ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÏòÊ¢ÓÐÁòËáÍ­Ë®ÈÜÒºµÄÊÔ¹ÜÀï¼ÓÈ백ˮ£¬Ê×ÏÈÐγÉÄÑÈÜÎ¼ÌÐø¼Ó°±Ë®£¬ÄÑÈÜÎïÈܽ⣬µÃµ½ÉîÀ¶É«µÄ͸Ã÷ÈÜÒº£»Èô¼ÓÈ뼫ÐÔ½ÏСµÄÈܼÁ(ÈçÒÒ´¼)£¬½«Îö³öÉîÀ¶É«µÄ¾§Ìå¡£

¢ñ.ÔÚ»¯Ñ§ÊµÑéºÍ¿ÆѧÑо¿ÖУ¬Ë®ÊÇÒ»ÖÖ×î³£ÓõÄÈܼÁ¡£Ë®ÊÇÉúÃüÖ®Ô´£¬ËüÓëÎÒÃǵÄÉú»îÃÜÇÐÏà¹Ø¡£

(1)д³öH2O·Ö×ӵĵç×Óʽ£º________¡£

(2)Ë®·Ö×ÓÔÚÌض¨Ìõ¼þÏÂÈÝÒ׵õ½Ò»¸öH£«£¬ÐγÉË®ºÏÇâÀë×Ó(H3O£«)¡£ÏÂÁжÔÉÏÊö¹ý³ÌµÄÃèÊö²»ºÏÀíµÄÊÇ________¡£

A£®ÑõÔ­×ÓµÄÔÓ»¯ÀàÐÍ·¢ÉúÁ˸ıä

B£®Î¢Á£µÄÐÎ×´·¢ÉúÁ˸ıä

C£®Î¢Á£µÄ»¯Ñ§ÐÔÖÊ·¢ÉúÁ˸ıä

D£®Î¢Á£Öеļü½Ç·¢ÉúÁ˸ıä

¢ò.µ¨·¯¾§ÌåÊÇÅäÖƲ¨¶û¶àÒºµÄÖ÷ÒªÔ­ÁÏ£¬²¨¶û¶àÒºÊÇÒ»ÖÖ±£»¤ÐÔɱ¾ú¼Á£¬¹ã·ºÓ¦ÓÃÓÚÊ÷ľ¡¢»¨»ÜÉÏ¡£

(3)д³öÍ­Ô­×Ó¼Ûµç×Ó²ãµÄµç×ÓÅŲ¼Ê½£º_____£¬ÓëͭͬһÖÜÆÚ¸±×åÔªËصĻù̬ԭ×ÓÖÐ×îÍâ²ãµç×ÓÊýÓëÍ­Ô­×ÓÏàͬµÄÔªËØÓÐ________(ÌîÔªËØ·ûºÅ)¡£

(4)ʵÑéʱÐγɵÄÉîÀ¶É«ÈÜÒºÖеÄÑôÀë×ÓÄÚ´æÔÚµÄÈ«²¿»¯Ñ§¼üÀàÐÍÓÐ________¡£

(5)ʵÑé¹ý³ÌÖмÓÈëC2H5OHºó¿É¹Û²ìµ½Îö³öÉîÀ¶É«Cu(NH3)4SO4¡¤H2O¾§Ì塣ʵÑéÖÐËù¼ÓC2H5OHµÄ×÷ÓÃÊÇ_________________________ ¡£

¡¾´ð°¸¡¿ A 3d104s1 Cr ¹²¼Û¼ü¡¢Åäλ¼ü ½µµÍCu(NH3)4SO4¡¤H2OµÄÈܽâ¶È

¡¾½âÎö¡¿

¢ñ.£¨1£©Ë®Îª¹²¼Û»¯ºÏÎ

£¨2£©A. ¸ù¾Ý¼Û²ãµç×Ó¶Ô»¥³âÀíÂÛÈ·¶¨ÖÐÐÄÔ­×ÓÔÓ»¯ÀàÐÍ£¬¼Û²ãµç×Ó¶Ô¸öÊý=¼ü¸öÊý+¹Âµç×Ó¶Ô¸öÊý£¬Ë®ÖÐÑõµÄÔÓ»¯·½Ê½Îªsp3£¬H3O£«ÖÐOµÄÔÓ»¯·½Ê½Îªsp3£»

