ÌâÄ¿ÄÚÈÝ

½«Ò»¶¨Á¿µÄþºÍÍ­×é³ÉµÄ»ìºÏÎï¼ÓÈ뵽ϡÏõËáÖУ¬½ðÊôÍêÈ«Èܽ⣨¼ÙÉè·´Ó¦Öл¹Ô­²úÎïÖ»ÓÐNO£©¡£Ïò·´Ó¦ºóµÄÈÜÒºÖмÓÈë3 mol£¯L NaOHÈÜÒºÖÁ³ÁµíÍêÈ«£¬²âµÃÉú³É³ÁµíµÄÖÊÁ¿±ÈÔ­ºÏ½ðµÄÖÊÁ¿Ôö¼Ó5£®1 g¡£ÏÂÁÐÐðÊö²»ÕýÈ·µÄÊÇ
A£®µ±Éú³ÉµÄ³ÁµíÁ¿´ïµ½×î´óʱ£¬ÏûºÄNaOHÈÜÒºµÄÌå»ýV¡Ý100 mL
B£®µ±½ðÊôÈ«²¿ÈܽâʱÊÕ¼¯µ½NOÆøÌåµÄÌå»ýÒ»¶¨Îª2£®24 L
C£®²Î¼Ó·´Ó¦µÄ½ðÊôµÄ×ÜÖÊÁ¿3£®6 g<m<9£®6 g
D£®µ±½ðÊôÈ«²¿Èܽâʱ£¬²Î¼Ó·´Ó¦µÄÏõËáµÄÎïÖʵÄÁ¿Ò»¶¨ÊÇ0£®4 mol
B

ÊÔÌâ·ÖÎö£ºÓÉÌâÒâ¿ÉÖª£¬Éú³É³ÁµíµÄÖÊÁ¿±ÈÔ­ºÏ½ðµÄÖÊÁ¿Ôö¼Ó5.1g£¬¼´ÎªÔö¼ÓµÄÇâÑõ¸ùÀë×ÓµÄÖÊÁ¿£¬ËùÒÔÇâÑõ¸ùÀë×ÓµÄÎïÖʵÄÁ¿Îª0.3mol£¬Ò²ÊÇ·´Ó¦ÖÐתÒƵç×ÓµÄÎïÖʵÄÁ¿¡£A¡¢³ÁµíÖÐÇâÑõ¸ùÀë×ÓµÄÎïÖʵÄÁ¿Îª0.3mol£¬ÔòÐèÒªÇâÑõ»¯ÄƵÄÌå»ýÊÇ100mL£¬ËùÒÔµ±Éú³ÉµÄ³ÁµíÁ¿´ïµ½×î´óʱ£¬ÏûºÄNaOHÈÜÒºµÄÌå»ýV¡Ý100 mL£¬ÕýÈ·£»B¡¢·´Ó¦ÖÐתÒƵç×ÓµÄÎïÖʵÄÁ¿ÊÇ0.3mol£¬¼´NOµÃÎïÖʵÄÁ¿ÊÇ0.1mol£¬µ«Î´Ö¸Ã÷±ê×¼×´¿ö£¬ËùÒÔÆøÌåµÄÌå»ý²»Ò»¶¨ÊÇ2.24L£¬´íÎó£»C¡¢Èô½ðÊôÈ«²¿ÊÇþ£¬ÔòÆäÖÊÁ¿Îª0.3mol/2¡Á24g/mol=3.6g,Èô½ðÊôÈ«²¿ÊÇÍ­£¬ÔòÆäÖÊÁ¿Îª0.3mol/2¡Á64g/mol=9.6g£¬ËùÒÔ¹ÌÌåµÄÖÊÁ¿½éÓÚ3.6g¡«9.6gÖ®¼ä£¬ÕýÈ·£»D¡¢½ðÊôÈ«²¿Èܽâʱ±»»¹Ô­µÄÏõËáÒ²¼´Éú³ÉµÄNOµÄÎïÖʵÄÁ¿ÊÇ0.1mol£¬Î´±»»¹Ô­µÄÏõËá¼´ÓëÇâÑõ»¯ÄÆ·´Ó¦Éú³ÉÏõËáÄƵÄÎïÖʵÄÁ¿ÊÇ0.3mol£¬ËùÒÔ¹²ÏûºÄÏõËá0.4mol£¬ÕýÈ·£¬´ð°¸Ñ¡B¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
Í­µ¥Öʼ°Æ仯ºÏÎïÊÇÓ¦Óü«Æä¹ã·ºµÄÎïÖÊ¡£
(1)Í­ÊÇÇâºó½ðÊô£¬²»ÄÜÓëÑÎËá·¢ÉúÖû»·´Ó¦£¬µ«½«µ¥ÖÊÍ­ÖÃÓÚŨÇâµâËáÖУ¬»áÓпÉȼÐÔÆøÌå¼°°×É«³ÁµíÉú³É£¬ÓÖÖªÑõ»¯ÐÔ£ºCu2£«>I2£¬ÔòÍ­ÓëÇâµâËá·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________________________________
(2)ÒÑÖªCu2OÄÜÈÜÓÚ´×ËáÈÜÒº»òÑÎËáÖУ¬Í¬Ê±µÃµ½À¶É«ÈÜÒººÍºìÉ«¹ÌÌ壬ÔòCu2OÓëÏ¡ÁòËá·´Ó¦µÄÀë×Ó·½³ÌʽΪ____________________________________£»
Cu2OÓëÏ¡ÏõËá·´Ó¦µÄÀë×Ó·½³ÌʽΪ_____________________________£»
Ö»ÓÃÏ¡ÁòËáÀ´È·¶¨Ä³ºìÉ«¹ÌÌåÊÇ Cu2OÓëCu×é³ÉµÄ»ìºÏÎïµÄ·½·¨£º³ÆÈ¡m g¸ÃºìÉ«¹ÌÌåÖÃÓÚ×ãÁ¿Ï¡ÁòËáÖУ¬³ä·Ö·´Ó¦ºó¹ýÂË£¬È»ºó___________________¡£

