题目内容
计算:
(1)(x3n+1)(x3n-1)-(x3n-1)2;
(2)(2xn+1)2(-2xn+1)2-16(xn+1)2(xn-1)2.
(1)(x3n+1)(x3n-1)-(x3n-1)2;
(2)(2xn+1)2(-2xn+1)2-16(xn+1)2(xn-1)2.
(1)原式=x6n-1-x6n+2x3n-1
=2x3n-2.
(2)原式=[(1+2xn)(1-2xn)]2-16[(xn+1)(xn-1)]2
=(1-4x2n)2-16(x2n-1)2
=1-8x2n+16x4n-16x4n+32x2n-16
=24x2n-15.
=2x3n-2.
(2)原式=[(1+2xn)(1-2xn)]2-16[(xn+1)(xn-1)]2
=(1-4x2n)2-16(x2n-1)2
=1-8x2n+16x4n-16x4n+32x2n-16
=24x2n-15.
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