题目内容
先化简,再求值:
÷[(x+2)-
],其中x=1.
x-3 |
x-2 |
5 |
x-2 |
原式=
÷
=
•
=
,
当x=1时,原式=
.
x-3 |
x-2 |
x2-9 |
x-2 |
=
x-3 |
x-2 |
x-2 |
(x+3)(x-3) |
=
1 |
x+3 |
当x=1时,原式=
1 |
4 |
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题目内容
x-3 |
x-2 |
5 |
x-2 |
x-3 |
x-2 |
x2-9 |
x-2 |
x-3 |
x-2 |
x-2 |
(x+3)(x-3) |
1 |
x+3 |
1 |
4 |