(3)Cu2OÊÇÒ»ÖÖ°ëµ¼Ìå²ÄÁÏ£¬»ùÓÚÂÌÉ«»¯Ñ§ÀíÄîÉè¼ÆµÄÖÆÈ¡Cu2OµÄµç½â×°ÖÃÈçͼËùʾ£¬µç½â×Ü·´Ó¦£º2Cu£«H2OCu2O£«H2¡ü£¬ÔòʯīӦÓëµçÔ´µÄ________¼«ÏàÁ¬£¬Í­µç¼«Éϵĵ缫·´Ó¦Ê½Îª________£»µç½â¹ý³ÌÖУ¬Òõ¼«ÇøÖÜΧÈÜÒºpH________(Ìî¡°±ä´ó¡±¡¢¡°±äС¡±»ò¡°²»±ä¡±)¡£
(4)ÏÖÏòCu¡¢Cu2O¡¢CuO×é³ÉµÄ»ìºÏÎïÖмÓÈë1 L 0.6 mol/L HNO3Ç¡ºÃʹ»ìºÏÎïÈܽ⣬ͬʱÊÕ¼¯µ½2 240 mL NO(±ê×¼×´¿ö)¡£Èô½«ÉÏÊö»ìºÏÎïÓÃ×ãÁ¿µÄÇâÆø»¹Ô­£¬ËùµÃ¹ÌÌåµÄÖÊÁ¿Îª________£»Èô»ìºÏÎïÖк¬ÓÐ0.1 mol Cu£¬½«¸Ã»ìºÏÎïÓëÏ¡ÁòËá³ä·Ö·´Ó¦£¬ÖÁÉÙÏûºÄÁòËáµÄÎïÖʵÄÁ¿Îª________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø