题目内容
把下列各式分解因式:
(1)a2-2a;
(2)x2-16;
(3)-4a3+16a2-16a;
(4)xy2-x.
答案:
解析:
解析:
|
(1)a(a-2); (2)(x+4)(x-4); (3)-4a(a-2)2; (4)x(y+1)(y-1). |
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题目内容
把下列各式分解因式:
(1)a2-2a;
(2)x2-16;
(3)-4a3+16a2-16a;
(4)xy2-x.
|
(1)a(a-2); (2)(x+4)(x-4); (3)-4a(a-2)2; (4)x(y+1)(y-1). |