ÌâÄ¿ÄÚÈÝ

ϱíÊÇNa¡¢Mg¡¢Si¡¢S¡¢BrÎåÖÖÔªËصĵ¥Öʵķе㣬ÆäÖÐb¡¢e¾ùÊÇÈȺ͵çµÄÁ¼µ¼Ìå¡£
µ¥ÖÊ
a
b
c
d
e
·Ðµã(¡æ)
58.8
882.9
444.7
2 355
1 107
(1) aµÄÔªËØÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪ________¡£
(2) д³ödµÄÔªËØÔ­×ӵĵç×Óʽ________£»Æä×î¸ß¼ÛÑõ»¯ÎïÐγɵľ§ÌåΪ________¾§Ìå(ÌîÀàÐÍ)£¬ÈÜÓÚÇ¿¼îµÄÀë×Ó·½³ÌʽΪ________________________________________¡£
(3) cÓëÇâÐγɵķÖ×ÓXµÄ¿Õ¼ä¹¹ÐÍΪ________£»Ð´³öXµÄË®ÈÜÒºÓë×ãÁ¿bÔªËصÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯Îï·´Ó¦µÄÀë×Ó·½³Ìʽ___________________________________¡£
(4) ÉÏÊöÔªËØËùÄÜÐγɵļòµ¥Àë×ÓÖа뾶×îСµÄÊÇ________£¨ÌîÀë×Ó·ûºÅ£©£¬×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïËáÐÔ×îÇ¿µÄÊÇ________(Ìî·Ö×Óʽ)£¬eÔªËØÓëNÔªËØÐγɻ¯ºÏÎïµÄµç×ÓʽΪ____________________________¡£
(5) bÔªËØÓëÂÈÔªËØÐγɵĻ¯ºÏÎïYµÄ¾§ÌåÖУ¬1¸ö¾§°ûÄÚº¬ÓеĻù±¾Î¢Á£¼°¸öÊýÊÇ________¡£
£¨11·Ö ³ý×¢Ã÷Íâÿ¿Õ1·Ö£©£¨1£©µÚËÄÖÜÆÚµÚ¢÷A×å
£¨2£©£» Ô­×Ó£» Si+2OH-+H2O£½SiO32-+2H2¡ü
£¨3£©VÐÍ  H2S+2OH-£½S2-+H2O  £¨4£©Mg2+   H2SO4      
£¨5£©4¸öNa+   4¸öCl-£¨2·Ö£©

