题目内容

已知x2-5x-2014=0,求代数式
(x-2)3-(x-1)2+1
x2-4x+4
÷
2x
2x2-4x
的值.
∵x2-5x-2014=0,
∴x2-5x=2014,
∴原式=
(x-2)3-(x-1)2+1
(x-2)2
×
2x(x-2)
2x
=
(x-2)3-(x-1)2+1
x-2

=(x-2)2-
(x-1)2
x-2
+
1
x-2

=(x-2)2-
(x-1)2-1
x-2

=(x-2)2-
x(x-2)
x-2

=(x-2)2-x
=x2-5x+4
=2014+4
=2018;
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