B. ˮΪVÐνṹ£¬H3O£«ÎªÈý½Ç׶ÐΣ»

C. ·Ö×ÓºÍÀë×ӵĻ¯Ñ§ÐÔÖʲ»Í¬£»

D. ¸ù¾Ý΢Á£µÄ¿Õ¼ä¹¹ÐÍÅжϣ»

¢ò.£¨3£©CuµÄÔ­×ÓÐòÊýΪ29£¬ÎªµÚËÄÖÜÆÚµÚIB×åÔªËØ£¬×îÍâ²ãµç×ÓΪ4s1£»

£¨4£©µ¨·¯ÈÜÒºÓë×ãÁ¿°±Ë®ÐγɵÄÉîÀ¶É«ÈÜÒºÖеÄÑôÀë×ÓΪËÄ°±ºÏÍ­ÂçÀë×Ó£»

£¨5£©´Ó½µµÍÎïÖʵÄÈܽâ¶ÈµÄ½Ç¶È½øÐзÖÎö¡£

¢ñ.£¨1£©Ë®Îª¹²¼Û»¯ºÏÎµç×ÓʽΪ£º£»

£¨2£©A. Ë®·Ö×ÓÖÐOÔ­×Ó¼Û²ãµç×Ó¶Ô¸öÊý=2+¡Á(6-2¡Á1)=4£¬²ÉÓÃsp3ÔÓ»¯£¬H3O£«ÖÐOÔ­×Ó¼Û²ãµç×Ó¶Ô¸öÊý=3+¡Á(6-1-3¡Á1)=4£¬²ÉÓÃsp3ÔÓ»¯£¬ÑõÔ­×ÓµÄÔÓ»¯ÀàÐÍûÓиı䣬AÏî´íÎ󣬷ûºÏÌâÒ⣻

B. Ë®·Ö×ÓÖÐOÔ­×Óº¬ÓÐ2¸ö¹Âµç×Ó¶Ô£¬²ÉÓÃsp3ÔÓ»¯£¬£¬¿Õ¼ä¹¹ÐÍΪVÐνṹ£¬H3O£«ÎªÈý½Ç׶ÐΣ¬Î¢Á£µÄÐÎ×´·¢ÉúÁ˱仯£¬BÏîÕýÈ·£¬²»·ûºÏÌâÒ⣻

C. H2OΪÖÐÐÔ·Ö×Ó£¬H3O£«ÎªËáÐÔµÄÑôÀë×Ó£¬Î¢Á£µÄ»¯Ñ§ÐÔÖÊ·¢ÉúÁ˱仯£¬CÏîÕýÈ·£¬²»·ûºÏÌâÒ⣻

D. Ë®·Ö×ÓΪVÐνṹ£¬H3O£«ÎªÈý½Ç׶ÐΣ¬Î¢Á£Öеļü½Ç·¢ÉúÁ˱仯£¬DÏîÕýÈ·£¬²»·ûºÏÌâÒ⣻

´ð°¸Ñ¡A¡£

¢ò.£¨3£©CuµÄÔ­×ÓÐòÊýΪ29£¬ÎªµÚËÄÖÜÆÚµÚIB×åÔªËØ£¬¼Û²ãµç×ӵĵç×ÓÅŲ¼Îª3d104s1£¬×îÍâ²ãΪ4s1£¬Í¬ÖÜÆڵĸ±×åÔªËØCrµÄ¼Û²ãµç×ÓÅŲ¼Îª3d54s1£»

£¨4£©µ¨·¯ÈÜÒºÓë×ãÁ¿°±Ë®ÐγɵÄÉîÀ¶É«ÈÜÒºÖеÄÑôÀë×ÓΪËÄ°±ºÏÍ­ÂçÀë×Ó£¬N¡¢HÔ­×ÓÖ®¼äÒÔ¹²¼Û¼ü½áºÏ£¬Cu2+Ìṩ¿Õ¹ìµÀ£¬NÔ­×ÓÌṩ¹Â¶Ôµç×Ó£¬ÒÔÅäλ¼ü½áºÏ£»