ÊÔÌâ·ÖÎö£ºÄƺÍþÐγɵľ§ÌåÊǽðÊô¾§Ì壬ÄÆÀë×Ӱ뾶´óÓÚþÀë×ӱȽϣ¬ËùÒÔ½ðÊôþµÄ·Ðµã¸ßÓÚÄƵġ£b¡¢e¾ùÊÇÈȺ͵çµÄÁ¼µ¼Ì壬ËùÒÔbÊÇÄÆ£¬eÊÇþ¡£¹èÊÇÔ­×Ó¾§Ì壬·Ðµã×î¸ß£¬ËùÒÔdÊǹ衣SºÍµ¥ÖÊäåÐγɵľ§Ìå¾ùÊÇ·Ö×Ó¾§Ì壬ÆäÖÐSµ¥Öʵķеã¸ßÓÚµ¥ÖÊäåµÄ£¬ËùÒÔaÊÇä壬cÊÇS¡£
£¨1£©äåλÓÚÔªËØÖÜÆÚ±íµÄµÚËÄÖÜÆÚµÚ¢÷A×å¡£
£¨2£©¹èλÓÚµÚ¶þÕýÈ·µÚ¢ôA×壬Æäµç×ÓʽÊÇ¡£¶þÑõ»¯¹èÐγɵľ§ÌåÊÇÔ­×Ó¾§Ìå¡£µ¥ÖʹèÄܺÍÇâÑõ»¯ÄÆÈÜÒº·´Ó¦£¬·´Ó¦µÄÀë×Ó·½³ÌʽÊÇSi+2OH-+H2O£½SiO32-+2H2¡ü¡£
£¨3£©H2S·Ö×ÓÖÐSÔ­×Óº¬ÓеŶԵç×Ó¶ÔÊý£½£¨6£­2¡Á1£©¡Â2£½2£¬ËùÒÔH2SÊÇVÐνṹ¡£H2SÊǶþÔªÈõËᣬËùÒԺ͹ýÁ¿µÄÇâÑõ»¯ÄÆÈÜÒº·´Ó¦µÄÀë×Ó·½³ÌʽÊÇH2S+2OH-£½S2-+H2O¡£
£¨4£©ÔÚºËÍâµç×ÓÅŲ¼ÏàͬµÄÌõ¼þÏ£¬Î¢Á£°ë¾¶ËæÔ­×ÓÐòÊýµÄÔö´ó¶ø¼õС£¬ËùÒÔÐγɵļòµ¥Àë×ÓÖа뾶×îСµÄÊÇMg2+¡£·Ç½ðÊôÐÔԽǿ£¬×î¸ß¼ÛÑõ»¯ÎïË®»¯ÎïµÄËáÐÔԽǿ£¬ËùÒÔ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïËáÐÔ×îÇ¿µÄH2SO4¡£µªÔªËغÍþÐγɵĻ¯ºÏÎﵪ»¯Ã¾ÊǺ¬ÓÐÀë×Ó¼üµÄÀë×Ó»¯ºÏÎµç×ÓʽÊÇ¡£
£¨5£©¸ù¾ÝÂÈ»¯ÄƵľ§°û½á¹¹¿ÉÖª£¬1¸ö¾§°ûÄÚº¬ÓеĻù±¾Î¢Á£¼°¸öÊýÊÇ4¸öNa+ºÍ4¸öCl-¡£
µãÆÀ£º¸ÃÌâÊǸ߿¼Öеij£¼ûÌâÐÍ£¬ÊôÓÚÖеÈÄѶȵÄÊÔÌâ¡£ÊÔÌâ»ù´¡ÐÔÇ¿£¬²àÖضÔѧÉúÄÜÁ¦µÄÅàÑøºÍ½âÌâ·½·¨µÄÖ¸µ¼ÓëѵÁ·£¬Ö¼ÔÚ¿¼²éѧÉúÁé»îÔËÓûù´¡ÖªÊ¶½â¾öʵ¼ÊÎÊÌâµÄÄÜÁ¦£¬ÓÐÀûÓÚÅàÑøѧÉúµÄÓ¦ÊÔÄÜÁ¦ºÍÂß¼­ÍÆÀíÄÜÁ¦¡£¸ÃÌâÒÔ¡°ÖÜÆÚ±íÖÐÔªËصÄÍƶϡ±ÎªÔØÌ壬±È½ÏÈ«Ã濼²éѧÉúÓйØÔªËØÍƶÏ֪ʶºÍÁé»îÔËÓÃ֪ʶµÄÄÜÁ¦¡£¿¼²éѧÉú¶ÔÔªËØÖÜÆÚ±íµÄÊìϤ³Ì¶È¼°Æä¶Ô±íÖи÷ÔªËØÐÔÖʺÍÏàÓ¦Ô­×ӽṹµÄÖÜÆÚÐԵݱä¹æÂɵÄÈÏʶºÍÕÆÎճ̶ȡ£¿¼²éÁËѧÉú¶ÔÎïÖʽṹÓëÐÔÖʹØϵÒÔ¼°ÔËÓÃÔªËØÖÜÆÚÂɽâ¾ö¾ßÌ廯ѧÎÊÌâµÄÄÜÁ¦¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¢ñ.º¬µª»¯ºÏÎïÎ÷¹ÏÅò´ó¼Á±ðÃûÂÈßÁ±½ë壬ÊǾ­¹ý¹ú¼ÒÅú×¼µÄÖ²ÎïÉú³¤µ÷½Ú¼Á£¬Êµ¼ùÖ¤Ã÷³¤ÆÚʹÓöÔÈËÌåÎÞº¦¡£ÒÑÖªÆäÏà¹ØÐÔÖÊÈçϱíËùʾ£º
·Ö×Óʽ
½á¹¹¼òʽ
Íâ¹Û
ÈÛµã
ÈܽâÐÔ
C12H10ClN3O

°×É«½á¾§·ÛÄ©
170¡«172¡æ
Ò×ÈÜÓÚË®
 
£¨1£©ÂÈßÁ±½ëåµÄ¾§ÌåÀàÐÍΪ_______        £¬Ëùº¬µÚ¶þÖÜÆÚÔªËصÚÒ»µçÀëÄÜ´Ó´óµ½Ð¡µÄ˳ÐòΪ
________________£¨ÓÃÔªËØ·ûºÅ±íʾ£©¡£
£¨2£©ÂÈßÁ±½ëåÈÛµãµÍ£¬Ò×ÈÜÓÚË®µÄÔ­Òò·Ö±ðΪ                      _                        ¡£
£¨3£©²éÎÄÏ׿ÉÖª£¬¿ÉÓÃ2-ÂÈ-4-°±»ùßÁà¤ÓëÒìÇèËá±½õ¥·´Ó¦£¬Éú³ÉÂÈßÁ±½ëå¡£

