ÌâÄ¿ÄÚÈÝ

ÒÑÖªBaCO3¡¢BaSO4ÈܶȻý³£Êý·Ö±ðΪKsp=5.1¡Á10-9 mol2¡¤L-2,Ksp=1.1¡Á10-10 mol2¡¤L-2,ÔòBaSO4¿É×÷±µ²Í,BaCO3²»ÄÜ×÷±µ²ÍµÄÖ÷ÒªÀíÓÉÊÇ(¡¡¡¡)
A£®BaSO4µÄÈܶȻý³£Êý±ÈBaCO3µÄС
B£®SûÓж¾ÐÔ,CÓж¾ÐÔ
C£®BaSO4µÄÃܶȴó
D£®Î¸ËáÄÜÓëC½áºÏ,Éú³ÉCO2ºÍH2O,ʹBaCO3µÄÈܽâƽºâÏòÓÒÒƶ¯,Ba2+Ũ¶ÈÔö´ó,Ôì³ÉÈËÌåBa2+Öж¾
D
BaSO4¿É×÷±µ²ÍÊÇÒòΪÁòËá±µ²»ÈÜÓÚËá¡£¶øBaCO3ÄÜÓëËá·´Ó¦:BaCO3+2H+Ba2++H2O+CO2¡ü,Éú³ÉµÄBa2+½øÈëÈËÌå,»áÔì³ÉÖؽðÊôÑÎÖж¾¡£ËùÒÔDÕýÈ·¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨15·Ö£©Ä¿Ç°£¬È«ÊÀ½çµÄÄøÏû·ÑÁ¿½ö´ÎÓÚÍ­¡¢ÂÁ¡¢Ç¦¡¢Ð¿£¬¾ÓÓÐÉ«½ðÊôµÚÎåλ¡£ÄøÐÐÒµ·¢Õ¹Ô̲Øמ޴óµÄDZÁ¦¡£Äø»¯ºÏÎïÖеÄÈýÑõ»¯¶þÄøÊÇÒ»ÖÖÖØÒªµÄµç×ÓÔª¼þ²ÄÁϺͶþ´Îµç³Ø²ÄÁÏ¡£¹¤ÒµÉÏ¿ÉÀûÓú¬ÄøºÏ½ð·ÏÁÏ£¨³ýÄøÍ⣬»¹º¬ÓÐFe¡¢Cu¡¢Ca¡¢Mg¡¢CµÈÔÓÖÊ£©ÖÆÈ¡²ÝËáÄø£¬È»ºó¸ßÎÂìÑÉÕ²ÝËáÄøÀ´ÖÆÈ¡ÈýÑõ»¯¶þÄø¡£
ÒÑÖª£º¢Ù²ÝËáµÄ¸Æ¡¢Ã¾¡¢ÄøÑξùÄÑÈÜÓÚË®£¬ÇÒÈܽâ¶È£ºNiC2O4> NiC2O4¡¤H2O> NiC2O4¡¤2H2O
¢Ú³£ÎÂÏ£¬Ksp[(Fe(OH))3]=4.0¡Á10-38,lg5=0.7
¸ù¾ÝÏÂÁй¤ÒÕÁ÷³Ìͼ»Ø´ðÎÊÌ⣺

£¨1£©¼Ó6%µÄH2O2ʱ£¬Î¶Ȳ»ÄÜÌ«¸ß£¬ÆäÄ¿µÄÊÇ              ¡£ÈôH2O2ÔÚÒ»¿ªÊ¼ËáÈÜʱ±ãÓëÑÎËáÒ»Æð¼ÓÈ룬»áÔì³ÉËáÈܹýÂ˺óµÄÂËÒºÖÐÔö¼ÓÒ»ÖÖ½ðÊôÀë×Ó£¬ÓÃÀë×Ó·½³Ìʽ±íʾÕâÒ»Çé¿ö                             ¡£
£¨2£©Á÷³ÌÖÐÓÐÒ»²½Êǵ÷pH£¬Ê¹Fe3+ת»¯ÎªFe(OH)3³Áµí£¬³£ÎÂϵ±ÈÜÒºÖÐc (Fe3+)=0.5¡Á10-5mol/Lʱ£¬ÈÜÒºµÄpH=          ¡£
£¨3£©Á÷³ÌÖмÓÈëNH4FµÄÄ¿µÄÊÇ           ¡£
£¨4£©½«×îºóËùµÃµÄ²ÝËáÄø¾§ÌåÔÚ¿ÕÆøÖÐÇ¿Èȵ½400¡æ£¬¿ÉÉú³ÉÈýÑõ»¯¶þÄøºÍÎÞ¶¾ÆøÌ壬д³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ                         ¡£
£¨5£©¹¤ÒµÉÏ»¹¿ÉÓõç½â·¨ÖÆÈ¡ÈýÑõ»¯¶þÄø£¬ÓÃNaOHÈÜÒºµ÷½ÚNiCl2ÈÜÒºµÄpHÖÁ7.5£¬ÔÙ¼ÓÈëÊÊÁ¿Na2SO4½øÐеç½â£¬µç½â²úÉúµÄCl2Æä80%µÄ¿É½«¶þ¼ÛÄøÑõ»¯ÎªÈý¼ÛÄø¡£Ð´³öCl2Ñõ»¯Ni(OH)2Éú³ÉÈýÑõ»¯¶þÄøµÄÀë×Ó·½³Ìʽ                  £»½«amol¶þ¼ÛÄøÈ«²¿×ª»¯ÎªÈý¼ÛÄøʱ£¬Íâµç·ÖÐͨ¹ýµç×ÓµÄÎïÖʵÄÁ¿ÊÇ                     ¡£
£¨6£©½üÄêÀ´ÄøÇâµç³Ø·¢Õ¹ºÜ¿ì£¬Ëü¿ÉÓÉNiO(OH)¸úLaNi5H6(LaNi5H6Öи÷ÔªËØ»¯ºÏ¼Û¾ù¿É¿´×÷ÊÇÁã)×é³É£º6NiO(OH)+LaNi5H6 LaNi5+6Ni(OH)2¡£¸Ãµç³Ø·Åµçʱ£¬¸º¼«·´Ó¦ÊÇ                   ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø