¦·Æ¡±ÖеÄFe2+½øÐеζ¨(¼ÙÉèÒ©Æ·ÖÐÆäËû³É·Ý²»ÓëKMnO4·´Ó¦)¡£Çëд³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º ¡£
¢ÚʵÑéÇ°£¬Ê×ÏÈÒª¾«È·ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄKMnO4ÈÜÒº250 mL£¬ÅäÖÆʱÐèÒªµÄ²£Á§ÒÇÆ÷³ý²£Á§°ô¡¢ÉÕ±¡¢½ºÍ·µÎ¹ÜÍ⣬»¹Ðè ¡£
¢ÛijͬѧÉè¼ÆÁËÏÂÁеζ¨·½Ê½£¨¼Ð³Ö²¿·ÖÂÔÈ¥£©£¬×îºÏÀíµÄÊÇ ¡££¨Ìî×ÖĸÐòºÅ£©
£¨2£©³ÆÁ¿ÉÏÊöº¬ÌúÔªËØÖÊÁ¿·ÖÊýΪ20.00%µÄ¡°ËÙÁ¦·Æ¡±10.00 g£¬½«ÆäÈ«²¿ÈÜÓÚÏ¡H2SO4ÖУ¬ÅäÖƳÉ1000 mlÈÜÒº£¬È¡³ö20.00 ml£¬ÓÃ0.01000 mol?L-1µÄKMnO4ÈÜÒºµÎ¶¨£¬ÓÃÈ¥KMnO4ÈÜÒº12.00 ml £¬¸ÃÒ©Æ·ÖÐFe2+µÄÑõ»¯ÂÊΪ ¡£
£¨3£©ÒÑÖªçúçêËáΪ¶þÔªÓлúôÈËᣬº¬23.6 gçúçêËáµÄÈÜÒºÓë4.0 mol?L-1 100.0 mlµÄÇâÑõ»¯ÄÆÈÜҺǡºÃÍêÈ«Öк͡£ºË´Å¹²ÕñÇâÆ×·ÖÎöÏÔʾ£¬çúçêËá·Ö×ÓÆ×ͼÉÏÖ»ÓÐÁ½×éÎüÊշ塣д³öçúçêËáÈÜÒºÓëÇâÑõ»¯ÄÆÈÜÒºÍêÈ«Öк͵Ļ¯Ñ§·½³Ìʽ(ÓлúÎïд½á¹¹¼òʽ) ¡£
[¹æ¸ñ]ÿƬº¬çúçêËáÑÇÌú [ÊÊÓ¦Ö¢]ÓÃÓÚȱÌúÐÔƶѪ֢£¬Ô¤·À¼°ÖÎÁÆÓᣠ[ÓÃÁ¿Ó÷¨]³ÉÈËÔ¤·ÀÁ¿/ÈÕ£¬³ÉÈËÖÎÁÆÁ¿¡ª/ÈÕ¡£ С¶ùÓÃÁ¿Ô¤·ÀÁ¿¡ª /ÈÕ£¬ÖÎÁÆÁ¿¡ª/ÈÕ [Öü²Ø]±Ü¹â¡¢ÃÜ·â¡¢ÔÚ¸ÉÔï´¦±£´æ¡£ |
£¨1£©¸ÃÒ©Æ·ÖÐFe2+»á»ºÂýÑõ»¯¡£¹ú¼Ò¹æ¶¨¸ÃÒ©ÎïÖÐFe2+µÄÑõ»¯ÂÊ£¨ÒѾ±»Ñõ»¯Fe2+µÄÖÊÁ¿ÓëFe2+×ÜÖÊÁ¿µÄ±ÈÖµ£©³¬¹ý10.00% ¼´²»ÄÜÔÙ·þÓá£
¢ÙʵÑéÊҿɲÉÓÃH2SO4ËữµÄKMnO4ÈÜÒº£¬¶Ô¡°ËÙÁ¦·Æ¡±ÖеÄFe2+½øÐеζ¨(¼ÙÉèÒ©Æ·ÖÐÆäËû³É·Ý²»ÓëKMnO4·´Ó¦)¡£Çëд³ö¸Ã·´Ó¦µÄÀë×Ó·½³Ìʽ£º ¡£
¢ÚʵÑéÇ°£¬Ê×ÏÈÒª¾«È·ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄKMnO4ÈÜÒº250 mL£¬ÅäÖÆʱÐèÒªµÄ²£Á§ÒÇÆ÷³ý²£Á§°ô¡¢ÉÕ±¡¢½ºÍ·µÎ¹ÜÍ⣬»¹Ðè ¡£
¢ÛijͬѧÉè¼ÆÁËÏÂÁеζ¨·½Ê½£¨¼Ð³Ö²¿·ÖÂÔÈ¥£©£¬×îºÏÀíµÄÊÇ ¡££¨Ìî×ÖĸÐòºÅ£©
£¨2£©³ÆÁ¿ÉÏÊöº¬ÌúÔªËØÖÊÁ¿·ÖÊýΪ20.00%µÄ¡°ËÙÁ¦·Æ¡±10.00 g£¬½«ÆäÈ«²¿ÈÜÓÚÏ¡H2SO4ÖУ¬ÅäÖƳÉ1000 mlÈÜÒº£¬È¡³ö20.00 ml£¬ÓÃ0.01000 mol?L-1µÄKMnO4ÈÜÒºµÎ¶¨£¬ÓÃÈ¥KMnO4ÈÜÒº12.00 ml £¬¸ÃÒ©Æ·ÖÐFe2+µÄÑõ»¯ÂÊΪ ¡£
£¨3£©ÒÑÖªçúçêËáΪ¶þÔªÓлúôÈËᣬº¬23.6 gçúçêËáµÄÈÜÒºÓë4.0 mol?L-1 100.0 mlµÄÇâÑõ»¯ÄÆÈÜҺǡºÃÍêÈ«Öк͡£ºË´Å¹²ÕñÇâÆ×·ÖÎöÏÔʾ£¬çúçêËá·Ö×ÓÆ×ͼÉÏÖ»ÓÐÁ½×éÎüÊշ塣д³öçúçêËáÈÜÒºÓëÇâÑõ»¯ÄÆÈÜÒºÍêÈ«Öк͵Ļ¯Ñ§·½³Ìʽ(ÓлúÎïд½á¹¹¼òʽ) ¡£
