ÌâÄ¿ÄÚÈÝ

ijУͬѧΪ̽¾¿Br2¡¢I2ºÍFe3£«µÄÑõ»¯ÐÔÇ¿Èõ£¬½øÐÐÁËÈçÏÂʵÑé¡£
ʵÑé¢Ù£ºÈ¡ÉÙÁ¿KIÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏȼÓÈëäåË®¡¢Õñµ´£¬ÔÙ¼ÓÈëCCl4£¬Õñµ´ºó¾²Ö㬹۲쵽ϲãÒºÌå³Ê×ϺìÉ«£»
ʵÑé¢Ú£ºÈ¡ÉÙÁ¿FeSO4ÈÜÒºÓÚÊÔ¹ÜÖУ¬ÏȼÓÈëäåË®£¬Õñµ´£¬ÔÙ¼ÌÐøµÎ¼ÓÁ½µÎKSCNÈÜÒº£¬Õñµ´£¬¹Û²ìµ½ÈÜÒº³ÊºìÉ«¡£
(1)д³öÀë×Ó·½³Ìʽ£º
ʵÑé¢Ù£º__________________________________________________________£»
ʵÑé¢Ú£º__________________________________________________________¡£
(2)ÓÉÉÏÊöÁ½¸öʵÑ飬¶ÔÎïÖʵÄÑõ»¯ÐÔ¿ÉÒԵóöµÄÕýÈ·½áÂÛÊÇ________¡£
A£®Br2>I2B£®Fe3£«>Br2
C£®Br2>Fe3£«D£®I£­>Br£­
(3)ÒÑÖªFe3£«µÄÑõ»¯ÐÔÇ¿ÓÚI2£¬ÇëÄã´ÓËù¸øÊÔ¼ÁÖÐÑ¡ÔñËùÐèÊÔ¼Á£¬Éè¼ÆÒ»¸öʵÑé¼ÓÒÔÖ¤Ã÷¡£(Ìáʾ£ºÇëд³öʵÑé²½Öè¡¢ÏÖÏó¼°½áÂÛ)
¢ÙFeCl3ÈÜÒº¡¡¢ÚµâË®¡¡¢ÛKIÈÜÒº¡¡¢ÜÏ¡H2SO4¡¡¢Ýµí·ÛÈÜÒº
__________________________________________________________________
__________________________________________________________________
(1)¢Ù2I£­£«Br2=I2£«2Br£­¡¡¢Ú2Fe2£«£«Br2=2Fe3£«£«2Br£­¡¡(2)AC
(3)È¡ÉÙÁ¿FeCl3ÈÜÒºÓڽྻÊÔ¹ÜÖУ¬ÒÀ´Î¼ÓÈëKIÈÜÒººÍµí·ÛÈÜÒº£¬Õñµ´£¬ÈôÈÜÒº±äÀ¶£¬Ö¤Ã÷Fe3£«µÄÑõ»¯ÐÔÇ¿ÓÚI2¡£
ÓÉʵÑé¢ÚÖªÉú³ÉÁËFe3£«£¬¼´ÌúÔªËØ»¯ºÏ¼ÛÉý¸ß£¬ÄÇôäåÔªËصĻ¯ºÏ¼Û±ØÈ»½µµÍÉú³ÉBr£­£¬·´Ó¦Îª2Fe2£«£«Br2=2Fe3£«£«2Br£­¡£ÓÉʵÑé¢ÙÖªÉú³ÉÁËI2£¬·´Ó¦Îª2I£­£«Br2=I2£«2Br£­¡£ÉÏÊöÁ½·´Ó¦ÖУ¬Br2ÊÇÑõ»¯¼Á£¬Fe3£«ºÍI2ÊÇÑõ»¯²úÎËùÒÔÑõ»¯ÐÔBr2>I2¡¢Br2>Fe3£«¡£Fe3£«µÄÑõ»¯ÐÔÇ¿ÓÚI2£¬¿ÉÒÔ¸ù¾ÝÈçÏ·´Ó¦Éè¼Æ£º2Fe3£«£«2I£­=2Fe2£«£«I2¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
Ïû¶¾¼ÁÔÚÉú²úÉú»îÖÐÓм«ÆäÖØÒªµÄ×÷Ó㬿ª·¢¾ßÓйãÆÕ¡¢¸ßЧ¡¢µÍ¶¾µÄɱ¾ú¼ÁºÍÏû¶¾¼ÁÊǽñºó·¢Õ¹µÄÇ÷ÊÆ¡£
(1)Cl2¡¢H2O2¡¢ClO2(»¹Ô­²úÎïΪCl£­)¡¢O3(1 mol O3ת»¯Îª1 mol O2ºÍ1 mol H2O)µÈÎïÖʳ£±»ÓÃ×÷Ïû¶¾¼Á¡£µÈÎïÖʵÄÁ¿µÄÉÏÊöÎïÖÊÏû¶¾Ð§ÂÊ×î¸ßµÄÊÇ________(ÌîÐòºÅ)¡£
A£®Cl2B£®H2O2C£®ClO2D£®O3
(2)H2O2ÓÐʱ¿É×÷Ϊ¿óÒµ·ÏÒºÏû¶¾¼Á£¬ÓС°ÂÌÉ«Ñõ»¯¼Á¡±µÄÃÀ³Æ¡£ÈçÏû³ý²É¿óÒµ½ºÒºÖеÄÇ軯Îï(ÈçKCN)£¬¾­ÒÔÏ·´Ó¦ÊµÏÖ£ºKCN£«H2O2£«H2O=A£«NH3¡ü£¬ÔòÉú³ÉÎïAµÄ»¯Ñ§Ê½Îª________£¬H2O2±»³ÆΪ¡°ÂÌÉ«Ñõ»¯¼Á¡±µÄÀíÓÉÊÇ____________________________________
(3)Ư°×¼ÁÑÇÂÈËáÄÆ(NaClO2)ÔÚ³£ÎÂÓëºÚ°µ´¦¿É±£´æÒ»Äê¡£ÑÇÂÈËá²»Îȶ¨¿É·Ö½â£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪHClO2¨D¡úClO2¡ü£«H£«£«Cl£­£«H2O(δÅäƽ)¡£Ôڸ÷´Ó¦ÖУ¬µ±ÓÐ1 mol ClO2Éú³ÉʱתÒƵĵç×Ó¸öÊýԼΪ________¡£
(4)¡°84¡±Ïû¶¾Òº(Ö÷Òª³É·ÖÊÇNaClO)ºÍ½à²Þ¼Á(Ö÷Òª³É·ÖÊÇŨÑÎËá)²»ÄÜ»ìÓã¬Ô­ÒòÊÇ__________________(ÓÃÀë×Ó·½³Ìʽ±íʾ)¡£ÀûÓÃÂȼҵµÄ²úÎï¿ÉÒÔÉú²ú¡°84¡±Ïû¶¾Òº£¬Ð´³öÓйط´Ó¦µÄ»¯Ñ§·½³Ìʽ£º____________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø