题目内容

【题目】已知下列数据:4Al(s)3O2(g)2Al2O3(s)   H=-3350kJ·mol1

2Fe(s)O2(g)2FeO(s)    H=-544kJ·mol1

2Al(s) +3FeO(s)Al2O3(s) + 3Fe(s)的△H是(

A. 1403 kJ·mol1 B. 859 kJ·mol1

C. 1718 kJ·mol1 D. 2806kJ·mol1

【答案】B

【解析】已知:①2Fe(s)+O2(g)=2FeO(s)H=-544kJmol-14Al(s)+3O2(g)=2Al2O3(s)H=-3350kJmol-1据盖斯定律可得,②× -×得:2Al(s)+3FeO(s)=Al2O3(s)+3Fe(s)H=(-3350kJmol-1-(-544kJmol-1=-859kJ/mol,故选B

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