ÌâÄ¿ÄÚÈÝ
£¨8·Ö£©
(1) Ìå»ýÏàͬ£¬pHÏàͬµÄÑÎËáºÍ´×ËáÈÜÒº·Ö±ðÓë×ãÁ¿µÄ¿ÅÁ£´óСÏàͬµÄпÁ£·´Ó¦,¿ªÊ¼Ê±²úÉúÇâÆøµÄËÙÂÊ_____________,³ä·Ö·´Ó¦ºó£¬²úÉúÇâÆøµÄÁ¿_____________(Ïàͬ¡¢ÑÎËáµÄ¶à¡¢´×ËáµÄ¶à)
(2) ÔÚÒ»¶¨Á¿µÄÑÎËáÈÜÒºÖмÓÈë×ãÁ¿µÄпÁ£,Èôʹ²úÉúÇâÆøµÄÁ¿±£³Ö²»±ä£¬µ«·´Ó¦ËÙÂʼӿ죬¿É¼ÓÈë__________¾§Ì壬Ҫʹ²úÉúÇâÆøµÄÁ¿²»±ä,µ«·´Ó¦ËÙÂʼõÂý,¿É¼ÓÈë____________¾§Ìå¡£
¿ÉÑ¡ÔñµÄ¾§ÌåÓУº
(A) ´¿¼î (B)ÉÕ¼î (C)µ¨·¯ (D) ´×ËáÄÆ (E) KHSO4
(3)ijÑо¿Ð¡×éÄâÓö¨Á¿µÄ·½·¨²âÁ¿AlºÍFe·Ö±ðÓëËá·´Ó¦µÄ¿ìÂý£¬Éè¼ÆÁËÈçÏÂͼ1ËùʾµÄ×°Öá£
¢Ù ÔÚÐéÏß¿òÄÚÁ¬½ÓºÏÊʵÄ×°ÖÃ___________________
¢ÚÈôÒª±È½Ï²úÉúÆøÌåµÄ¿ìÂý£¬¿ÉÒÔ²âÁ¿Ïàͬʱ¼ä¶ÎÄÚ²úÉúÆøÌåµÄÌå»ý£¬Ò²¿ÉÒÔ²âÁ¿____________________________________¡£
¢ÛʵÑé²âµÃÂÁË¿²úÉúÆøÌåµÄËÙÂÊ(v)Óëʱ¼ä(t)µÄ¹ØÏµÈçͼ2Ëùʾ£¬Ôòt1¡«t2ʱ¼ä¶ÎÄÚ·´Ó¦ËÙÂÊÖð½¥¼Ó¿ìµÄÖ÷ÒªÔÒòÊÇ__________________________________¡£
£¨8·Ö£©
£¨1£©Ò»Ñù£¬´×Ëá¶à
£¨2£©C£»D
(3)¢ÙB ¢Ú²úÉúÏàͬÌå»ýµÄÆøÌåËùÐèʱ¼ä¡¡¢Û·´Ó¦·ÅÈÈ£¬ÈÜҺζÈÉý¸ß
½âÎö:
| A¡¢ ±íʾÎïÖʵÄÁ¿Ö®±ÈΪ2£º3µÄþºÍÂÁ·Ö±ðÓë¹ýÁ¿Ï¡ÁòËᷴӦʱ£¬²úÉúÆøÌåµÄÌå»ý£¨V£©Óëʱ¼ä£¨t£©µÄ¹ØÏµ | B¡¢ ±íʾ2SO2£¨g£©+O2£¨g£©?2SO3£¨g£©£¨¡÷H£¼0£©µÄƽºâ³£ÊýKÓëѹǿPµÄ¹ØÏµÇÒT1£¼T2 | C¡¢ ±íʾÓÃ0.1mol-L-1NaOHÈÜÒº·Ö±ðµÎ¶¨Å¨¶È¾ùΪ0.1mol?L-1Ìå»ýÏàͬµÄÑÎËáºÍ´×ËᣬÆäÖеÄÐéÏßÊǵζ¨´×ËáµÄÇúÏß | D¡¢ ±íʾÔÚÏàͬÌõ¼þÏÂ1 mol H2£¨g£©Óë1 mol F2£¨g£©·´Ó¦Éú³É2 mol HF£¨g£©Ê±£¬·Å³öµÄÈÈͯΪ270kJ |