ÒìÇèËá±½õ¥                2£­ÂÈ£­4£­°±»ùßÁठ            ÂÈßÁ±½ëå
·´Ó¦¹ý³ÌÖУ¬Ã¿Éú³É1molÂÈßÁ±½ë壬¶ÏÁÑ_______¸ö¦Ò¼ü¡¢¶ÏÁÑ_______¸ö¦Ð¼ü¡£
£¨4£©º¬µªµÄ»¯ºÏÎï°±ÆøË®ÈÜÒºÖðµÎ¼ÓÈëÏõËáÒøÈÜÒºÖÐÖƱ¸Òø°±ÈÜÒº£¬Ð´³öÒø°±ÈÜÒºµÄÅäÖƹý³ÌÖгÁµíÈܽâµÄÀë×Ó·½³Ìʽ                            ¡£
¢ò£®ÏÂÁÐÊDz¿·Ö½ðÊôÔªËصĵçÀëÄÜ
 
X
Y
Z
µÚÒ»µçÀëÄÜ(kJ/mol)
520.2
495.8
418.8
 
£¨5£©ÒÑÖªX¡¢Y¡¢ZµÄ¼Û²ãµç×Ó¹¹ÐÍΪns1£¬ÔòÈýÖÖ½ðÊôµÄÂÈ»¯ÎRCl£©µÄÈÛµãÓɵ͵½¸ßµÄ˳ÐòΪ£º
                              ¡£
£¨6£©RCl¿ÉÓÃ×÷ÓлúºÏ³É´ß»¯¼Á, ²¢ÓÃÓÚÑÕÁÏ, ·À¸¯µÈ¹¤Òµ¡£R£«ÖÐËùÓеç×ÓÕýºÃ³äÂúK¡¢L¡¢M Èý¸öµç×Ӳ㣬ËüÓëCl£­Ðγɵľ§Ìå½á¹¹ÈçÏÂͼËùʾ¡£ÔªËØR»ù̬ԭ×ӵĵç×ÓÅŲ¼Ê½              _      £¬
Óëͬһ¸öCl£­ÏàÁ¬µÄ R£«ÓР        ¸ö¡£
ÎÒ¹ú²¿·Ö³ÇÊлÒö²ÌìռȫÄêÒ»°ë£¬ÒýÆð»Òö²µÄPM2.5΢ϸÁ£×Ó°üº¬£¨NH4£©2SO4¡¢NH4NO3£¬Óлú¿ÅÁ£Îï¼°Ñï³¾µÈ¡£Í¨¹ý²â¶¨»Òö²ÖÐпµÈÖؽðÊôµÄº¬Á¿£¬¿É֪ĿǰÔì³ÉÎÒ¹ú»Òö²ÌìÆøÖ÷ÒªÊǽ»Í¨ÎÛȾ¡£
£¨1£©Zn2+ÔÚ»ù̬ʱºËÍâµç×ÓÅŲ¼Ê½Îª____                   _¡£
£¨2£©SO42-µÄ¿Õ¼ä¹¹ÐÍÊÇ___       __(ÓÃÎÄ×ÖÃèÊö)¡£
£¨3£©PM2.5¸»º¬´óÁ¿µÄÓж¾¡¢Óк¦ÎïÖÊ£¬Ò×Òý·¢¶þ´Î¹â»¯Ñ§ÑÌÎíÎÛȾ£¬¹â»¯Ñ§ÑÌÎíÖк¬ÓÐNOX¡¢O3¡¢CH2="CH-CHO," HCOOH, CH3COOONO2(PAN)µÈ¶þ´ÎÎÛȾÎï¡£
¢ÙÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ___       __(²»¶¨ÏîÑ¡Ôñ)¡£
a£®N2O½á¹¹Ê½¿É±íʾΪN=N=O
b£®O3·Ö×Ó³ÊÖ±ÏßÐÎ
c£®CH2=CH-CHO·Ö×ÓÖÐ̼ԭ×Ó¾ù²ÉÓÃsp2ÔÓ»¯
d£®ÏàͬѹǿÏ£¬HCOOH·Ðµã±ÈCH3OCH3¸ß£¬ËµÃ÷Ç°ÕßÊǼ«ÐÔ·Ö×Ó£¬ºóÕßÊǷǼ«ÐÔ·Ö×Ó
¢Ú1mo1PANÖк¬¦Ò¼üÊýĿΪ_____¡£
¢ÛNOÄܱ»FeS04ÈÜÒºÎüÊÕÉú³ÉÅäºÏÎï[(Fe(NO)(H20)5)S04,¸ÃÅäºÏÎïÖÐÐÄÀë×ÓµÄÅäλÊýΪ_____(ÌîÊý×Ö)¡£
£¨4£©²â¶¨´óÆøÖÐPM2.5µÄŨ¶È·½·¨Ö®Ò»ÊǦÂÒ»ÉäÏßÎüÊÕ·¨£¬¦ÂÒ»ÉäÏß·ÅÉäÔ´¿ÉÓÃ85Kr£¬ÒÑÖªKr¾§ÌåµÄ¾§°û½á¹¹ÈçͼËùʾ£¬É辧ÌåÖÐÓëÿ¸öKrÔ­×ÓÏà½ôÁÚµÄKrÔ­×ÓÓÐm¸ö£¬¾§°ûÖк¬KrÔ­×ÓΪn¸ö£¬Ôòm/n=_____(ÌîÊý×Ö)¡£
ÓÐA¡¢B¡¢C¡¢DËÄÖÖÔªËØ¡£ÒÑÖªAÔ­×ÓµÄp¹ìµÀÖÐÓÐ3¸öδ³É¶Ôµç×Ó£¬ÆäÆø̬Ç⻯ÎïÔÚË®ÖеÄÈܽâ¶ÈÔÚͬ×åÔªËØËùÐγɵÄÇ⻯ÎïÖÐ×î´ó¡£B µÄ»ù̬ԭ×ÓÕ¼¾ÝÁ½ÖÖÐÎ×´µÄÔ­×Ó¹ìµÀ£¬ÇÒÁ½ÖÖÐÎ×´¹ìµÀÖеĵç×Ó×ÜÊý¾ùÏàͬ£¬BλÓÚÔªËØÖÜÆÚ±íµÄsÇø¡£CÔªËØÔ­×ÓµÄÍâΧµç×Ó²ãÅŲ¼Ê½Îªnsn¡ª1npn¡ª1¡£ DÔ­×ÓMÄܲãΪȫ³äÂú״̬£¬ÇÒ×îÍâ²ãµç×ÓÖ»ÓÐÒ»¸ö¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ACl3·Ö×ÓÖÐAµÄÔÓ»¯ÀàÐÍΪ        ¡£ACl3·Ö×ӵĿռ乹ÐÍΪ         ¡£
£¨2£©Ä³Í¬Ñ§¸ù¾ÝÉÏÊöÐÅÏ¢£¬ÍƶÏBµÄºËÍâµç×ÓÅŲ¼ÈçÓÒͼËùʾ£¬