£¨5£©ÊµÑé¹ý³ÌÖмÓÈëC2H5OHºó£¬½µµÍÁËCu(NH3)4SO4µÄÈܽâ¶È£¬Îö³öÁËCu(NH3)4SO4¡¤H2O¾§Ìå¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿10¡æʱ¼ÓÈÈNaHCO3±¥ºÍÈÜÒº£¬²âµÃ¸ÃÈÜÒºµÄpH·¢ÉúÈçϱ仯

ζÈ(¡æ)

10

20

30

¼ÓÈÈÖó·ÐºóÀäÈ´µ½50¡æ

pH

8.3

8.4

8.5

8.8

(1)¼×ͬѧÈÏΪ£¬¸ÃÈÜÒºµÄpHÖµÉý¸ßµÄÔ­ÒòÊÇHCO3£­µÄË®½â³Ì¶ÈÔö´ó£¬¹Ê¼îÐÔÔöÇ¿£¬¸Ã·´Ó¦µÄÀë×Ó·½³ÌʽΪ_________¡£

(2)ÒÒͬѧÈÏΪ£¬ÈÜÒºpHÉý¸ßµÄÔ­ÒòÊÇNaHCO3ÊÜÈȷֽ⣬Éú³ÉÁËNa2CO3£¬²¢ÍƶÏNa2CO3µÄË®½â³Ì¶È_________(Ìî¡°´óÓÚ¡±»ò¡°Ð¡ÓÚ¡±)NaHCO3¡£

(3)±ûͬѧÈÏΪ¼×¡¢ÒÒµÄÅж϶¼²»³ä·Ö¡£±ûÈÏΪ£º

¢ÙÖ»ÒªÔÚ¼ÓÈÈÖó·ÐµÄÈÜÒºÖмÓÈë×ãÁ¿µÄÊÔ¼ÁX£¬Èô²úÉú³Áµí£¬Ôò_________(Ìî¡°¼×¡±»ò¡°ÒÒ¡±)ÅжÏÕýÈ·¡£ÊÔ¼ÁXÊÇ_____________(ÌîÐòºÅ)¡£

a.Ba(OH)2ÈÜÒº b.BaCl2ÈÜÒº c.NaOHÈÜÒº d.³ÎÇåʯ»ÒË®

¢Ú½«¼ÓÈȺóµÄÈÜÒºÀäÈ´µ½10¡æ£¬ÈôÈÜÒºµÄpH____________(Ìî¡°¸ßÓÚ¡±¡¢¡°µÍÓÚ¡±»ò¡°µÈÓÚ¡±)8.3£¬Ôò¼×ÅжÏÕýÈ·¡£

(4)³£ÎÂÏ£¬ÔÚ²âµÃpH¶¼µÈÓÚ9µÄNaOHÈÜÒººÍNa2CO3ÈÜÒºÖУ¬ÓÉË®µçÀë³öµÄOH£­Å¨¶È·Ö±ðΪa mol/LºÍb mol/L¡£Ôòa£ºb£½________¡£

(5)25¡æʱ£¬Å¨¶È¾ùΪ0.1 mol/LµÄNa2CO3ºÍNaHCO3ÈÜÒº¡£

¢ÙÏÂÁÐÅжϲ»ÕýÈ·µÄÊÇ________(ÌîÐòºÅ)¡£

a.Á½ÖÖÈÜÒºµÈÌå»ý»ìºÏºó£º3c(Na£«)£½2[c(HCO3£­)£«c(CO32£­)£«c(H2CO3)]

b.Á½ÖÖÈÜÒºÖдæÔÚµÄÁ£×ÓÖÖÀ಻Ïàͬ

c.Á½ÖÖÈÜÒºÖÐc(H£«)¡¤c(OH£­)£½10£­14

d.Á½ÖÖÈÜÒºÖзֱð¼ÓÈëÉÙÁ¿NaOH¹ÌÌ壬»Ö¸´µ½Ô­Î¶ȣ¬c(CO32£­)¾ùÔö´ó

¢ÚµÈÌå»ý»ìºÏºóÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£º__________£»

¢Û³£ÎÂÏ£¬µÈÌå»ý»ìºÏºóµÄÈÜÒºÖеμÓÏ¡ÑÎËáÖÁÖÐÐÔʱ£¬ÈÜÖʵÄÖ÷Òª³É·ÖÓУº_______¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø