题目内容
(1)解方程:x2-4x=5
(2)计算:
+(-1)3-2×
.
(2)计算:
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(1)解法一:x2-4x-5=0,
(x-5)(x+1)=0,
x1=5,x=-1.
解法二:x2-4x+4=9,
(x-2)2=9,
x-2=±3,
x1=5,x=-1.
(2)原式=2
-1-
=
-1
(x-5)(x+1)=0,
x1=5,x=-1.
解法二:x2-4x+4=9,
(x-2)2=9,
x-2=±3,
x1=5,x=-1.
(2)原式=2
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