¸ÃͬѧËù»­µÄµç×ÓÅŲ¼Í¼Î¥±³ÁË         ¡£
£¨3£©A¡¢B¡¢CÈýÔªËØÔ­×ÓµÚÒ»µçÀëÄÜÓÉ´óµ½Ð¡µÄ˳ÐòΪ               £¨ÓÃÔªËØ·ûºÅ±íʾ£©¡£C60·Ö×ÓÖÐÿ¸öÔ­×ÓÖ»¸úÏàÁÚµÄ3¸öÔ­×ÓÐγɹ²¼Û¼ü£¬ÇÒÿ¸öÔ­×Ó×îÍâ²ã¶¼Âú×ã8µç×ÓÎȶ¨½á¹¹£¬ÔòC60·Ö×ÓÖЦмüµÄÊýĿΪ      ¡£
£¨4£©DµÄ»ù̬ԭ×ÓÓР   ÖÖÄÜÁ¿²»Í¬µÄµç×Ó£»D2+ µÄ¼Ûµç×ÓÅŲ¼Ê½Îª        ¡£ÒÑÖªD¾§ÌåÖÐ΢Á£µÄ¶Ñ»ý·½Ê½ÎªÃæÐÄÁ¢·½¶Ñ»ý£¬¾§ÌåÖÐÒ»¸ö¾§°ûµÄ±ß³¤Îªa cm£¬ÔòD¾§ÌåµÄÃܶÈΪ              £¨Ð´³öº¬aµÄ±í´ïʽ£¬ÓÃNA±íʾ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµ£©¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø