ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿¾ö¶¨ÎïÖÊÐÔÖʵÄÖØÒªÒòËØÊÇÎïÖʽṹ¡£Çë»Ø´ðÏÂÁÐÎÊÌâ¡£
£¨1£©ÂÈßÁ±½ëåÊÇÒ»ÖÖÎ÷¹ÏÅò´ó¼Á(Ö²ÎïÉú³¤µ÷½Ú¼Á)£¬Æä×é³É½á¹¹ºÍÎïÀíÐÔÖʼûÏÂ±í¡£
·Ö×Óʽ | ½á¹¹¼òʽ | Íâ¹Û | ÈÛµã | ÈܽâÐÔ |
C12H10ClN3O | °×É«½á¾§·ÛÄ© | 170~172 ¡æ | Ò×ÈÜÓÚË® |
²éÎÄÏ׿ÉÖª£¬¿ÉÓÃ2-ÂÈ-4-°±ßÁà¤ÓëÒìÇèËá±½õ¥·´Ó¦£¬Éú³ÉÂÈßÁ±½ëå¡£
·´Ó¦¹ý³ÌÖУ¬Ã¿Éú³É1 molÂÈßÁ±½ë壬¶ÏÁÑ____¸ö¦Ò¼ü¡¢¶ÏÁÑ____¸ö¦Ð¼ü¡£
£¨2£©¹ý¶É½ðÊôÀë×ÓÓëË®·Ö×ÓÐγɵÄÅäºÏÎïÊÇ·ñÓÐÑÕÉ«ÓëÆäd¹ìµÀµç×ÓÅŲ¼Óйء£Ò»°ãµØ£¬d0»òd10ÅŲ¼ÎÞÑÕÉ«£¬d1¡«d9ÅŲ¼ÓÐÑÕÉ«¡£ÈçCo(H2O)6]2£«ÏÔ·ÛºìÉ«¡£¾Ý´ËÅжϣºMn(H2O)6]2£«_____(Ìî¡°ÎÞ¡±»ò¡°ÓС±)ÑÕÉ«¡£
£¨3£©ÅðÔªËؾßÓÐȱµç×ÓÐÔ£¬Æ仯ºÏÎïÍùÍù¾ßÓмӺÏÐÔ£¬Òò¶øÅðËᣨH3BO3£©ÔÚË®ÈÜÒºÖÐÄÜÓëË®·´Ó¦Éú³ÉB(OH)4]£¶øÌåÏÖÒ»ÔªÈõËáµÄÐÔÖÊ£¬ÔòB(OH)4]£ÖÐBµÄÔ×ÓÔÓ»¯ÀàÐÍΪ_________£»
£¨4£©MgÊǵÚÈýÖÜÆÚÔªËØ£¬¸ÃÖÜÆÚ²¿·ÖÔªËØ·ú»¯ÎïµÄÈÛµã¼ûÏÂ±í£º
·ú»¯Îï | NaF | MgF2 | SiF4 |
ÈÛµã/K | 1 266 | 1 534 | 183 |
½âÊͱíÖзú»¯ÎïÈÛµã²îÒìµÄÔÒò£º___________________________________¡£
£¨5£©ÎÒ¹ú¿Æѧ¼Ò³É¹¦ºÏ³ÉÁËÊÀ½çÉÏÊ׸öÎ嵪ÒõÀë×ÓÑÎ(N5)6(H3O)3(NH4)4Cl(ÓÃR ´ú±í)¡£¾X-ÉäÏßÑÜÉä²âµÃ»¯ºÏÎïR µÄ¾§Ìå½á¹¹£¬Æä¾Ö²¿½á¹¹ÈçÏÂͼËùʾ¡£
¢Ù×é³É»¯ºÏÎïR µÄÁ½ÖÖÑôÀë×ÓÖЦҼüµÄ¸öÊýÖ®±ÈΪ____________£»ÆäÖÐËĺËÑôÀë×ÓµÄÁ¢Ìå¹¹ÐÍΪ____________£¬ÆäÖÐÐÄÔ×ÓµÄÔÓ»¯¹ìµÀÀàÐÍÊÇ____________¡£
¢Ú·Ö×ÓÖеĴó¦Ð¼ü¿ÉÓ÷ûºÅ±íʾ¦Ðmn£¬ÆäÖÐm ´ú±í²ÎÓëÐγɵĴó¦Ð¼üÔ×ÓÊý£¬n ´ú±í²ÎÓëÐγɵĴó¦Ð¼üµç×ÓÊý£¬Èç±½·ÖÁËÖеĴó¦Ð¼ü¿É±íʾΪ¦Ð66¡£ÔòN5£ÖеĴó¦Ð¼üÓ¦±íʾΪ____________¡£