£¨1£©¢Ù5Fe2++MnO-4+8H+£½5Fe3++Mn2++4H2O(2·Ö) ¢Ú250mlÈÝÁ¿Æ¿(2·Ö)¢Ûb(2·Ö)
£¨2£©16.00% (3·Ö)
£¨3£©HOOC£CH2CH2£COOH£«2NaOH¡úNaOOC£CH2CH2£COONa£«2H2O (3·Ö)
£¨2£©16.00% (3·Ö)
£¨3£©HOOC£CH2CH2£COOH£«2NaOH¡úNaOOC£CH2CH2£COONa£«2H2O (3·Ö)
ÊÔÌâ·ÖÎö£º£¨1£©¢ÙFe2+¾ßÓл¹ÔÐÔ£¬±¶Ñõ»¯»áÉú³É³ÉFe3+£¬¸ßÃÌËá¼ØÈÜÒº¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬ÄÜÑõ»¯ÑÇÌúÀë×Ó£¬ÆäÖÐMnO4-ÖÐMnµÄ»¯ºÏ¼ÛÓÉ+7¼Û½µÎª+2¼Û£¬±ä»¯5£¬Fe2+ÖÐFeÓÉ+2¼ÛÉýΪ+3¼Û£¬±ä»¯1£¬¸ù¾Ý»¯ºÏ¼ÛÉý½µ×ÜÊýÏàµÈºÍÖÊÁ¿ÊغãµÃ·´Ó¦µÄÀë×Ó·½³ÌʽΪ5Fe2++MnO-4+8H+£½5Fe3++Mn2++4H2O¡£
¢ÚÒª¾«È·ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄKMnO4ÈÜÒº250 mL£¬ÅäÖÆʱÐèÒªµÄ²£Á§ÒÇÆ÷³ý²£Á§°ô¡¢ÉÕ±¡¢½ºÍ·µÎ¹ÜÍ⣬»¹Ðè250mlÈÝÁ¿Æ¿¡£
¢Ûa¡¢¸ßÃÌËá¼ØÈÜÒº¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬Äܸ¯Ê´¼îʽµÎ¶¨¹ÜµÄÏðƤ¹Ü£¬¹Êa´íÎó£»b¡¢¸ßÃÌËá¼ØÈÜÒº¾ßÓÐÇ¿Ñõ»¯ÐÔ£¬Äܸ¯Ê´¼îʽµÎ¶¨¹ÜµÄÏðƤ¹Ü£¬Ó¦ÓÃËáʽµÎ¶¨¹ÜÊ¢×°£¬µÎ¶¨Ê±Îª±ãÓÚ¹Û²ìÑÕÉ«±ä»¯£¬µÎ¶¨ÖÕµãÑÕÉ«ÓÉdz±äÉîÒ×Óڹ۲죬Ӧ½«¸ßÃÌËá¼ØµÎµ½´ý²âÒºÖУ¬¹ÊbÕýÈ·£»c¡¢ÁòËáÑÇÌúÈÜÒºÏÔËáÐÔ£¬Ó¦¸Ã·ÅÔÚËáʽµÎ¶¨¹ÜÖУ¬Í¬Ê±µÎ¶¨ÖÕµãÑÕÉ«ÓÉÉî±ädzÉî²»Ò×Óڹ۲죬¹Êc´íÎ󣬴ð°¸Ñ¡b¡£
£¨2£©ÓÉMnO4-¡«5Fe2+£¬¿ÉµÃ1000.00mLÈÜÒºº¬ÓеÄFe2+µÄÎïÖʵÄÁ¿n(Fe2+)£½0.01 mol/L¡Á12.00¡Á10-3L¡Á5¡Á£½0.03 mol£¬m(Fe2+)£½0.03 mol¡Á56 g/mol£½1.68 g£¬ËùÒÔFe2+µÄÑõ»¯ÂÊ£½£½16.00%¡£
£¨3£©ÏûºÄÇâÑõ»¯ÄƵÄÎïÖʵÄÁ¿ÊÇ0.4mol£¬µ±çúçêËáΪһԪËáʱ£¬¸ù¾ÝÓë¼î·´Ó¦µÄ¹Øϵ£¬ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª23.6¡Â0.4£½59£¬²»·ûºÏÓлúÎï×é³ÉÔÔò£»µ±çúçêËáΪ¶þÔªËáʱ£¬ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª23.6¡Â0.2£½118£¬ÓÖçúçêËá·Ö×ÓÖÐÓÐÁ½ÖÖλÖò»Í¬µÄÇâÔ×Ó£¬ËùÒÔçúçêËáµÄ½á¹¹¼òʽΪHOOC-CH2-CH2-COOH£¬Òò´ËçúçêËáÈÜÒºÓëÇâÑõ»¯ÄÆÈÜÒºÍêÈ«Öк͵ÄÀë×Ó·½³ÌʽΪHOOC£CH2CH2£COOH£«2NaOH¡úNaOOC£CH2CH2£COONa£«2H2O¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