题目内容
【题目】已知下列数据:4Al(s)+3O2(g)=2Al2O3(s) △H=-3350kJ·mol-1
2Fe(s)+O2(g)=2FeO(s) △H=-544kJ·mol-1
则2Al(s) +3FeO(s)=Al2O3(s) + 3Fe(s)的△H是( )
A. +1403 kJ·mol-1 B. -859 kJ·mol-1
C. -1718 kJ·mol-1 D. -2806kJ·mol-1
【答案】B
【解析】已知:①2Fe(s)+O2(g)=2FeO(s)△H=-544kJmol-1,②4Al(s)+3O2(g)=2Al2O3(s)△H=-3350kJmol-1,据盖斯定律可得,②× -①×得:2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)△H=(-3350kJmol-1)×-(-544kJmol-1)×=-859kJ/mol,故选B。
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