题目内容
计算:
(1)
÷
;
(2)(
)3•(
)2÷(
)4;
(3)
•
;
(4)
÷
.
(1)
x2-2x+1 |
x2-1 |
x-1 |
x2+x |
(2)(
a2b |
-c |
c2 |
-ab |
bc |
a |
(3)
a+2 |
a-2 |
1 |
a2+2a |
(4)
16-a2 |
a2+8a+16 |
a-4 |
2a+8 |
(1)原式=
•
=x;
(2)原式=
•
•
=-
;
(3)原式=
•
=
;
(4)原式=-
•
=-2.
(x-1)2 |
(x+1)(x-1) |
x(x+1) |
x-1 |
(2)原式=
a6b3 |
-c3 |
c4 |
a2b2 |
a4 |
b4c4 |
a8 |
b3c3 |
(3)原式=
a+2 |
a-2 |
1 |
a(a+2) |
1 |
a(a-2) |
(4)原式=-
(a+4)(a-4) |
(a+4)2 |
2(a+4) |
a-4 |
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