¢ÛÇë±íʾ³öÉÏͼÖеÄÇâ¼ü:________________________¡£
¡¾´ð°¸¡¿ NA NA ÓÐ sp3 NaFÓëMgF2ΪÀë×Ó¾§Ì壬SiF4Ϊ·Ö×Ó¾§Ì壬ËùÒÔNaFÓëMgF2Ô¶±ÈSiF4ÈÛµãÒª¸ß¡£ÒòΪMg2+µÄ°ë¾¶Ð¡ÓÚNa+µÄ°ë¾¶£¬ÇÒËù´øµçºÉÊý¶à£¬ËùÒÔMgF2µÄ¾§¸ñÄÜ´óÓÚNaFµÄ¾§¸ñÄÜ£¬¹ÊMgF2µÄÈÛµã´óÓÚNaF 3:4(»ò4:3) Èý½Ç׶ÐÎ sp3 ¦Ð56 N-H¡¤¡¤¡¤N¡¢ O-H¡¤¡¤¡¤N¡¢ N-H¡¤¡¤¡¤Cl
¡¾½âÎö¡¿(1).ÒìÇèËá±½õ¥¶ÏÁѵÄN=CÖк¬1¸ö¦Ð¼ü£¬2-ÂÈ-4-°±ßÁशÏÁѵÄÊÇ1¸ö¦Ò¼ü£»(2).¸ù¾ÝÌâÖÐÐÅÏ¢ºÍMn(H2O)6]2£«ÖÐMnÔ×ÓdÄܼ¶µç×ÓÊýÅжÏÀë×ÓÊÇ·ñÓÐÑÕÉ«£»(3). ¸ù¾Ý¼Û²ãµç×Ó¶Ô»¥³âÀíÂÛÈ·¶¨ÆäÔÓ»¯·½Ê½£»(4).·ú»¯ÎïµÄÈÛµã¸ßµÍÓ뾧ÌåÀàÐÍÓйأ¬Àë×Ó¾§ÌåµÄÈÛµã½Ï¸ß£¬·Ö×Ó¾§ÌåµÄÈÛµã½ÏµÍ£»(5). ¢Ù.ÑôÀë×ÓΪH3O£«ºÍNH4£«£¬H3O£«Öк¬ÓÐ3¸ö¦Ò¼ü£¬NH4£«Öк¬ÓÐ4¸ö¦Ò¼ü£»¢Ú. N5£Öл¯Ñ§¼ü×ÜÊýΪ5¸ö£¬ÓÉ6¸öµç×ÓÐγɴó¦Ð¼ü£»¢Û. ¾Ýͼ¿ÉÖªÇâ¼ü¿É±íʾΪN-H¡¤¡¤¡¤N¡¢O-H¡¤¡¤¡¤N¡¢N-H¡¤¡¤¡¤Cl¡£
(1).ÔÚ·´Ó¦¹ý³ÌÖУ¬ÒìÇèËá±½õ¥¶ÏÁѵÄN=CÖк¬1¸ö¦Ð¼ü£¬2-ÂÈ-4-°±ßÁशÏÁѵÄÊÇ1¸ö¦Ò¼ü£¬ÔòÿÉú³É1 molÂÈßÁ±½ë壬¶ÏÁÑNA¸ö¦Ò¼üºÍNA¸ö¦Ð¼ü£¬¹Ê´ð°¸Îª£ºNA£»NA£»
(2). ¹ý¶É½ðÊôÀë×ÓÓëË®·Ö×ÓÐγɵÄÅäºÏÎïÊÇ·ñÓÐÑÕÉ«ÓëÆäd¹ìµÀµç×ÓÅŲ¼Óйأ¬Ò»°ãµØ£¬d0»òd10ÅŲ¼ÎÞÑÕÉ«£¬d1¡«d9ÅŲ¼ÓÐÑÕÉ«£¬Mn(H2O)6]2£«ÖÐMnÔ×ÓdÄܼ¶µç×ÓÊýΪ5£¬ËùÒÔ¸ÃÀë×ÓÓÐÑÕÉ«£¬¹Ê´ð°¸Îª£ºÓУ»
(3). B(OH)4]£ÖÐBµÄ¼Û²ãµç×Ó¶ÔÊýΪ4+=4£¬ËùÒÔBÔ×ÓµÄÔÓ»¯ÀàÐÍΪsp3£¬¹Ê´ð°¸Îª£ºsp3£»
