题目内容
已知x2-5x-2014=0,求代数式
÷
的值.
(x-2)3-(x-1)2+1 |
x2-4x+4 |
2x |
2x2-4x |
∵x2-5x-2014=0,
∴x2-5x=2014,
∴原式=
×
=
=(x-2)2-
+
=(x-2)2-
=(x-2)2-
=(x-2)2-x
=x2-5x+4
=2014+4
=2018;
∴x2-5x=2014,
∴原式=
(x-2)3-(x-1)2+1 |
(x-2)2 |
2x(x-2) |
2x |
(x-2)3-(x-1)2+1 |
x-2 |
=(x-2)2-
(x-1)2 |
x-2 |
1 |
x-2 |
=(x-2)2-
(x-1)2-1 |
x-2 |
=(x-2)2-
x(x-2) |
x-2 |
=(x-2)2-x
=x2-5x+4
=2014+4
=2018;
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