ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿X¡¢Y¡¢ZÊÇÈýÖÖÆø̬ÎïÖÊ£¬ÔÚÒ»¶¨Î¶ÈÏÂÆä±ä»¯·ûºÏÏÂͼ¡£ÏÂÁÐ˵·¨Ò»¶¨ÕýÈ·µÄÊÇ£¨ £©
A.¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪX(g) +3Y(g) 2Z(g) ¡÷H= -£¨E2-E1£©kJ
B.ÈôͼIIIÖмױíʾѹǿ£¬ÒÒ±íʾZµÄº¬Á¿£¬ÔòÆä±ä»¯·ûºÏͼIIIÖÐÇúÏß
C.¸ÃζÈÏ£¬·´Ó¦µÄƽºâ³£ÊýÊýֵԼΪ533£¬ÈôÉý¸ßζȣ¬¸Ã·´Ó¦µÄƽºâ³£Êý¼õС£¬YµÄת»¯ÂʽµµÍ
D.ͼIIÖÐÇúÏßbÊǼÓÈë´ß»¯¼ÁʱµÄÄÜÁ¿±ä»¯ÇúÏߣ¬ÇúÏßaÊÇûÓмÓÈë´ß»¯¼ÁʱµÄÄÜÁ¿±ä»¯ÇúÏß
¡¾´ð°¸¡¿C
¡¾½âÎö¡¿
A. ͼ¢ñÖÐX¡¢YµÄÎïÖʵÄÁ¿Å¨¶ÈÖð½¥¼õС£¬Ó¦ÊÇ·´Ó¦ÎZµÄÎïÖʵÄÁ¿Å¨¶ÈÖð½¥Ôö´ó£¬Ó¦ÊÇÉú³ÉÎŨ¶ÈµÄ±ä»¯±ÈֵΪ£¨0.5-0.3£©£º£¨0.7-0.1£©£º£¨0.4-0£©=1£º3£º2£¬¸ù¾ÝŨ¶ÈµÄ±ä»¯Ö®±ÈµÈÓÚ»¯Ñ§¼ÆÁ¿ÊýÖ®±È¿ÉÖª·´Ó¦·½³ÌʽӦΪX(g) +3Y(g) 2Z(g)£¬ÓÉͼ¢ò¿ÉÖª·´Ó¦ÎïµÄ×ÜÄÜÁ¿´óÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿£¬·´Ó¦·ÅÈÈ£¬·´Ó¦ÈÈΪ¡÷H= -£¨E2-E1£©kJ/mol£¬¸Ã·´Ó¦ÈÈ»¯Ñ§·½³ÌʽΪX(g) +3Y(g) 2Z(g) ¡÷H= -£¨E2-E1£©kJ/mol£¬·´Ó¦Èȵĵ¥Î»ÎªkJ/mol£¬AÏî´íÎó£»
B. ѹǿÔö´ó£¬Æ½ºâÓÒÒÆ£¬ZµÄº¬Á¿Ó¦Ôö´ó£¬BÏî´íÎó£»
C. ¸Ã·´Ó¦·ÅÈÈ£¬Éý¸ßζÈƽºâ×óÒÆ£¬¸Ã·´Ó¦µÄƽºâ³£Êý¼õС£¬YµÄת»¯ÂʽµµÍ£¬CÏîÕýÈ·£»
D. ͼ¢òÒ²¿ÉÄÜΪ¼ÓÈ벻ͬµÄ´ß»¯¼Á£¬bµÄ´ß»¯Ð§¹û½ÏºÃ£¬»òÕßÊÇÇúÏßbÊǼÓÈë´ß»¯¼Á£¬ÇúÏßaÊÇûÓмÓÈë´ß»¯¼ÁʱµÄÄÜÁ¿±ä»¯ÇúÏߣ¬DÏî´íÎó£»
´ð°¸Ñ¡C¡£
¡¾ÌâÄ¿¡¿Óɼ¸ÖÖÀë×Ó»¯ºÏÎï×é³ÉµÄ»ìºÏÎïÖк¬ÓÐÒÔÏÂÀë×ÓÖеÄÈô¸ÉÖÖ£ºK£«¡¢Cl£¡¢NH¡¢Mg2£«¡¢Ba2£«¡¢CO¡¢SO¡£½«¸Ã»ìºÏÎïÈÜÓÚË®ºóµÃ³ÎÇåÈÜÒº£¬ÏÖÈ¡Èý·Ý100 mL¸ÃÈÜÒº·Ö±ð½øÐÐÈçÏÂʵÑé¡£
ʵÑéÐòºÅ | ʵÑéÄÚÈÝ | ʵÑé½á¹û |
1 | ¼ÓÈëAgNO3ÈÜÒº | Óа×É«³ÁµíÉú³É |
2 | ¼ÓÈë×ãÁ¿NaOHÈÜÒº²¢¼ÓÈÈ | ÊÕ¼¯µ½ÆøÌå1.12 L(±ê×¼×´¿öÏÂ) |
3 | ¼ÓÈë×ãÁ¿BaCl2ÈÜÒº£¬¶ÔËùµÃ³Áµí½øÐÐÏ´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿£»ÔÙÏò³ÁµíÖмÓÈë×ãÁ¿Ï¡ÑÎËᣬȻºó¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿ | µÚÒ»´Î³ÆÁ¿¶ÁÊýΪ6.27 g£¬µÚ¶þ´Î³ÆÁ¿¶ÁÊýΪ2.33 g |
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©¸ù¾ÝʵÑé1¶ÔCl£ÊÇ·ñ´æÔÚµÄÅжÏÊÇ________(Ìî¡°Ò»¶¨´æÔÚ¡±¡°Ò»¶¨²»´æÔÚ¡±»ò¡°²»ÄÜÈ·¶¨¡±)£»¸ù¾ÝʵÑé1¡«3ÅжÏÔ»ìºÏÎïÖÐÒ»¶¨²»´æÔÚµÄÀë×ÓÊÇ________¡£
£¨2£©ÊÔÈ·¶¨100 mLÈÜÒºÖÐÒ»¶¨´æÔÚµÄÒõÀë×Ó¼°ÆäÎïÖʵÄÁ¿Å¨¶È(¿É²»ÌîÂú)¡£
ÒõÀë×Ó·ûºÅ | ÎïÖʵÄÁ¿Å¨¶È(mol¡¤L£1) |
_______ | ___________ |
______ | _______________ |
£¨3£©K£«ÊÇ·ñ´æÔÚ£¿________(Ìî¡°´æÔÚ¡±»ò¡°²»´æÔÚ¡±)£¬ÅжϵÄÀíÓÉÊÇ____________________¡£