(4). Àë×Ó¾§ÌåµÄÈÛµã½Ï¸ß£¬·Ö×Ó¾§ÌåµÄÈÛµã½ÏµÍ£¬NaFÓëMgF2ΪÀë×Ó¾§Ì壬SiF4Ϊ·Ö×Ó¾§Ì壬ËùÒÔNaFÓëMgF2Ô¶±ÈSiF4ÈÛµãÒª¸ß£¬ÓÖÒòΪMg2+µÄ°ë¾¶Ð¡ÓÚNa+µÄ°ë¾¶£¬ÇÒMg2+µÄµçºÉÊý¶à£¬ËùÒÔMgF2µÄ¾§¸ñÄÜ´óÓÚNaF£¬µ¼ÖÂMaF2µÄÈÛµã´óÓÚNaF£¬¹Ê´ð°¸Îª£ºNaFÓëMgF2ΪÀë×Ó¾§Ì壬SiF4Ϊ·Ö×Ó¾§Ì壬ËùÒÔNaFÓëMgF2Ô¶±ÈSiF4ÈÛµãÒª¸ß¡£ÒòΪMg2+µÄ°ë¾¶Ð¡ÓÚNa+µÄ°ë¾¶£¬ÇÒËù´øµçºÉÊý¶à£¬ËùÒÔMgF2µÄ¾§¸ñÄÜ´óÓÚNaFµÄ¾§¸ñÄÜ£¬¹ÊMgF2µÄÈÛµã´óÓÚNaF£»
(5).¢Ù.¾Ýͼ¿ÉÖª£¬ÑôÀë×ÓΪH3O£«ºÍNH4£«£¬H3O£«Öк¬ÓÐ3¸ö¦Ò¼ü£¬NH4£«Öк¬ÓÐ4¸ö¦Ò¼ü£¬ËùÒÔR µÄÁ½ÖÖÑôÀë×ÓÖЦҼüµÄ¸öÊýÖ®±ÈΪ3:4(»ò4:3)£¬H3O£«µÄÖÐÐÄÔ×ÓÊÇO£¬Æä¼Û²ãµç×Ó¶ÔÊýΪ3+=3+1=4£¬ËùÒÔOÔ×ÓµÄÔÓ»¯ÀàÐÍΪsp3£¬¹Âµç×Ó¶ÔÊýΪ1£¬ÔòÆä¿Õ¼ä¹¹ÐÍΪÈý½Ç׶ÐΣ¬¹Ê´ð°¸Îª£º3:4(»ò4:3)£»Èý½Ç׶ÐΣ»sp3£»
¢Ú.¾Ýͼ¿ÉÖª£¬N5£Öл¯Ñ§¼ü×ÜÊýΪ5¸ö£¬ÓÉ6¸öµç×ÓÐγɴó¦Ð¼ü£¬¿ÉÓ÷ûºÅ¦Ð56±íʾ£¬¹Ê´ð°¸Îª£º¦Ð56£»
¢Û.¾Ýͼ¿ÉÖª£¬ÉÏͼÖеÄÇâ¼ü¿É±íʾΪN-H¡¤¡¤¡¤N¡¢O-H¡¤¡¤¡¤N¡¢N-H¡¤¡¤¡¤Cl£¬¹Ê´ð°¸Îª£ºN-H¡¤¡¤¡¤N¡¢O-H¡¤¡¤¡¤N¡¢N-H¡¤¡¤¡¤Cl¡£

¡¾ÌâÄ¿¡¿ÔÚ80 ¡æʱ£¬½«0.20 molµÄN2O4ÆøÌå³äÈë1 LÒѳé¿ÕµÄ¹Ì¶¨ÈÝ»ýµÄÃܱÕÈÝÆ÷ÖУ¬¸ôÒ»¶Îʱ¼ä¶Ô¸ÃÈÝÆ÷ÄÚµÄÎïÖʽøÐзÖÎö£¬µÃµ½ÈçÏÂÊý¾Ý£º
ʱ¼ä /(s) | 0 | 20 | 40 | 60 | 80 | 100 |
c(N2O4) / mol ¡¤ L£1 | 0.20 | c1 | 0.10 | c2 | c3 | c4 |
c(NO2) / mol ¡¤ L£1 | 0.00 | 0.12 | 0.20 | 0.22 | 0.22 | 0.22 |
¸ù¾Ý±¾ÌâÄÚÈݺͱíÖÐÌṩÊý¾ÝÌî¿Õ(c1¡¢c2¡¢c3¡¢c4±íʾÏàÓ¦µÄŨ¶È)£¬Çë»Ø´ðÏÂÁи÷СÌ⣺
(1)¸Ã·´Ó¦»¯Ñ§·½³Ìʽ_________________________£» ±íÖÐc2____c3(Ìî¡°£¼¡±¡¢¡°£¾¡±»ò¡°£½¡±)
(2)c4£½_______mol ¡¤ L£1£¬ÔÚ0¡«20 sÄÚNO2µÄƽ¾ù·´Ó¦ËÙÂÊΪ______________________