题目内容
先化简,再求值:
-
•(x+1),其中x=
+1.
2 |
x-1 |
1 |
x2-1 |
3 |
原式=
-
=
-
=
,
当x=
+1时,原式=
=
.
2 |
x-1 |
x+1 |
(x+1)(x-1) |
2 |
x-1 |
1 |
x-1 |
1 |
x-1 |
当x=
3 |
1 | ||
|
| ||
3 |
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题目内容
2 |
x-1 |
1 |
x2-1 |
3 |
2 |
x-1 |
x+1 |
(x+1)(x-1) |
2 |
x-1 |
1 |
x-1 |
1 |
x-1 |
3 |
1 | ||
|
| ||
3 |