ÌâÄ¿ÄÚÈÝ

´ÖʳÑγ£º¬ÓÐÉÙÁ¿K+¡¢Ca2+¡¢Mg2+¡¢Fe3+¡¢SO42-µÈÔÓÖÊÀë×Ó£¬ÊµÑéÊÒÌá´¿NaClµÄÁ÷³ÌÈçÏ£º

ÌṩµÄÊÔ¼Á£º±¥ºÍNa2CO3ÈÜÒº¡¢ ±¥ºÍK2CO3ÈÜÒº ¡¢NaOHÈÜÒº¡¢ KOHÈÜÒº¡¢  BaCl2ÈÜÒº ¡¢Ba£¨NO3£©2ÈÜÒº
£¨1£©Óû³ýÈ¥ÈÜÒºÖеÄCa2+¡¢Mg2+¡¢Fe3+¡¢SO42-Àë×Ó£¬Ñ¡³öaËù´ú±íµÄ¸÷ÖÖÊÔ¼Á£¬°´µÎ¼Ó˳ÐòÒÀ´ÎΪ            £¨Ìѧʽ£©£»
£¨2£©Õô·¢Å¨ËõÈÜÒº¢òµÃµ½µÄºý×´ÎïµÄ»¯Ñ§³É·Ö×î¶àµÄÊÇ£¨Ìѧʽ£©£»
£¨3£©ÓÃÌá´¿¹ýµÄNaCl¹ÌÌåÀ´ÅäÖÆ480 mL 0£®4 mol¡¤L-1NaClÈÜҺʱ£¬ËùÓÃÒÇÆ÷³ýÉÕ±­¡¢Ò©³×¡¢²£Á§°ô¡¢Ììƽ¡¢½ºÍ·µÎ¹ÜÍ⻹ÓР£¨ÌîÒÇÆ÷Ãû³Æ£©£»ÐèNaCl g¡£
£¨4£©µç½â±¥ºÍʳÑÎË®µÄ×°ÖÃÈçͼËùʾ£º

ÈôÊÕ¼¯µ½µÄH2Ϊ2 L£¬ÔòͬÑùÌõ¼þÏÂÊÕ¼¯µ½µÄCl2Ìå»ý  £¨Ìî¡°>¡±¡¢¡°=¡±»ò¡°<¡±£©2 L£¬ÆäÔ­ÒòÊÇ£º         £¨ÎÄ×ÖÃèÊö£©£»Èô½«´Ë×°ÖõÄb¿ÚÃÜ·âס£¬Ôòµç½âÒ»¶Îʱ¼äºó£¬UÐ͹ÜÖпÉÒÔ»ñµÃÒ»ÖÖÏû¶¾Òº£¬Ð´³ö»ñµÃ´ËÏû¶¾ÒºµÄÒ»¸ö×Ü·´Ó¦·½³Ìʽ£º              ¡£
£¨±¾Ð¡Ìâ12·Ö£©
£¨1£©µÎ¼Ó˳ÐòΪ£º BaCl2 ¡¢NaOH¡¢Na2CO3 £»£¨3·Ö£¬ÆäËûºÏÀí´ð°¸Ò²¿É£©
£¨2£©»¯Ñ§³É·ÖÊÇ  NaCl       £¨Ìѧʽ£©£»£¨1·Ö£©
£¨3£©»¹ÓР  500ºÁÉýÈÝÁ¿Æ¿ £¨2·Ö£¬Î´´ð³öÈÝÁ¿Æ¿²»¸ø·Ö£©11£®7g£¨2·Ö£©
£¨4£©  <  2 L£¬Ô­ÒòÊÇ£º ÂÈÆøÔÚË®ÖÐÓÐÒ»¶¨Á¿µÄÈܽ⠣»£¨¸÷1·Ö£©     ×Ü·´Ó¦·½³Ìʽ£ºNaCl+H2O¡ú NaClO + H2¡ü£¨Ìõ¼þ£ºµç½â£©  ¡££¨2·Ö£©
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨8·Ö£©¹ýÂ˺óµÄʳÑÎË®ÈÔº¬ÓпÉÈÜÐÔµÄCaCl2¡¢MgCl2¡¢Na2SO4µÈÔÓÖÊ£¬Í¨¹ýÈçϼ¸¸öʵÑé²½Ö裬¿ÉÖƵô¿¾»µÄʳÑÎË®£º
¢Ù¼ÓÈëÉÔ¹ýÁ¿µÄNa2CO3ÈÜÒº£» ¢Ú¼ÓÈëÉÔ¹ýÁ¿µÄNaOHÈÜÒº£» 
¢Û¼ÓÈëÉÔ¹ýÁ¿µÄBaCl2ÈÜÒº£» ¢ÜµÎÈëÏ¡ÑÎËáÖÁÈÜÒº³ÊÖÐÐÔ£»   ¢Ý¹ýÂË   
£¨1£©ÏÂÁвÙ×÷˳ÐòÕýÈ·µÄÊÇ                            
A£®¢Û¢Ú¢Ù¢Ý¢ÜB£®¢Ù¢Ú¢Û¢Ý¢ÜC£®¢Ú¢Û¢Ù¢Ý¢ÜD£®¢Û¢Ý¢Ú¢Ù¢Ü
£¨2£©ÈçºÎÓÃʵÑé·½·¨È·¶¨¢ÙÖÐNa2CO3ÈÜÒºÒѹýÁ¿£¿                                      
                                                                     
                                                                         
£¨3£©Èô¢ÜºÍ¢ÝÁ½²½²Ù×÷·´ÁË¿ÉÄÜÔì³Éʲôºó¹û£¿
                                                                                 
                                                                  ¡£
£¨4£©µÎÈëÏ¡ÑÎËáÖÁÈÜÒº³ÊÖÐÐÔÉæ¼°µ½µÄÀë×Ó·´Ó¦·½³Ìʽ
                                                                         

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø